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An exponential distribution is known to have a mean of \(10 .\) You want to find the standard error of the median of this distribution if a random sample of size 8 is drawn. Use the bootstrap method to find the standard error, using \(n_{a}=100\) bootstrap samples.

Short Answer

Expert verified
The standard error of the median (via bootstrap) is the standard deviation of the bootstrap medians.

Step by step solution

01

Understand the Parameters of the Distribution

The exponential distribution has a mean of \( \mu = 10 \). For an exponential distribution, the parameter \( \lambda \) (rate) is calculated using \( \lambda = \frac{1}{\mu} \), so \( \lambda = \frac{1}{10} = 0.1 \).
02

Determine the Median of the Exponential Distribution

The median of an exponential distribution with rate \( \lambda \) is given by \( \frac{\ln(2)}{\lambda} \). Substitute \( \lambda = 0.1 \) to find the median: \( \frac{\ln(2)}{0.1} = 6.9315 \).
03

Generate Bootstrap Samples

For the bootstrap method, we need \( n_{a} = 100 \) bootstrap samples. From the given sample of size 8, repeatedly draw samples (with replacement) also of size 8, to generate 100 different bootstrap samples.
04

Calculate the Median for Each Bootstrap Sample

For each of the 100 bootstrap samples generated in Step 3, calculate the sample median. This will result in a distribution of 100 medians.
05

Compute the Standard Error Using Bootstrap Medians

Calculate the standard deviation of the 100 bootstrap medians obtained in Step 4. This standard deviation is the bootstrap estimate of the standard error of the median of the original sample.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Distribution
The exponential distribution is a continuous probability distribution often used to model the time until an event occurs, such as the lifetime of a product. It is characterized by its rate parameter, \( \lambda \), which is the reciprocal of the mean. This distribution is memoryless, meaning that the probability of an event occurring in the future is independent of any past events. In simpler terms, each event occurs independently of the others.

For example, if we have an exponential distribution with a mean of 10, we can determine \( \lambda \) by using the formula \( \lambda = \frac{1}{\mu} \). In this case, \( \mu = 10 \), so \( \lambda = 0.1 \). This rate affects how quickly or slowly events happen.

The median of an exponential distribution can be calculated using \( \frac{\ln(2)}{\lambda} \). This is because the median is the point where half of the distribution's probability is below and half is above.

Understanding the exponential distribution is crucial when dealing with processes where events happen continuously and independently.
Standard Error
The standard error is a statistic that measures the accuracy with which a sample represents a population. It tells us how much the sample statistic (like a mean or a median) would vary if we took multiple samples from the same population.

In simpler terms, it gives us an idea of the reliability of our sample statistic. A smaller standard error indicates more reliable estimates. It is calculated as the standard deviation of the sample divided by the square root of the sample size.

In the context of this exercise, the bootstrap method is used to estimate the standard error of the sample median. By taking many random samples from our initial data and calculating the metric of interest (here, the median) for each sample, we can find how much the median varies. This variation, measured as the standard deviation of those medians, provides an estimate of the standard error.
Sample Median
The sample median is the middle value of a data set when the numbers are arranged in order. It is a measure of central tendency, like the mean, but is less affected by outliers and skewed data.

To find the median of a sample:
  • Order the data from smallest to largest.
  • If the sample size is odd, the median is the middle number.
  • If the sample size is even, the median is the average of the two middle numbers.
In this exercise, the median of an exponential distribution was determined analytically. However, for our bootstrap samples, the median is calculated directly from each sample, illustrating its sensitivity to sample variation.

Understanding the median is valuable, especially in datasets with outliers, as it gives a better overall representation of the dataset's centre.
Statistical Sampling
Statistical sampling refers to the process of selecting a subset of individuals from a population to estimate characteristics of the entire population. This method allows researchers to make inferences about a population without the need for a complete census, which might be impractical or impossible.

There are various sampling methods, and the choice depends on the study's goals, resources, and the nature of the population being studied. In the original problem, the bootstrap method, a resampling technique, is used to draw samples with replacement from the data.

The bootstrap method involves the following steps:
  • Take a random sample from your data set.
  • Replace the sampled data back into your set and draw again, creating a new sample with possible repetitions from the initial data.
  • Repeat these steps several times (100 times in the exercise) to create multiple samples.
These samples are used to estimate the distribution of a statistic, such as the median, allowing us to estimate the standard error and understand the variability of our statistic. This approach highlights the power of resampling techniques in statistical analysis.

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Most popular questions from this chapter

A lot consists of \(N\) transistors. and of these \(M(M \leq N)\) are defective. We randomly select two transistors without replacement from this lot and determine whether they are defective or non defective. The random variable $$ X_{i}=\left\\{\begin{array}{ll} 1, & \text { if the } i \text { th transistor } \\ & \text { is nondefective } \\ 0, & \text { if the ith transistor } \\\ & \text { is defective } \end{array} \quad i=1,2\right. $$ Determine the joint probability function for \(X_{1}\) and \(X_{2}\). What are the marginal probability functions for \(X_{1}\) and \(X_{2}\) ? Are \(X_{1}\) and \(X\), independent random variables?

Data on the oxide thickness of semiconductor wafers are as follows: 425,431,416,419,421,436,418,410 , \(431,433,423,426,410,435,436,428,411,426,409,437,\) 422,428,413,416 (a) Calculate a point estimate of the mean oxide thickness for all wafers in the population. (b) Calculate a point estimate of the standard deviation of oxide thickness for all wafers in the population. (c) Calculate the standard error of the point estimate from part (a). (d) Calculate a point estimate of the median oxide thickness for all wafers in the population. (e) Calculate a point estimate of the proportion of wafers in the population that have oxide thickness of more than 430 angstroms.

Suppose that \(X\) is uniformly distributed on the interval from 0 to 1 . Consider a random sample of size 4 from \(X\). What is the joint probability density function of the sample?

You plan to use a rod to lay out a square, each side of which is the length of the rod. The length of the rod is \(\mu\). which is unknown. You are interested in estimating the area of the square, which is \(\mu^{2}\). Because \(\mu\) is unknown, you measure it \(n\) times, obtaining observations \(X_{1}, X_{2} \ldots, X_{n}\). Suppose that each measurement is unbiased for \(\mu\) with variance \(\sigma^{2}\) (a) Show that \(\bar{X}^{2}\) is a biased estimate of the area of the square. (b) Suggest an estimator that is unbiased.

Suppose that \(X\) is a normal random variable with unknown mean \(\mu\) and known variance \(\sigma^{2}\). The prior distribution for \(\mu\) is a uniform distribution defined over the interval \([a, b]\). (a) Find the posterior distribution for \(\mu\). (b) Find the Bayes estimator for \(\mu\).

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