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A random sample of 500 adult residents of Maricopa County indicated that 385 were in favor of increasing the highway speed limit to \(75 \mathrm{mph}\), and another sample of 400 adult residents of Pima County indicated that 267 were in favor of the increased speed limit. a. Do these data indicate that there is a difference in the support for increasing the speed limit for the residents of the two counties? Use \(\alpha=0.05 .\) What is the \(P\) -value for this test? b. Construct a \(95 \%\) confidence interval on the difference in the two proportions. Provide a practical interpretation of this interval.

Short Answer

Expert verified
There is a statistically significant difference in support between the counties. The confidence interval suggests the true difference is between 0.069 and 0.155, which does not include 0.

Step by step solution

01

State the Hypotheses

For part (a), we need to first state the null and alternative hypotheses. The null hypothesis \((H_0)\) is that there is no difference in support for the speed limit increase between the two counties, i.e., \(p_1 = p_2\). The alternative hypothesis \((H_a)\) is that there is a difference, i.e., \(p_1 eq p_2\). Here, \(p_1\) and \(p_2\) are the proportions of residents in favor from Maricopa and Pima counties, respectively.
02

Calculate Sample Proportions

Determine the sample proportions for both counties. For Maricopa County, \(\hat{p}_1 = \frac{385}{500} = 0.77\). For Pima County, \(\hat{p}_2 = \frac{267}{400} = 0.6675\).
03

Formulate the Test Statistic

The test statistic for comparing two proportions is given by \[z = \frac{(\hat{p}_1 - \hat{p}_2)}{\sqrt{\hat{p}(1-\hat{p})(\frac{1}{n_1} + \frac{1}{n_2})}}\]where \(\hat{p} = \frac{x_1 + x_2}{n_1 + n_2}\). Substitute \(x_1 = 385\), \(x_2 = 267\), \(n_1 = 500\), and \(n_2 = 400\) to find \(\hat{p}\) and then calculate \(z\).
04

Calculate the P-Value

Once the \(z\)-value is calculated, use the standard normal distribution to find the corresponding \(P\)-value. A two-tailed test is used, so the \(P\)-value is \(2P(Z > |z|)\). Compare this \(P\)-value to \(\alpha = 0.05\) to make a decision on the null hypothesis.
05

Construct the Confidence Interval

For part (b), the formula for the 95% confidence interval of the difference between two proportions is given by:\[(\hat{p}_1 - \hat{p}_2) \pm z^* \cdot \sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\]where \(z^*\) is the critical value from the standard normal distribution for a 95% confidence level. Compute and interpret the interval.
06

Interpret the Results

Based on the confidence interval, determine if it includes 0. If it does not include 0, it suggests a significant difference in the proportion of residents in favor of the speed limit increase between the two counties. Provide practical implications of this confidence interval in context.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval gives us a range of values that is believed to contain the true difference between two population proportions with a certain level of confidence, commonly 95%. In our exercise, we are looking at two counties, Maricopa and Pima, and trying to determine if there is a significant difference in their support for increasing the highway speed limit. The confidence interval provides a numerical range that captures this difference, considering the sample data gathered.

To calculate the confidence interval for the difference in proportions, we use the formula:
  • \[(\hat{p}_1 - \hat{p}_2) \pm z^* \cdot \sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\]
  • Where \(\hat{p}_1\) and \(\hat{p}_2\) are the sample proportions for Maricopa and Pima.
  • The value of \(z^*\) is the critical value which, for a 95% confidence level, is typically around 1.96.
By calculating this interval, we determine the range in which the true difference in support between the two counties might lie. If the interval contains zero, it means there's no significant difference. If it does not, it suggests that there is indeed a significant difference in opinions between the counties.
Proportions
Proportions are used to represent parts of a whole in a simple and clear way, especially useful for comparison across groups or categories. In our exercise, we are dealing with the proportions of people in favor of increasing the speed limit in two different counties.

The sample proportions are calculated as follows:
  • Maricopa County: \(\hat{p}_1 = \frac{385}{500} = 0.77\)
  • Pima County: \(\hat{p}_2 = \frac{267}{400} = 0.6675\)
These numbers reflect the fraction of the surveyed population in each county that supports the increase in the speed limit. Calculating proportions is key in hypothesis testing as it provides a basis for comparing two populations. By observing these proportions, it becomes possible to quantify similarities or differences in opinions or behaviors.

The differences in the proportions between these two counties will inform decisions on significance in the later steps of statistical analysis.
P-Value
The P-value helps us determine the strength of our results in hypothesis testing. It measures the probability of observing the results if the null hypothesis is true. In simpler terms, it's like a litmus test for our data. A small P-value suggests strong evidence against the null hypothesis.

In our example, after calculating the test statistic \(z\), we use it to find the P-value. Because we are conducting a two-tailed test, we need to consider the probability of finding results as extreme or more so in both directions:
  • Calculate \(P(Z > |z|)\).
  • The P-value is \(2P(Z > |z|)\).
We then compare this P-value to our chosen significance level \(\alpha=0.05\). If the P-value is less than \(0.05\), we reject the null hypothesis, indicating that there's a significant difference between the counties regarding their support. If it's higher, we fail to reject the null hypothesis, suggesting no significant difference.

Understanding P-value is crucial as it guides us in making an informed decision about our hypothesis.
Statistical Significance
Statistical significance is a key concept that tells us if an observed effect in data is real or if it occurred by chance. In hypothesis testing, we determine statistical significance by comparing the P-value calculated from our data to a predefined significance level, usually denoted as \(\alpha\).

In this exercise, we set \(\alpha = 0.05\). If the P-value is below this threshold, we say that our findings are statistically significant, meaning there's a tangible effect or difference worth noting between populations. It implies that the observed differences in the proportions of support for the speed limit increase between Maricopa and Pima Counties are probably not due to random fluctuation.

When results are statistically significant, they provide strong evidence to reject the null hypothesis, suggesting that there is indeed a difference in opinion between the two counties. This kind of conclusion can assist policymakers in making decisions based on data rather than assumptions or guesswork.

Ultimately, statistical significance helps ensure that the conclusions drawn from the analysis are grounded in reliable and valid data, making it one of the cornerstones of scientific research.

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Most popular questions from this chapter

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