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If \(P(A)=0.3, P(B)=0.2,\) and \(P(A \cap B)=0.1,\) determine the following probabilities: a. \(P\left(A^{\prime}\right)\) b. \(P(A \cup B)\) c. \(P\left(A^{\prime} \cap B\right)\) d. \(P\left(A \cap B^{\prime}\right)\) e. \(P\left[(A \cup B)^{\prime}\right]\) f. \(P\left(A^{\prime} \cup B\right)\)

Short Answer

Expert verified
a. 0.7, b. 0.4, c. 0.1, d. 0.2, e. 0.6, f. 0.8

Step by step solution

01

Calculate P(A')

We need to find the probability of the complement of event A, denoted as \( P(A') \). The probability of the complement is given by the formula \( P(A') = 1 - P(A) \). Using the given \( P(A) = 0.3 \), we have: \[ P(A') = 1 - 0.3 = 0.7 \]
02

Calculate P(A ∪ B)

To find \( P(A \cup B) \), use the formula \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \). Substituting the given probabilities \( P(A) = 0.3 \), \( P(B) = 0.2 \), and \( P(A \cap B) = 0.1 \):\[ P(A \cup B) = 0.3 + 0.2 - 0.1 = 0.4 \]
03

Calculate P(A' ∩ B)

We need to calculate \( P(A' \cap B) \), which is the probability that A does not occur and B does occur. Use the formula: \( P(A' \cap B) = P(B) - P(A \cap B) \). Using \( P(B) = 0.2 \) and \( P(A \cap B) = 0.1 \), we find:\[ P(A' \cap B) = 0.2 - 0.1 = 0.1 \]
04

Calculate P(A ∩ B')

We aim to find \( P(A \cap B') \). Use the formula \( P(A \cap B') = P(A) - P(A \cap B) \). With \( P(A) = 0.3 \) and \( P(A \cap B) = 0.1 \),\[ P(A \cap B') = 0.3 - 0.1 = 0.2 \]
05

Calculate P[(A ∪ B)']

We need to find the complement of \( P(A \cup B) \). The formula is \( P[(A \cup B)'] = 1 - P(A \cup B) \). With \( P(A \cup B) = 0.4 \) (from Step 2), \[ P[(A \cup B)'] = 1 - 0.4 = 0.6 \]
06

Calculate P(A' ∪ B)

To find \( P(A' \cup B) \), use the complement of \( P(A \cap B') \), or follow the formula \( P(A' \cup B) = P(A') + P(B) - P(A' \cap B) \). First, calculate using the complement:\( P(A' \cup B) = 1 - P(A \cap B') = 1 - 0.2 = 0.8 \). Verification with the formula:Substituting \( P(A') = 0.7 \), \( P(B) = 0.2 \), and \( P(A' \cap B) = 0.1 \): \[ P(A' \cup B) = 0.7 + 0.2 - 0.1 = 0.8 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Set Operations in Probability
Understanding set operations in probability theory is crucial for solving probability problems effectively. These operations can simplify the process of calculating the likelihood of complex events. In probability, we use set operations to describe how two or more events relate to one another. Some of the key set operations include:
  • Intersection (\( \cap \)): Represents the probability of both events occurring at the same time.
  • Union (\( \cup \)): Indicates the probability of at least one of the events happening.
  • Complement (\( A' \)): Refers to the probability of the event not occurring.
These operations help to frame problems in a way that makes use of known probabilities and mathematical relationships. This ability to manipulate sets allows us to derive unknown probabilities from those we've already determined. Set operations serve as essential tools in the analysis and modeling of probabilities in various contexts.
Complementary Events
Complementary events are an essential part of probability theory since they represent the opposite outcomes of a given event. If we have an event, say "A," the complement of "A," denoted as \( A' \), includes all outcomes where event "A" does not happen. The total probability of all possible outcomes in a probability model is always 1. Thus, the probability of an event and its complement sum to 1:
\[ P(A') = 1 - P(A) \]
In practical terms, if we know the probability of an event occurring, we can easily find the probability of it not occurring using its complement. For instance, if the probability that event "A" occurs is 0.3, the probability of its complement, \( P(A') \), would be 0.7. Complementary events are particularly useful because they provide a straightforward way to find missing probability values when all other possibilities are known.
Probability of Intersections
The probability of intersections is a measure of the likelihood of two events occurring simultaneously. For any two events "A" and "B," their intersection, \( A \cap B \), represents the outcomes that are common to both events. Calculating the probability of an intersection often makes use of direct probabilities that are already given in a problem.
In formula terms, the probability of the intersection of "A" and "B" is denoted as:
\[ P(A \cap B) \]
This can often be calculated directly from data or experiment. Sometimes, intersecting event outcomes can be derived using additional information provided in probability problems. Knowing how to calculate the intersection is essential, as it helps in finding the probabilities of other related events, such as unions, decoupled with other probabilities.
Probability of Unions
The probability of unions involves finding the likelihood of either one event or another occurring, or both. When two events "A" and "B" are involved, the union \( A \cup B \) represents situations where either event "A," event "B," or both occur.
To calculate the probability of this union, use the formula:
\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]
This formula adjusts for the fact that simply adding probabilities for both events might include overlap twice. Thus, subtracting the intersection probability \( P(A \cap B) \) adjusts for that overlap. This concept also helps in understanding how combined event probabilities work and expands our ability to solve more complicated probability problems. Understanding union probabilities can significantly impact the analysis of real-world scenarios involving multiple factors and conditions.

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