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A regional commuter airline selected a random sample of 25 flights and found that the correlation between the number of passengers and the total weight, in pounds, of luggage stored in the luggage compartment is \(0.94 .\) Using the .05 significance level, can we conclude that there is a positive association between the two variables?

Short Answer

Expert verified
Yes, there is a positive association between the variables.

Step by step solution

01

Define Null and Alternative Hypotheses

To test the significance of the correlation, we first set up the null hypothesis (H0) and the alternative hypothesis (H1). The null hypothesis states that there is no correlation between the two variables in the population, i.e., \( \rho = 0 \). The alternative hypothesis, stating there is a positive association, is \( \rho > 0 \).
02

Determine the Test Statistic

We will use the sample correlation coefficient \( r = 0.94 \) to calculate the test statistic, using the formula for the t-distribution: \[ t = \frac{r \sqrt{n-2}}{\sqrt{1-r^2}} \]where \( n = 25 \) is the sample size. Plugging in the values, we get: \[ t = \frac{0.94 \sqrt{25-2}}{\sqrt{1-0.94^2}} \].
03

Compute the Test Statistic

Calculate the test statistic using the values from Step 2: \[ t = \frac{0.94 \times 4.795}{0.345} \approx 12.92 \].
04

Determine the Critical Value

Using the t-distribution table, find the critical value for \( n-2 = 23 \) degrees of freedom at the \( 0.05 \) significance level (one-tailed test). The critical t-value is approximately \( 1.714 \).
05

Compare the Test Statistic with the Critical Value

Compare the calculated test statistic (\( t \approx 12.92 \)) with the critical value (\( 1.714 \)). Since \( 12.92 > 1.714 \), the test statistic falls in the rejection region.
06

Make a Decision

Since the test statistic exceeds the critical value, we reject the null hypothesis. This means there is enough evidence at the \( 0.05 \) significance level to conclude a positive association between the number of passengers and the weight of luggage.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In statistical hypothesis testing, the null hypothesis is a statement that suggests no effect or no relationship between two variables. In the context of correlation hypothesis testing, the null hypothesis, denoted as \( H_0 \), asserts that there is no correlation in the population. In our case, it is represented as \( \rho = 0 \). This means that any observed relationship from the sample data is due to random chance.

It's important to define the null hypothesis clearly because it provides a basis for comparison with the alternative hypothesis. Rejecting or failing to reject the null hypothesis forms the basis of the conclusion in hypothesis testing. The aim is to determine whether the observed sample data provides enough evidence to reject this initial assumption of no effect. Using this principle, researchers can evaluate whether the relationship between variables like the number of passengers and luggage weight is significant or just by chance.
Alternative Hypothesis
The alternative hypothesis represents the opposite claim to the null hypothesis. In correlation testing, the alternative hypothesis, denoted as \( H_1 \), indicates that there is a correlation in the population. This correlation can be positive, negative, or non-zero in general. In our example, the alternative hypothesis is specified as \( \rho > 0 \), suggesting a positive association between the number of passengers and the weight of luggage.

The main goal is to gather sufficient evidence to support the alternative hypothesis and, as a result, reject the null hypothesis. When the test statistic calculated from the sample data shows extreme values compared to the expected values under \( H_0 \), it indicates that the result provides substantial support for \( H_1 \). Thus, in practical applications, supporting the alternative hypothesis helps to establish relationships or effects that have real-world implications, such as optimizing air travel logistics.
Test Statistic
The test statistic is a standardized value that helps determine if the null hypothesis can be rejected. In correlation hypothesis testing, it is derived from the sample correlation coefficient \( r \). The formula used to compute the test statistic \( t \) for correlation is: \[ t = \frac{r \sqrt{n-2}}{\sqrt{1-r^2}} \] where \( n \) is the sample size.

For the given problem, with \( r = 0.94 \) and \( n = 25 \), substituting these values gives: \[ t = \frac{0.94 \times \sqrt{23}}{\sqrt{1-0.94^2}} \approx 12.92 \].

The test statistic essentially measures how far the sample correlation deviates from what the null hypothesis predicts, scaled by the variance. A higher absolute value of the test statistic suggests a stronger deviation from the null hypothesis, indicating that the sample correlation is less likely to have arisen by random chance alone.
Critical Value
The critical value is a threshold that the test statistic must exceed to reject the null hypothesis. It is determined based on the chosen significance level, often set at 0.05, and the degrees of freedom in the dataset, calculated as \( n-2 \) for correlation testing. This is because two parameters are estimated (the slope and the intercept in the associated linear model).

For our example with \( n = 25 \) and a significance level of 0.05 in a one-tailed test, the critical value from the t-distribution table can be found as approximately 1.714.

If the test statistic calculated from the sample is greater than the critical value, like in our case where \( t \approx 12.92 \) is significantly larger than 1.714, it lies in the rejection region. Hence, we conclude that the sample provides sufficient evidence to reject the null hypothesis and accept that a positive correlation exists.

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Most popular questions from this chapter

The production department of Celltronics International wants to explore the relationship between the number of employees who assemble a subassembly and the number produced. As an experiment, two employees were assigned to assemble the subassemblies. They produced 15 during a one-hour period. Then four employees assembled them. They produced 25 during a one-hour period. The complete set of paired observations follows. $$ \begin{array}{|cc|} \hline \begin{array}{c} \text { Number of } \\ \text { Assemblers } \end{array} & \begin{array}{c} \text { One-Hour } \\ \text { Production } \\ \text { (units) } \end{array} \\ \hline 2 & 15 \\ 4 & 25 \\ 1 & 10 \\ 5 & 40 \\ 3 & 30 \\ \hline \end{array} $$ The dependent variable is production; that is, it is assumed that different levels of production result from a different number of employees. a. Draw a scatter diagram. b. Based on the scatter diagram, does there appear to be any relationship between the number of assemblers and production? Explain. c. Compute the correlation coefficient.

Emily Smith decides to buy a fuel-efficient used car. Here are several vehicles she is considering, with the estimated cost to purchase and the age of the vehicle. $$ \begin{array}{|lrr|} \hline \text { Vehicle } & \text { Estimated Cost } & \text { Age } \\ \hline \text { Honda Insight } & \$ 5,555 & 8 \\ \text { Toyota Prius } & \$ 17,888 & 3 \\ \text { Toyota Prius } & \$ 9,963 & 6 \\ \text { Toyota Echo } & \$ 6,793 & 5 \\ \text { Honda Civic Hybrid } & \$ 10,774 & 5 \\ \text { Honda Civic Hybrid } & \$ 16,310 & 2 \\ \text { Chevrolet Cruz } & \$ 2,475 & 8 \\ \text { Mazda3 } & \$ 2,808 & 10 \\ \text { Toyota Corolla } & \$ 7,073 & 9 \\ \text { Acura Integra } & \$ 8,978 & 8 \\ \text { Scion xB } & \$ 11,213 & 2 \\ \text { Scion xA } & \$ 9,463 & 3 \\ \text { Mazda3 } & \$ 15,055 & 2 \\ \text { Mini Cooper } & \$ 20,705 & 2 \\ \hline \end{array} $$ a. Plot these data on a scatter diagram with estimated cost as the dependent variable. b. Find the correlation coefficient. c. A regression analysis was performed and the resulting regression equation is Estimated Cost \(=18358-1534\) Age. Interpret the meaning of the slope. d. Estimate the cost of a five-year-old car. e. Here is a portion of the regression software output. What does it tell you? $$ \begin{array}{lrrrr} \text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\ \text { Constant } & 18358 & 1817 & 10.10 & 0.000 \\ \text { Age } & -1533.6 & 306.3 & -5.01 & 0.000 \end{array} $$ f. Using the 10 significance level, test the significance of the slope. Interpret the result. Is there a significant relationship between the two variables?

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