/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 A sample of 81 observations is t... [FREE SOLUTION] | 91Ó°ÊÓ

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A sample of 81 observations is taken from a normal population. The sample mean is \(40,\) and the sample standard deviation is \(5 .\) Determine the 95 percent confidence interval for the population mean.

Short Answer

Expert verified
The 95% confidence interval for the population mean is (38.90, 41.10).

Step by step solution

01

Understand the Confidence Interval Formula

To find the confidence interval for the population mean, we use the formula: \[ \text{CI} = \bar{x} \pm Z \left( \frac{s}{\sqrt{n}} \right) \] where \( \bar{x} \) is the sample mean, \( s \) is the sample standard deviation, \( n \) is the sample size, and \( Z \) is the Z-score corresponding to the desired confidence level.
02

Identify Given Values

From the problem, we identify: \( \bar{x} = 40 \), \( s = 5 \), and \( n = 81 \). The confidence level is 95%, which corresponds to a Z-score of 1.96 for a normal distribution.
03

Calculate Standard Error

Compute the standard error (SE) using the formula \( SE = \frac{s}{\sqrt{n}} \). Substituting the values, we have: \[ SE = \frac{5}{\sqrt{81}} = \frac{5}{9} \approx 0.56 \]
04

Calculate the Margin of Error

The margin of error (ME) is calculated as \( Z \times SE \). With \( Z = 1.96 \) and \( SE = 0.56 \), the margin of error becomes: \[ ME = 1.96 \times 0.56 \approx 1.10 \]
05

Determine the Confidence Interval

Using the formula for confidence interval, \( CI = \bar{x} \pm ME \). Substituting the values \( \bar{x} = 40 \) and \( ME = 1.10 \), the confidence interval is: \[ CI = 40 \pm 1.10 \] which gives \( CI = (40 - 1.10, 40 + 1.10) = (38.90, 41.10) \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean (\( \bar{x} \)) is a crucial part of statistics. It is simply the average of all the observations you collect in a sample. In this problem, it is given as 40. Here's how you can calculate it in general: sum up all the values in your sample and divide that sum by the total number of observations in the sample. If your data set includes numbers like 38, 40, and 42, you add them up and get 120, then divide by 3 (the number of observations), resulting in a sample mean of 40.

The sample mean is used as an estimate of the population mean—the average you’d get if you could compute data from every member of the entire population. An important assumption here is the normal distribution of the population from which your samples are drawn. Understanding this average helps to make inferences about the population, especially by preparing confidence intervals.
Standard Error
Standard error (SE) is an indicator of how much variability you can expect in the sample mean from sample to sample. The formula to find it is:\[ SE = \frac{s}{\sqrt{n}} \]where:
  • \( s \) is the sample standard deviation
  • \( n \) is the sample size.
In the exercise, the standard deviation \( s = 5 \) and sample size \( n = 81 \) are used to compute:\[ SE = \frac{5}{9} \approx 0.56 \]

This tells you that, on average, repeated samples would have a standard deviation of about 0.56 units away from the mean of 40. Lower SE values mean you have a more precise measure of your sample mean, leading to narrower confidence intervals, which is generally desirable.
Margin of Error
The margin of error (ME) quantifies the range of uncertainty about the sample mean. It determines how wide the confidence interval will be. It’s calculated by multiplying the Z-score by the standard error:\[ ME = Z \times SE \]

In this case, with a Z-score of 1.96 for a 95% confidence level and previously calculated\( SE = 0.56 \), the computation is:\[ ME = 1.96 \times 0.56 \approx 1.10 \]

This results in an error margin of 1.10 on each side of the sample mean. This range helps encapsulate the true population mean with 95% confidence, acknowledging that real-world observations can vary slightly.
Z-score
The Z-score is a statistical measure that describes a value's relationship to the mean of a group of values. It is expressed in terms of standard deviations from the mean. For confidence intervals, the Z-score indicates how many standard deviations a data point is from the mean.

For common confidence levels:
  • 90% confidence level has a Z-score of 1.645
  • 95% confidence level has a Z-score of 1.96
  • 99% confidence level has a Z-score of 2.576.
In the provided exercise, the Z-score is 1.96 for a 95% confidence interval. This means you can be 95% confident that the population mean falls within the calculated range of the sample mean plus and minus the margin of error. Understanding Z-scores is essential because it bridges the gap between raw data and statistical inferences, enabling decisions based on quantifiable statistics.

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Most popular questions from this chapter

There are 20,000 eligible voters in York County, South Carolina. A random sample of 500 York County voters revealed 350 plan to vote to return Louella Miller to the state senate. Construct a 99 percent confidence interval for the proportion of voters in the county who plan to vote for Ms. Miller. From this sample information, can you confirm she will be reelected?

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