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For a sample of 40 large U.S. cities, the correlation between the mean number of square feet per office worker and the mean monthly rental rate in the central business district is -0.363. At the .05 significance level, can we conclude that there is a negative association between the two variables?

Short Answer

Expert verified
There is a negative association between the two variables.

Step by step solution

01

State the null and alternative hypotheses

The null hypothesis (\(H_0\)) states that there is no correlation between the two variables, i.e., \(\rho = 0\). The alternative hypothesis (\(H_a\)) states that there is a negative correlation between the two variables, i.e., \(\rho < 0\). This implies that we are conducting a left-tailed test.
02

Determine the test statistic

The test statistic for testing the significance of a correlation coefficient is given by \( t = \frac{r \sqrt{n-2}}{\sqrt{1-r^2}} \), where \( r = -0.363 \) is the sample correlation coefficient, and \( n = 40 \) is the sample size. Using this formula, the test statistic is calculated as follows:\[t = \frac{-0.363 \times \sqrt{40-2}}{\sqrt{1-(-0.363)^2}} \approx -2.407\]
03

Determine the critical value

Since we are conducting a left-tailed test at the \(0.05\) significance level, we can look up the critical value from a t-distribution table with \( n-2 = 38\) degrees of freedom. The critical value \(t_{0.05, 38} \approx -1.685\).
04

Compare test statistic to critical value

Compare the test statistic to the critical value: \( t \approx -2.407 \) and the critical value is \( -1.685 \) for the \(0.05\) significance level. Since \(-2.407 < -1.685\), we reject the null hypothesis.
05

Conclusion

Since the test statistic falls in the rejection region, we have sufficient evidence to reject the null hypothesis and conclude that there is a negative association between the mean number of square feet per office worker and the mean monthly rental rate in the central business districts of large U.S. cities at the \(0.05\) significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Correlation Coefficient
The correlation coefficient is a statistical measure that describes the degree and direction of the relationship between two variables. It ranges from -1 to 1, where -1 represents a perfect negative linear relationship, 0 indicates no linear relationship, and 1 signifies a perfect positive linear relationship. In this exercise, a correlation coefficient of -0.363 was found between mean square feet per office worker and mean monthly rental rate.
This value suggests a weak negative correlation, implying that as one variable increases, the other tends to decrease, but not in a strong or consistent way.
This coefficient is crucial in testing hypotheses regarding the existence of an association and helps to understand whether observed relationships in the data are likely to be genuine or simply due to random chance.
Null and Alternative Hypotheses
In hypothesis testing, we start by stating two opposite outcomes called the null and alternative hypotheses. The null hypothesis ( \(H_0\)) assumes there is no effect or no relationship between variables, and in this context, it suggests no correlation ( \(\rho = 0\)) exists between the number of square feet and rental rates.
On the other hand, the alternative hypothesis ( \(H_a\)) posits that there is an effect or relationship, specifically a negative correlation in this case ( \(\rho < 0\)).
This setup allows researchers to statistically determine whether the data provides enough evidence to support one hypothesis over the other, using mathematical analyses to draw conclusions based on probability rather than assumptions or intuition.
Significance Level
The significance level, often denoted as alpha ( \(\alpha\)), is the probability of rejecting the null hypothesis when it is true, essentially quantifying the risk of making a Type I error. In this exercise, a significance level of 0.05 is used.
This means that there is a 5% chance of falsely concluding that there is a correlation when, in fact, there is none.
Selecting the right significance level is important because it influences the results of hypothesis testing. A common choice like 0.05 balances the risk of believing false results and the chance of missing actual findings, providing a reasonable threshold for most scientific studies.
Critical Value
The critical value is the point, or threshold, on the distribution curve that the test statistic must exceed to reject the null hypothesis. This value is determined by the chosen significance level and the degrees of freedom within the dataset being analyzed.
In our case, for a left-tailed test and $n-2=38$ degrees of freedom, the critical value was found to be approximately -1.685.
Since the test statistic of -2.407 is more extreme than -1.685, it falls into the rejection region. This means we have sufficient statistical evidence to reject the null hypothesis, supporting the hypothesis of a negative association between the variables.
The interplay between the test statistic and critical value helps to systematically make decisions about the hypotheses, ensuring conclusions are driven by data-derived evidence.

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Most popular questions from this chapter

The table below shows the number of cars (in millions) sold in the United States for various years and the percent of those cars manufactured by GM. $$ \begin{array}{|lcc|ccc|} \hline \text { Year } & \text { Cars Sold (millions) } & \text { Percent GM } & \text { Year } & \text { Cars Sold (millions) } & \text { Percent GM } \\ \hline 1950 & 6.0 & 50.2 & 1985 & 15.4 & 40.1 \\ 1955 & 7.8 & 50.4 & 1990 & 13.5 & 36.0 \\ 1960 & 7.3 & 44.0 & 1995 & 15.5 & 31.7 \\ 1965 & 10.3 & 49.9 & 2000 & 17.4 & 28.6 \\ 1970 & 10.1 & 39.5 & 2005 & 16.9 & 26.9 \\ 1975 & 10.8 & 43.1 & 2010 & 11.6 & 19.1 \\ 1980 & 11.5 & 44.0 & 2015 & 17.5 & 17.6 \\ \hline \end{array} $$ Use a statistical software package to answer the following questions. a. Is the number of cars sold directly or indirectly related to GM's percentage of the market? Draw a scatter diagram to show your conclusion. b. Determine the correlation coefficient between the two variables. Interpret the value. c. Is it reasonable to conclude that there is a negative association between the two variables? Use the .01 significance level. d. How much of the variation in GM's market share is accounted for by the variation in cars sold?

A dog trainer is exploring the relationship between the size of the dog (weight in pounds) and its daily food consumption (measured in standard cups). Below is the result of a sample of 18 observations. $$ \begin{array}{|ccc|ccc|} \hline \text { Dog } & \text { Weight } & \text { Consumption } & \text { Dog } & \text { Weight } & \text { Consumption } \\ \hline 1 & 41 & 3 & 10 & 91 & 5 \\ 2 & 148 & 8 & 11 & 109 & 6 \\ 3 & 79 & 5 & 12 & 207 & 10 \\ 4 & 41 & 4 & 13 & 49 & 3 \\ 5 & 85 & 5 & 14 & 113 & 6 \\ 6 & 111 & 6 & 15 & 84 & 5 \\ 7 & 37 & 3 & 16 & 95 & 5 \\ 8 & 111 & 6 & 17 & 57 & 4 \\ 9 & 41 & 3 & 18 & 168 & 9 \\ \hline \end{array} $$ a. Compute the correlation coefficient. Is it reasonable to conclude that the correlation in the population is greater than zero? Use the .05 significance level. b. Develop the regression equation for cups based on the dog's weight. How much does each additional cup change the estimated weight of the dog? c. Is one of the dogs a big undereater or overeater?

A study of 20 worldwide financial institutions showed the correlation between their assets and pretax profit to be .86. At the .05 significance level, can we conclude that there is positive correlation in the population?

Given the following sample of five observations, develop a scatter diagram, using \(x\) as the independent variable and \(y\) as the dependent variable, and compute the correlation coefficient. Does the relationship between the variables appear to be linear? Try squaring the \(x\) variable and then develop a scatter diagram and determine the correlation coefficient. Summarize your analysis. $$ \begin{array}{|lllrlr|} \hline \boldsymbol{x} & -8 & -16 & 12 & 2 & 18 \\ \boldsymbol{y} & 58 & 247 & 153 & 3 & 341 \\ \hline \end{array} $$

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