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If \(P(A \mid B)=0.3, P(B)=0.8,\) and \(P(A)=0.3,\) are the events \(B\) and the complement of \(A\) indenendent?

Short Answer

Expert verified
Yes, events \(B\) and \(A^c\) are independent.

Step by step solution

01

Understand the Concept of Independence

Two events, say \(X\) and \(Y\), are independent if the occurrence of one does not change the probability of the other. Mathematically, events \(X\) and \(Y\) are independent if \(P(X \cap Y) = P(X) P(Y)\).
02

Determine the Event of Interest

In this exercise, we are interested in checking the independence between event \(B\) and the complement of event \(A\), denoted as \(A^c\). This means we need to check if \(P(B \cap A^c) = P(B)P(A^c)\).
03

Calculate \(P(A^c)\)

The complement rule states that \(P(A^c) = 1 - P(A)\). So, we calculate: \[ P(A^c) = 1 - P(A) = 1 - 0.3 = 0.7. \]
04

Use Conditional Probability

Given \(P(A \mid B) = 0.3\), we know by definition: \[ P(A \mid B) = \frac{P(A \cap B)}{P(B)}. \] Use this to find \(P(A \cap B)\).
05

Calculate \(P(A \cap B)\)

Substitute the known values into the formula for conditional probability: \[ 0.3 = \frac{P(A \cap B)}{0.8}, \] \[ P(A \cap B) = 0.3 \times 0.8 = 0.24. \]
06

Calculate \(P(B \cap A^c)\)

Knowing \(B = (A \cap B) \cup (A^c \cap B)\) and \(P(B) = 0.8\), we have: \[ P(B \cap A^c) = P(B) - P(A \cap B) = 0.8 - 0.24 = 0.56. \]
07

Verify Independence with Calculated Values

Now, check if \(P(B \cap A^c) = P(B)P(A^c)\): \[P(B)P(A^c) = 0.8 \times 0.7 = 0.56.\] Since \(P(B \cap A^c) = 0.56\), events \(B\) and \(A^c\) are independent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence of Events
Independence in probability means that the occurrence of one event does not change the likelihood of another. Consider two events, say, event \(X\) and event \(Y\). If they are independent, it follows that the probability of both events happening simultaneously is simply the product of their individual probabilities. This can be expressed as:
  • \(P(X \cap Y) = P(X) \cdot P(Y)\)
If this condition is satisfied, the events are considered independent. In situations where events do not meet this criterion, they are dependent, meaning that the occurrence of one event affects the probability of the other.
Understanding independence is crucial as it simplifies the calculation of probabilities in more complex problems. Remember, independence assures that knowing one event has occurred provides no information about whether or not the other event has occurred.
Conditional Probability
Conditional probability is concerned with determining the probability of an event occurring given that another event has already occurred. It is expressed as \(P(A \mid B)\), which reads as "the probability of \(A\) given \(B\)." Mathematically, this is derived from:
  • \(P(A \mid B) = \frac{P(A \cap B)}{P(B)}\)
Here, \(P(A \cap B)\) represents the probability that both events \(A\) and \(B\) occur together, while \(P(B)\) is the probability of the given event \(B\).
Conditional probability is useful when analyzing circumstances where events or outcomes are dependent on each other. It allows us to update or adjust probabilities based on new information or conditions. A classic example is how weather predictions are made more accurate based on current atmospheric conditions.
Complement Rule
The complement rule in probability provides a way to find the probability that an event does not occur. If \(A\) is an event, its complement, denoted as \(A^c\), represents the event "not \(A\)." The probability of the complement of \(A\) is given by:
  • \(P(A^c) = 1 - P(A)\)
This rule is straightforward and exceptionally useful when it's easier to calculate the probability of an event occurring rather than not occurring.
For example, if you know that the probability of it raining tomorrow is \(0.3\), you can directly calculate the probability of it not raining (its complement) as \(0.7\). The complement rule helps in ensuring that the total probability across all possible outcomes remains additive to 1.
Intersection of Events
The intersection of events in probability signifies the probability of both events occurring at the same time. For two events \(A\) and \(B\), the intersection is denoted as \(A \cap B\). The mathematical representation is the joint probability of the two events:
  • \(P(A \cap B)\)
This joint probability can be calculated using the formula for conditional probability as discussed earlier or directly if the events are known to be independent. When dealing with the intersection of events, understanding whether events are independent or dependent is crucial, as it influences how calculations are performed.
In real-world scenarios, looking at intersections allows us to evaluate the likelihood of co-occurring events, such as the chance of getting both a head and a tail in two tosses of a coin.

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Most popular questions from this chapter

Three attempts are made to read data in a magnetic storage device before an error recovery procedure is used. The error recovery procedure attempts three corrections before an "abort" message is sent to the operator. Let \(s\) denote the success of a read operation \(f\) denote the failure of a read operation \(S\) denote the success of an error recovery procedure \(F\) denote the failure of an error recovery procedure \(A\) denote an abort message sent to the operator Describe the sample space of this experiment with a tree diagram.

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