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Let \(X_{1}, X_{2}, \ldots, X_{r}\) be independent exponential random variables with parameter \(\lambda\). (a) Find the moment-generating function of \(Y=X_{1}+X_{2}+\) \(\ldots+X_{r}\) (b) What is the distribution of the random variable \(Y ?\)

Short Answer

Expert verified
(a) The MGF is \( \left(\frac{\lambda}{\lambda-t}\right)^r \). (b) \( Y \) follows a Gamma distribution with parameters \( (r, \lambda) \).

Step by step solution

01

Identify the MGF of an Exponential Distribution

For an exponential random variable with parameter \( \lambda \), the moment-generating function (MGF) is given by \( M_X(t) = \frac{\lambda}{\lambda - t} \) for \( t < \lambda \).
02

Determine the MGF of \( Y = X_1 + X_2 + \ldots + X_r \)

Since \(X_1, X_2, \ldots, X_r\) are independent exponential random variables each with parameter \( \lambda \), the MGF of the sum \( Y \) is the product of the MGFs of each \( X_i \). Thus, \( M_Y(t) = \left( \frac{\lambda}{\lambda - t} \right)^r \) for \( t < \lambda \).
03

Recognize the Form of the MGF for Y

The MGF \( \left( \frac{\lambda}{\lambda - t} \right)^r \) is the MGF of a gamma distribution with shape parameter \( r \) and rate parameter \( \lambda \).
04

Conclude the Distribution of Y

Given that \( M_Y(t) \) matches the MGF of a gamma distribution, \( Y \) follows a gamma distribution with parameters \( r \) and \( \lambda \). Specifically, \( Y \sim \text{Gamma}(r, \lambda) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Moment-Generating Functions
A moment-generating function (MGF) is a tool used in probability theory to simplify the process of finding the expected value of a random variable's power. Think of it as a function that summarizes all moments (like the mean and variance) of a distribution in a neat package. For a random variable \( X \), its MGF is defined as \( M_X(t) = E[e^{tX}] \), where \( E \) stands for the expected value. This function helps us understand the behavior of the distribution by generating all its moments.

One of the important properties of MGFs is that if two random variables have the same MGF, they have the same distribution. This is particularly useful in this exercise.

When dealing with independent random variables, like in the problem, the moments can be combined by multiplying the MGFs. For instance, if \( X_1, X_2, \ldots, X_r \) are independent, the MGF of their sum \( Y = X_1 + X_2 + \ldots + X_r \) is the product of their individual MGFs. In this exercise, the exponential distribution has an MGF of \( M_X(t) = \frac{\lambda}{\lambda - t} \). Thus, for the sum \( Y \), the MGF is \( M_Y(t) = \left( \frac{\lambda}{\lambda - t} \right)^r \). This gives us a way to identify the distribution of \( Y \) by matching it to known MGFs, such as the gamma distribution.
Gamma Distribution Explained
The gamma distribution is a continuous distribution that is pivotal in many areas, including waiting times and Bayesian statistics. It is characterized by two parameters: shape and rate (or scale). The shape parameter, often denoted by \( k \) or \( r \), affects the distribution's skewness and determines the number of exponential variables being summed. The rate parameter, denoted by \( \lambda \), scales the distribution.

One key property of the gamma distribution is that when independent exponential random variables with the same rate parameter are summed, the resulting random variable is gamma-distributed. This was observed in the exercise. If \( Y \) is the sum of \( r \) exponential random variables, \( Y \) follows a gamma distribution with shape parameter \( r \) and rate parameter \( \lambda \). Thus, \( Y \sim \text{Gamma}(r, \lambda) \).

Applications of the gamma distribution are vast, ranging from modeling the life expectancy of components, to being a cornerstone in Bayesian inference where it's used for conjugate priors. This profound flexibility and real-world applicability make the gamma distribution an essential concept in statistics and probability.
The Role of Independent Random Variables
Independent random variables form the backbone of many probability theories because their outcomes do not affect one another. This independence simplifies calculations significantly since it allows certain properties of these variables to be combined in straightforward ways.

In the context of the problem, the independence of the exponential variables \( X_1, X_2, \ldots, X_r \) allows us to simply multiply their MGFs to get the MGF of their sum \( Y \). If the variables were dependent, this multiplication wouldn't be possible, as their combined distribution would involve more complex interactions.

Understanding the role of independent random variables extends beyond just mathematical operations. It applies to real-world situations such as understanding various risk factors in financial portfolios, and computing probabilities in games of chance. Independence is a critical assumption in many models and is foundational for ensuring that the models work as expected. Recognizing and utilizing the independence of random variables can unlock powerful techniques and insights in both theoretical and applied statistics.

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