Chapter 7: Problem 19
According to the Internal Revenue Service, the mean tax refund for the year 2006 was \(\$ 2,290\). Assume the standard deviation is \(\$ 650\) and that the amounts refunded follow a normal probability distribution. a. What percent of the refunds are more than \(\$ 3,000 ?\) b. What percent of the refunds are more than \(\$ 3,000\) but less than \(\$ 3,500 ?\) c. What percent of the refunds are more than \(\$ 2,500\) but less than \(\$ 3,500 ?\)
Short Answer
Step by step solution
Understanding the Normal Distribution
Calculate the Z-score for $3,000
Find Percent of Refunds More Than $3,000
Calculate the Z-scores for $3,000 and $3,500
Find Percent of Refunds Between $3,000 and $3,500
Calculate the Z-score for $2,500
Find Percent of Refunds Between $2,500 and $3,500
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Z-score
- \(X\) is the value to be standardized
- \(\mu\) is the mean of the distribution
- \(\sigma\) is the standard deviation
Standard Deviation
- \(X_i\) represents each data point
- \(\mu\) is the mean of the data
- \(N\) is the number of data points
Cumulative Probability
- Percentages more or less than a certain Z-score by subtracting the cumulative probability from 1 (or 100% for percentages).
- Probabilities between two data points by calculating the difference between their cumulative probabilities.