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Information on a packet of seeds claims that \(93 \%\) of them will germinate. Of the 200 seeds that I planted, only 180 germinated. (a) Find a \(95 \%\) confidence interval for the true proportion of seeds that germinate based on this sample. (b) Does this seem to provide evidence that the claim is wrong?

Short Answer

Expert verified
(a) 95% CI is (0.8584, 0.9416). (b) The claim is supported; no evidence shows it is wrong.

Step by step solution

01

Identify the Sample Proportion

The sample proportion of seeds that germinated is given by the formula \( \hat{p} = \frac{x}{n} \), where \( x \) is the number of seeds that germinated and \( n \) is the total number of seeds. Here, \( x = 180 \) and \( n = 200 \), so \( \hat{p} = \frac{180}{200} = 0.90 \).
02

Calculate the Standard Error

The standard error of the sample proportion is calculated using the formula \( SE = \sqrt{\frac{\hat{p} (1 - \hat{p})}{n}} \). Plugging in the values, we get \( SE = \sqrt{\frac{0.90 \times 0.10}{200}} \approx 0.0212 \).
03

Determine the Z-score for a 95% Confidence Interval

For a 95% confidence interval, the Z-score is approximately 1.96. This value is standard for most confidence intervals at this level due to the properties of the normal distribution.
04

Calculate the Confidence Interval

The confidence interval is calculated using the formula \( \hat{p} \pm Z \times SE \). This gives us \( 0.90 \pm 1.96 \times 0.0212 \). When calculated, this yields the interval \( (0.8584, 0.9416) \).
05

Compare the Claim to the Confidence Interval

The confidence interval for the true proportion of seeds that germinate is \( (0.8584, 0.9416) \). The claimed proportion of 93%, or 0.93, falls within this confidence interval.
06

Conclusion

Since the claimed proportion lies within the 95% confidence interval, there is not enough statistical evidence to say that the claim is incorrect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion is a key concept in statistics that captures the portion of a sample that possesses a specific characteristic. It serves as an estimate of the population proportion. To find the sample proportion, use the formula:
  • \( \hat{p} = \frac{x}{n} \)
Here, \( x \) represents the number of successes (seeds that germinate), and \( n \) is the total number of trials (seeds planted).
In the example provided, 180 seeds out of 200 germinated. Plug these values into the formula:
  • \( \hat{p} = \frac{180}{200} = 0.90 \)
This means that 90% of the seeds germinated based on your sample. You estimate the same for the population, knowing there is inherent sample variation.
Standard Error
The standard error of the sample proportion measures how much you expect the sample proportion to vary from the true population proportion. It assesses the variability of your estimate due to random sampling.
The standard error is calculated using the formula:
  • \( SE = \sqrt{\frac{\hat{p} (1 - \hat{p})}{n}} \)
This formula considers both the sample proportion and the sample size. In the seed example, you calculate the standard error as:
  • \( SE = \sqrt{\frac{0.90 \times 0.10}{200}} \approx 0.0212 \)
A smaller standard error indicates that your sample proportion is a more precise estimate of the true population proportion. A larger sample size generally leads to a smaller standard error, improving the precision of your confidence interval.
Z-score
The Z-score is crucial when determining confidence intervals because it accounts for the distribution you're working with. For the normal distribution, specific Z-scores correspond to particular confidence levels. At a 95% confidence level, the Z-score is usually 1.96 due to the properties of the normal distribution.
The Z-score tells you how many standard deviations your sample proportion is away from the mean under the standard normal distribution. To adjust the sample proportion into a confidence interval, you multiply the standard error by the Z-score and add it to, and subtract it from, the sample proportion.
  • Example: \( \hat{p} \pm Z \times SE = 0.90 \pm 1.96 \times 0.0212 \)
This calculation provides a range of values, offering an estimate of where the true population proportion likely falls.
Normal Distribution
The normal distribution is a fundamental principle in statistics, often known for its bell-shaped curve. It is essential for understanding how data tends to be distributed around the mean.
When calculating confidence intervals, the normal distribution is used because it allows you to make inferences about the mean and variability of a population from a sample. The Z-score standardizes the sample proportion relative to this distribution, making confidence intervals possible.
In the context of the seed germination problem, assuming a normal distribution allows the use of Z-scores and simplifies complex statistical calculations, helping provide a reliable interval for the true proportion of seeds expected to germinate. Despite not all data being perfectly normal, large sample sizes often make the approximation valid, a principle established by the Central Limit Theorem.

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Most popular questions from this chapter

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