/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 The following is the number of m... [FREE SOLUTION] | 91Ó°ÊÓ

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The following is the number of minutes to commute from home to work for a group of 25 automobile executives. $$\begin{array}{|lllllllllllll|}\hline 28 & 25 & 48 & 37 & 41 & 19 & 32 & 26 & 16 & 23 & 23 & 29 & 36 \\\31 & 26 & 21 & 32 & 25 & 31 & 43 & 35 & 42 & 38 & 33 & 28 & \\\\\hline\end{array}$$ a. How many classes would you recommend? b. What class interval would you suggest? c. What would you recommend as the lower limit of the first class? d. Organize the data into a frequency distribution. e. Comment on the shape of the frequency distribution.

Short Answer

Expert verified
6 classes are recommended, with a class interval of 6, starting from 16, forming a symmetric distribution.

Step by step solution

01

Calculate the Range

First, identify the smallest and largest values in the dataset. The smallest value is 16 and the largest value is 48. Calculate the range by subtracting the smallest value from the largest value: \[\text{Range} = 48 - 16 = 32\]
02

Determine the Number of Classes

A common method for determining the number of classes is to use Sturges' formula, which is given by: \[k = 1 + 3.322 \log_{10}(N)\]where \(N\) is the number of observations. Substituting \(N = 25\): \[k = 1 + 3.322 \log_{10}(25) \approx 5.64\]Round this value to the nearest whole number, suggesting 6 classes.
03

Calculate the Class Interval

The class interval is found by dividing the range by the number of classes. \[\text{Interval} = \frac{\text{Range}}{\text{Number of Classes}} = \frac{32}{6} \approx 5.33\]Round this to a convenient number, typically either 5 or 6. Here, we choose 6.
04

Select the Lower Limit of the First Class

Choose a starting point that is equal to or less than the smallest observation: 16. Starting at 16 is convenient and includes all observations.
05

Create the Frequency Distribution

Using the starting point of 16 and a class interval of 6, determine class intervals: 16-21, 22-27, 28-33, 34-39, 40-45, and 46-51. Count occurrences in each class: - 16-21: 3 - 22-27: 5 - 28-33: 8 - 34-39: 4 - 40-45: 4 - 46-51: 1
06

Analyze the Shape of Distribution

Describe the shape by visualizing or analyzing the frequency distribution. The distribution's frequencies form a fairly symmetric shape, suggesting a normal distribution without a significant skew.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sturges' Formula
Sturges' formula is a helpful guideline crafted to determine how many classes are needed when creating a frequency distribution. It offers a systematic way to decide on class counts based on the size of your data. The formula itself is: \[k = 1 + 3.322 \log_{10}(N)\], where \(N\) is the total number of observations in your dataset.
In this particular problem, we had 25 data points, and applying the formula, we obtained approximately 5.64 classes. By rounding this number to the nearest whole number, it's suggested to use 6 classes. This simplification ensures that our frequency distribution remains organized and easy to interpret, balancing between too much detail and too little.
It's important to note that Sturges' formula assumes that the data follows a somewhat normal distribution, which makes it particularly well-suited for datasets that are neither too large nor too skewed. It's a quick and efficient tool often used in initial data exploration.
Class Interval
Class interval is the width of each class group when you're dividing your data into different classes. Determining the right class interval makes it easier to understand the data's distribution pattern. To calculate the class interval, you take the range of the data and divide it by the number of classes. In our exercise, the range was calculated by subtracting the smallest data point from the largest, which was 32. With 6 classes determined via Sturges' formula, we calculate the class interval as \( \frac{32}{6} \approx 5.33 \).
For simplicity and practicality, it's often best to round this number to a whole value, because this makes the data more manageable. In this case, rounding to 6 creates convenient and clear class boundaries, like 16-21, 22-27, etc. The fairness in interval rounding supports consistency, solidifying an easy path for further analysis.
Range
The range of a dataset provides a quick snapshot of its spread by showing the distance between the smallest and largest data points. It is one of the simplest measures of dispersion.To find the range, simply subtract the smallest value from the largest value within the dataset. In our executive commute times example, the range was calculated as \(32\) minutes, derived from \(48 - 16\). The range helps determine key pieces of the frequency distribution puzzle, such as class interval and boundaries.
Understanding the range offers a grounding perspective, guiding how detailed your class categories should be. A large range might require broader class intervals, while a smaller range could permit narrower ones. This simple yet powerful metric lays the groundwork for a meaningful exploratory analysis of data distribution.
Normal Distribution
Normal distribution, commonly referenced in statistics, describes a pattern where values cluster symmetrically around a central point, giving rise to the familiar bell-shaped curve. This distribution is highly significant and appears in numerous natural and social phenomena. For the frequency distribution built from the executives' commuting times, the class frequencies suggest that the data might demonstrate normal distribution characteristics. The symmetrically shaped frequency implies that most commuting times occur around the central class intervals, with fewer data points as you move away in either direction.
Normal distribution is vital as it underpins many statistical theories and methods. It simplifies analysis and prediction, using standard deviations and means to provide insights. In our case, acknowledging this distribution type supports the adoption of strategies like Sturges' Formula, aiding in effective and intuitive data organization.

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Most popular questions from this chapter

A social scientist is studying the use of iPods by college students. A sample of 45 students revealed they played the following number of songs yesterday. $$\begin{array}{|lllrllllllllllll|}\hline 4 & 6 & 8 & 7 & 9 & 6 & 3 & 7 & 7 & 6 & 7 & 1 & 4 & 7 & 7 \\\4 & 6 & 4 & 10 & 2 & 4 & 6 & 3 & 4 & 6 & 8 & 4 & 3 & 3 & 6 \\\8 & 8 & 4 & 6 & 4 & 6 & 5 & 5 & 9 & 6 & 8 & 8 & 6 & 5 & 10 \\\\\hline\end{array}$$ Organize the information into a frequency distribution. a. How many classes would you suggest? b. What is the most suitable class interval? c. What is the lower limit of the initial class? d. Create the frequency distribution. e. Describe the shape of the distribution.

One of the most popular candies in the United States is M\&M's, produced by the Mars Company. In the beginning M\&M's were all brown. Now they are produced in red, green, blue, orange, brown, and yellow. Recently, the purchase of a 14 -ounce bag of M\&M's Plain had 444 candies with the following breakdown by color: 130 brown, 98 yellow, 96 red, 35 orange, 52 blue, and 33 green. Develop a chart depicting this information and write a paragraph summarizing the results.

A total of 1,000 residents in Minnesota were asked which season they preferred. One hundred liked winter best, 300 liked spring, 400 liked summer, and 200 liked fall. Develop a frequency table and a relative frequency table to summarize this information.

A large Internet retailer is studying the lead time (elapsed time between when an order is placed and when it is filled) for a sample of recent orders. The lead times are reported in days. $$\begin{array}{|cc|}\hline \text { Lead Time (days) } & \text { Frequency } \\\\\hline 0 \text { up to } 5 & 6 \\\5 \text { up to } 10 & 7 \\\10 \text { up to } 15 & 12 \\\15 \text { up to } 20 & 8 \\\20 \text { up to } 25 & 7 \\\\\text { Total } & \frac{}{40} \\\\\hline\end{array}$$ a. How many orders were studied? b. What is the midpoint of the first class? c. What are the coordinates of the first class for a frequency polygon? d. Draw a histogram. e. Draw a frequency polygon. f. Interpret the lead times using the two charts.

Two thousand frequent business travelers were asked which Midwestern city they prefer: Indianapolis, Saint Louis, Chicago, or Milwaukee. One hundred liked Indianapolis best, 450 liked Saint Louis, 1,300 liked Chicago, and the remainder preferred Milwaukee. Develop a frequency table and a relative frequency table to summarize this information.

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