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A large Internet retailer is studying the lead time (elapsed time between when an order is placed and when it is filled) for a sample of recent orders. The lead times are reported in days. $$\begin{array}{|cc|}\hline \text { Lead Time (days) } & \text { Frequency } \\\\\hline 0 \text { up to } 5 & 6 \\\5 \text { up to } 10 & 7 \\\10 \text { up to } 15 & 12 \\\15 \text { up to } 20 & 8 \\\20 \text { up to } 25 & 7 \\\\\text { Total } & \frac{}{40} \\\\\hline\end{array}$$ a. How many orders were studied? b. What is the midpoint of the first class? c. What are the coordinates of the first class for a frequency polygon? d. Draw a histogram. e. Draw a frequency polygon. f. Interpret the lead times using the two charts.

Short Answer

Expert verified
a. 40 orders. b. Midpoint is 2.5. c. Coordinates: (2.5, 6). d. Draw bars using frequencies. e. Plot and connect midpoints. f. Lead times peak at 10-15 days.

Step by step solution

01

Determine the Total Number of Orders

To find the total number of orders studied, sum the frequencies for each class. These frequencies are 6, 7, 12, 8, and 7. Add them together: \(6 + 7 + 12 + 8 + 7 = 40\).
02

Calculate the Midpoint of the First Class

To calculate the midpoint for the first class (0 to 5 days), add the lower and upper bounds of the interval, then divide by 2: \(\frac{0 + 5}{2} = 2.5\). Thus, the midpoint of the first class is 2.5 days.
03

Find the Coordinates for the Frequency Polygon

For a frequency polygon, the x-coordinate of each point is the midpoint of the class interval, and the y-coordinate is the frequency. For the first class, use the midpoint (2.5) and its frequency (6). The coordinates are \((2.5, 6)\).
04

Draw a Histogram

A histogram represents the frequency of data in each class interval as bars. Each bar's height corresponds to the class interval's frequency. Using the boundaries (0 up to 5, 5 up to 10, etc.) and the frequencies (6, 7, 12, 8, 7), draw bars with corresponding heights for each class.
05

Draw a Frequency Polygon

To draw a frequency polygon, plot the midpoints of each class on the x-axis and their frequencies on the y-axis. Connect these points with straight lines. The midpoints are 2.5, 7.5, 12.5, 17.5, and 22.5. Plot and connect the following points: (2.5, 6), (7.5, 7), (12.5, 12), (17.5, 8), (22.5, 7). Include a point at each end on the baseline to complete the polygon.
06

Interpret the Charts

The histogram and frequency polygon visually display the lead times. Most orders have a lead time in the 10 up to 15 days range, as seen by both the highest bar and peak point. There's a symmetrical distribution around this peak, indicating balanced lead times in the sample. This suggests a central tendency around 10-15 days, with some variability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Histogram
A histogram is a graphical representation that illustrates the frequency of data within specific intervals or "bins". It is particularly helpful for visualizing the distribution of numerical data, such as lead times in days.

In a histogram, adjacent bars represent different intervals (e.g., 0-5 days, 5-10 days), with the height of each bar illustrating the frequency of values within that interval. Unlike a bar graph, a histogram does not have gaps between bars as it deals with continuous data.

When creating a histogram, follow these steps:
  • Choose class intervals that cover the entire range of data without overlapping.
  • Count how many data points fall within each interval to determine the frequency.
  • Draw bars for each interval with heights corresponding to the frequencies.
In the given Internet retailer example, the histogram would show bars at five intervals: 0 to 5 days, 5 to 10 days, 10 to 15 days, 15 to 20 days, and 20 to 25 days, with heights of 6, 7, 12, 8, and 7 respectively.
Frequency Polygon
A frequency polygon is another way to show the distribution of data. It is particularly useful for comparing multiple data sets.

By connecting the midpoints of each class interval with straight lines, we get a polygonal shape that presents an overview of how the frequencies are distributed. This can be more visually intuitive than a histogram in some cases.

To draw a frequency polygon, consider these steps:
  • Find the midpoint for each class interval (e.g., for 0-5 days, the midpoint is 2.5 days).
  • Plot these midpoint values along the x-axis against their corresponding frequencies on the y-axis.
  • Connect these points using straight lines.
  • Ensure to start and end the polygon on the baseline by adding a point at the start of the first interval and the end of the last interval at zero frequency.
In our case, the frequency polygon would connect points like (2.5, 6), (7.5, 7), (12.5, 12), (17.5, 8), and (22.5, 7), illustrating the data's symmetrical distribution.
Midpoint Calculation
Calculating midpoints is crucial in constructing frequency polygons and interpreting data intervals. The midpoint of a class interval provides a central value to represent the entire class.

The midpoint is found using the formula: \[ \text{Midpoint} = \frac{\text{Lower Bound} + \text{Upper Bound}}{2} \] This formula calculates the value lying in the middle of an interval. Midpoints simplify comparisons and provide a visual anchor for frequency polygons.

Let's apply this with an example from the table:
  • For the first interval, "0 up to 5 days", the midpoint calculation is \( \frac{0 + 5}{2} = 2.5 \text{ days} \).
  • Carry out similar calculations for the other intervals like \( \frac{5 + 10}{2} = 7.5\), \( \frac{10 + 15}{2} = 12.5 \), and so forth.
These midpoints (2.5, 7.5, 12.5, 17.5, and 22.5) are essential for plotting frequency polygons and understanding the central trend of data.

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Most popular questions from this chapter

A chain of sport shops catering to beginning skiers, headquartered in Aspen, Colorado, plans to conduct a study of how much a beginning skier spends on his or her initial purchase of equipment and supplies. Based on these figures, it wants to explore the possibility of offering combinations, such as a pair of boots and a pair of skis, to induce customers to buy more. A sample of 44 cash register receipts revealed these initial purchases: $$\begin{array}{rrrrrrrrr}\$ 140 & \$ 82 & \$ 265 & \$ 168 & \$ 90 & \$ 114 & \$ 172 & \$ 230 & \$ 142 \\\86 & 125 & 235 & 212 & 171 & 149 & 156 & 162 & 118 \\\139 & 149 & 132 & 105 & 162 & 126 & 216 & 195 & 127 \\\161 & 135 & 172 & 220 & 229 & 129 & 87 & 128 & 126 \\\175 & 127 & 149 & 126 & 121 & 118 & 172 & 126 & \\\\\hline\end{array}$$ a. Arrive at a suggested class interval. b. Organize the data into a frequency distribution using a lower limit of \(\$ 70\). c. Interpret vour findings.

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The food services division of Cedar River Amusement Park Inc. is studying the amount of money spent per day on food and drink by families who visit the amusement park. A sample of 40 families who visited the park yesterday revealed they spent the following amounts: $$\begin{array}{rrrrrrrrrrrrr}\hline \$ 77 & \$ 18 & \$ 63 & \$ 84 & \$ 38 & \$ 54 & \$ 50 & \$ 59 & \$ 54 & \$ 56 & \$ 36 & \$ 26 & \$ 50 & \$ 34 & \$ 44 \\\41 & 58 & 58 & 53 & 51 & 62 & 43 & 52 & 53 & 63 & 62 & 62 & 65 & 61 & 52 \\\60 & 60 & 45 & 66 & 83 & 71 & 63 & 58 & 61 & 71 & & & & & \\\\\hline\end{array}$$ a. Organize the data into a frequency distribution, using seven classes and 15 as the lower limit of the first class. What class interval did you select? b. Where do the data tend to cluster? c. Describe the distribution. d. Determine the relative frequency distribution.

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