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Suppose that \(X\) is a normal random variable with unknown mean \(\mu\) and known variance \(\sigma^{2}\). The prior distribution for \(\mu\) is a uniform distribution defined over the interval \([a, b]\). (a) Find the posterior distribution for \(\mu\). (b) Find the Bayes estimator for \(\mu\).

Short Answer

Expert verified
(a) The posterior is a truncated normal distribution. (b) The Bayes estimator is the posterior mean, which is the sample mean.

Step by step solution

01

Define the Problem

We need to find the posterior distribution for the mean \( \mu \) of a normal random variable \( X \) with known variance \( \sigma^2 \). Given that the prior distribution for \( \mu \) is uniform over the interval \( [a, b] \), this means that the prior probability density function is constant over this interval.
02

Establish Likelihood Function

The likelihood function for the normal distribution with known variance \( \sigma^2 \) given data \( X = x \) is \( f(x|\mu) = \frac{1}{\sqrt{2\pi \sigma^2}} e^{-\frac{(x-\mu)^2}{2\sigma^2}} \). This describes the probability of observing the data given \( \mu \).
03

Define the Prior Distribution

Since \( \mu \) is uniformly distributed over \( [a, b] \), the prior distribution is \( f(\mu) = \frac{1}{b-a} \) for \( \mu \in [a, b] \), and zero otherwise.
04

Calculate the Posterior Distribution

Using Bayes' Theorem, the posterior distribution \( f(\mu|x) \) is proportional to the product of the likelihood and the prior: \[ f(\mu|x) \propto f(x|\mu) \cdot f(\mu) = \frac{1}{\sqrt{2\pi \sigma^2}} e^{-\frac{(x-\mu)^2}{2\sigma^2}} \cdot \frac{1}{b-a} \]. As the prior is constant over \([a,b]\), the posterior becomes proportional to \[ f(\mu|x) \propto e^{-\frac{(x-\mu)^2}{2\sigma^2}} \]. This is recognized as the kernel of a normal distribution with mean \( x \) and variance \( \sigma^2 \), truncated over \([a, b]\).
05

Identify the Posterior Distribution

Therefore, the posterior distribution \( f(\mu|x) \) is a truncated normal distribution with mean \( x \) and variance \( \sigma^2 \), over the interval \([a, b]\).
06

Find the Bayes Estimator

For the uniform prior, the Bayes estimator of \( \mu \) under squared error loss is simply the mean of the posterior distribution. Since the posterior mean is simply the sample mean \( x \), provided it lies within \([a, b]\), or otherwise the closest endpoint of \([a,b]\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Distribution
A uniform distribution represents a scenario where all outcomes within a specific range are equally likely. It's akin to rolling a fair die, where each side is equally probable. For the problem at hand, the parameter \(\mu\), which is the mean of the normal random variable, is uniformly distributed over the interval \([a, b]\). This implies that every value of \(\mu\) within this interval has the same probability density. The prior distribution for \(\mu\) takes the form \(f(\mu) = \frac{1}{b-a} \) for \(\mu \in [a, b]\), which ensures that the total probability sums up to 1 over \([a, b]\).

This constant probability density is what defines the uniform nature of the distribution. Outside this interval, the probability density is zero, indicating that we assume \(\mu\) cannot take any values beyond \([a, b]\).
  • This uniform prior is non-informative—it does not suggest any particular value within \([a, b]\) is more likely than another.
Posterior Distribution
The posterior distribution is the crux of Bayesian statistics. It blends prior beliefs with new evidence to form an updated belief about a parameter. Using Bayes' Theorem, we calculate this posterior distribution for \(\mu\) given the data observed.

The theorem posits that the posterior \( f(\mu|x) \) is proportional to the likelihood \( f(x|\mu) \) times the prior \( f(\mu) \). In our example:
  • The likelihood function \( f(x|\mu) \) for a normal distribution is \( \frac{1}{\sqrt{2\pi \sigma^2}} e^{-\frac{(x-\mu)^2}{2\sigma^2}} \).
  • The prior distribution, as we previously established, is uniform, \( \frac{1}{b-a} \).

Multiplying these provides the unnormalized posterior:
\( f(\mu|x) \propto e^{-\frac{(x-\mu)^2}{2\sigma^2}} \).

This expression resembles a Gaussian or normal distribution centered around the observed data point \(x\).

Moreover, because the normal distribution exponentially fades out from its mean, it aligns perfectly with how updated beliefs (posterior) around \(\mu\) emerge given new information.
Bayes Estimator
A Bayes estimator minimizes expected loss, giving us a 'best guess' about a parameter based on our posterior beliefs. Here, under the uniform prior and the rule of squared error loss, the Bayes estimator for \(\mu\) is simply the mean of the posterior distribution.

For the case of a truncated normal distribution, this estimator usually corresponds to the sample mean \(x\), or the observed data itself. However, the condition here is that \(x\) must fall within our prior's bounds \([a, b]\). If \(x\) does not reside within this interval, the estimator defaults to the nearest boundary of the interval.

This ensures that our estimation remains consistent with our uniform prior assumptions. The Bayes estimator offers a reliable point estimation within the framework of Bayesian inference, accounting for data evidence and prior distributions.

  • The simplicity of choosing the sample mean emphasizes the efficacy and intuitiveness of Bayesian techniques in providing practical solutions.

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