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In a particular chi-square goodness-of-fit test there are four categories and 200 observations. Use the .05 significance level. a. How many degrees of freedom are there? b. What is the critical value of chi-square? \(?\) ?

Short Answer

Expert verified
a. 3 degrees of freedom; b. Critical value is 7.815.

Step by step solution

01

Determine Degrees of Freedom

The degrees of freedom in a chi-square goodness-of-fit test is calculated by the formula: \( ext{df} = ext{Number of categories} - 1 \). Given that there are four categories, the degrees of freedom would be \( 4 - 1 = 3 \).
02

Identify the Significance Level

The significance level is given as 0.05. This is used in conjunction with the degrees of freedom to find the critical value from the chi-square distribution table.
03

Look Up the Critical Value

Using the degrees of freedom (df = 3) and the significance level (0.05), we look up the critical value in a chi-square distribution table. The critical value for df = 3 and a significance level of 0.05 is approximately 7.815.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Degrees of Freedom (df) in a chi-square test represent the number of values that can vary freely in the analysis without breaking any constraints. Understanding degrees of freedom helps in determining the shape of the chi-square distribution curve. In the context of a chi-square goodness-of-fit test, degrees of freedom is determined based on the number of categories. The formula is:\[ \text{df} = \text{Number of categories} - 1 \]For instance, if you're dealing with four categories as in the problem, you simply subtract one from the total number of categories, giving you 3 degrees of freedom.
  • It's important because the value of df affects the critical value in the chi-square distribution table.
  • More categories generally lead to greater degrees of freedom, which requires adjustments in interpretation.
Knowing your degrees of freedom is essential for the next steps of the chi-square test, including evaluating the critical value.
Significance Level
The significance level, often denoted by \( \alpha \), is a threshold you set to determine how strictly you want to test your hypothesis. It's a crucial part of hypothesis testing because it helps you manage the risk of incorrectly making a decision.In the example given, the significance level is 0.05. This implies a 5% risk of concluding that there is a significant difference between the observed and expected data when there is none.
  • A common threshold, often used in many statistical tests, including the chi-square test.
  • Indicates the probability of rejecting the null hypothesis even if it were true (Type I error).
Understanding the significance level helps in decision-making within the context of the hypothesis test. If the computed chi-square statistic is greater than the critical value obtained at this significance level, the null hypothesis may be rejected.
Critical Value
The critical value in a chi-square test is a cutoff point based on the significance level and the degrees of freedom. It helps determine whether your test statistic falls in the region where you can reject the null hypothesis. To find the critical value, you will consult a chi-square distribution table using: - The previously calculated degrees of freedom - The established significance level For example, with 3 degrees of freedom and a significance level of 0.05, you will find a critical value of approximately 7.815.
  • If your calculated chi-square statistic exceeds this value, it means your observed data is significantly different from the expected data.
  • It's essential to use the correct critical value to make accurate judgments about your hypothesis.
In the chi-square test, the critical value serves as a benchmark. Whether your test statistic compares to this value tells you whether to accept or reject your hypothesis.

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Most popular questions from this chapter

For many years TV executives used the guideline that 30 percent of the audience were watching each of the prime-time networks, that is \(\mathrm{ABC}, \mathrm{NBC}\) and \(\mathrm{CBS},\) and 10 percent were watching cable stations on a weekday night. A random sample of 500 viewers in the Tampa-St. Petersburg, Florida, area last Monday night showed that 165 homes were tuned in to the ABC affiliate, 140 to the CBS affiliate, 125 to the NBC affiliate, and the remainder were viewing a cable station. At the .05 significance level, can we conclude that the guideline is still reasonable?

The use of cellular phones in automobiles has increased dramatically in the last few years. Of concern to traffic experts, as well as manufacturers of cellular phones, is the effect on accident rates. Is someone who is using a cellular phone more likely to be involved in a traffic accident? What is your conclusion from the following sample information? Use the .05 significance level. $$ \begin{array}{|lcc|} \hline & \begin{array}{c} \text { Had Accident } \\ \text { in the Last Year } \end{array} & \begin{array}{c} \text { Did Not Have an Accident } \\ \text { in the Last Year } \end{array} \\ \hline \text { Cellular phone in use } & 25 & 300 \\ \text { Cellular phone not in use } & 50 & 400 \\ \hline \end{array} $$

A recent survey suggested that 55 percent of all adults favored legislation requiring restaurants to include information on their menus regarding calories, fat, and carbohydrates of the menu items. The same survey indicated that 28 percent of all adult respondents were opposed to such legislation. The remainder of those surveyed was unsure of the need. A sample of 450 young adults revealed 220 favored the proposed legislation, 158 opposed it, and the remaining 72 were unsure. At the . 05 significance level is it reasonable to conclude the position of young adults regarding adding dietary information to restaurant menus is different from the total population?

In the Tidewater Virginia TV market there are three commercial television stations, each with its own evening news program from 6: 00 to 6: 30 P.M. According to a report in this morning's local newspaper, a random sample of 150 viewers last night revealed 53 watched the news on WNAE (channel 5), 64 watched on WRRN (channel 11 ), and 33 on WSPD (channel 13). At the .05 significance level, is there a difference in the proportion of viewers watching the three channels?

The publisher of a sports magazine plans to offer new subscribers one of three gifts: a sweatshirt with the logo of their favorite team, a coffee cup with the logo of their favorite team, or a pair of earrings also with the logo of their favorite team. In a sample of 500 new subscribers, the number selecting each gift is reported below. At the .05 significance level, is there a preference for the gifts or should we conclude that the gifts are equally well liked? $$ \begin{array}{|lc|} \hline \text { Gift } & \text { Frequency } \\ \hline \text { Sweatshirt } & 183 \\ \text { Coffee cup } & 175 \\ \text { Earrings } & 142 \\ \hline \end{array} $$

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