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For a normal population with known variance \(\sigma^{2}\) : (a) What value of \(z_{\alpha / 2}\) in Equation \(8-5\) gives \(98 \%\) confidence? (b) What value of \(z_{\alpha / 2}\) in Equation \(8-5\) gives \(80 \%\) confidence? (c) What value of \(z_{\alpha / 2}\) in Equation \(8-5\) gives \(75 \%\) confidence?

Short Answer

Expert verified
(a) 2.33; (b) 1.28; (c) 1.15.

Step by step solution

01

Understanding the Standard Normal Distribution

To find the value of \(z_{\alpha / 2}\), you'll want to use the standard normal distribution table. The \(z_{\alpha / 2}\) represents the z-value that creates the desired confidence level when using confidence intervals.
02

Finding the z-value for 98% confidence

With a 98% confidence level, the value \(\alpha\) is \(1 - 0.98 = 0.02\). For \(z_{\alpha / 2}\), we find \(z_{0.01}\) because the confidence interval splits \(\alpha\) into two tails. Using the z-table or calculator, \(z_{0.01} \approx 2.33\).
03

Finding the z-value for 80% confidence

With an 80% confidence level, \(\alpha\) is \(1 - 0.8 = 0.2\). We need \(z_{\alpha / 2} = z_{0.1}\). Using the z-table or calculator, \(z_{0.1} \approx 1.28\).
04

Finding the z-value for 75% confidence

For a 75% confidence level, \(\alpha\) is \(1 - 0.75 = 0.25\). We determine \(z_{\alpha / 2}\) by finding \(z_{0.125}\). From the z-table or calculator, \(z_{0.125} \approx 1.15\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The normal distribution is one of the most important probability distributions in statistics. It is often referred to as the bell curve due to its shape. This distribution is symmetric around the mean, meaning that the data near the mean are more frequent in occurrence than data far from the mean. In a normal distribution:
  • The mean, median, and mode are all the same and occur at the peak.
  • The distribution curves downwards as you move away from the center, indicating decreasing frequency.
  • It is defined by two parameters: the mean (\(\mu\)) and the variance (\(\sigma^{2}\)).
This distribution is crucial in statistics because many real-world phenomena approximate a normal distribution when scaled appropriately.
Furthermore, the normal distribution allows us to use the standard normal table (or z-table) to find probabilities and critical values that help us understand the behavior of data.
Z-value
The z-value, also known as a z-score, quantifies the number of standard deviations an element is from the mean of the distribution. It enables the comparison of scores from different distributions. The concept of the z-value is especially useful when determining confidence intervals in statistics.
Within the normal distribution, the area between two points underneath the curve represents probability. The z-value helps find this area by converting any normal distribution to the standard normal distribution, which has a mean of 0 and a standard deviation of 1. To find a particular z-value for a given confidence level, one must reference the z-table or use statistical software.
For example, in finding the z-value corresponding to a specific confidence level:
  • Calculate \(\alpha = 1 - \text{confidence level}\).
  • Determine \(\alpha/2\) for two-tailed tests.
  • Look up this critical value in the z-table to find the precise z-value needed for calculations.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. If the data points are close to the mean, the standard deviation is smaller, indicating that the data is more consistent. Conversely, a larger standard deviation suggests more spread-out data.
Mathematically, it is the square root of the variance (\(\sigma^{2}\)).The computation of standard deviation is fundamental in understanding how data varies around the mean:
  • It helps identify outliers and understand data consistency.
  • It is central to concepts like the z-score, where distances from the mean are measured in standard deviation units.
  • In the context of normal distribution, approximately 68% of data falls within one standard deviation of the mean, 95% within two, and 99.7% within three standard deviations.
Grasping standard deviation is key to understanding variability in data and is essential for confidence interval calculations.
Confidence Level
Confidence level is a crucial concept when making inferences about populations from samples. It represents the probability that the interval estimated from a sample contains the true population parameter. Typically, confidence levels are expressed as a percentage, such as 95% or 99%.
A higher confidence level indicates a higher certainty about the interval covering the true parameter but tends to produce wider intervals. This is because a higher confidence level requires capturing more of the potential distribution range of the sample statistics.
  • Common confidence levels are 90%, 95%, and 99%.
  • The confidence interval is calculated using: Sample Mean ± (Z-value × Standard Deviation/√n)
  • For more certainty (higher confidence), the z-value becomes larger, widening the interval.
Thus, selecting an appropriate confidence level is a balance between precision and certainty in estimation.

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Most popular questions from this chapter

Determine the \(t\) -percentile that is required to construct each of the following two-sided confidence intervals: (a) Confidence level \(=95 \%,\) degrees of freedom \(=12\) (b) Confidence level \(=95 \%,\) degrees of freedom \(=24\) (c) Confidence level \(=99 \%,\) degrees of freedom \(=13\) (d) Confidence level \(=99.9 \%,\) degrees of freedom \(=15\)

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed and that \(\sigma=2\) psi. A random sample of nine specimens is tested, and the average breaking strength is found to be 98 psi. Find a \(95 \%\) two-sided confidence interval on the true mean breaking strength.

Consider the one-sided confidence interval expressions for a mean of a normal population. (a) What value of \(z_{\alpha}\) would result in a \(90 \%\) CI? (b) What value of \(z_{\alpha}\) would result in a \(95 \%\) CI? (c) What value of \(z_{\alpha}\) would result in a \(99 \%\) CI?

A rivet is to be inserted into a hole. A random sample of \(n=15\) parts is selected, and the hole diameter is measured. The sample standard deviation of the hole diameter measurements is \(s=0.008\) millimeters. Construct a \(99 \%\) lower confidence bound for \(\sigma^{2}\).

An article in Cancer Research ["Analyses of Litter-Matched Time-to-Response Data, with Modifications for Recovery of Interlitter Information" \((1977,\) Vol. \(37,\) pp. \(3863-\) 3868 ) ] tested the tumorigenesis of a drug. Rats were randomly selected from litters and given the drug. The times of tumor appearance were recorded as follows: $$ \begin{array}{l} 101,104,104,77,89,88,104,96,82,70,89,91,39,103,93, \\ 85,104,104,81,67,104,104,104,87,104,89,78,104,86 \\ 76,103,102,80,45,94,104,104,76,80,72,73 \end{array} $$ Calculate a \(95 \%\) confidence interval on the standard deviation of time until a tumor appearance. Check the assumption of normality of the population and comment on the assumptions for the confidence interval.

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