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A random variable \(X\) has the gamma distribution $$ f(x)=\frac{\lambda}{\Gamma(r)}(\lambda x)^{r-1} e^{-\lambda x}, \quad x>0 $$ (a) Show that the moment-generating function of \(X\) is $$ M_{X}(t)=\left(1-\frac{t}{\lambda}\right)^{-r} $$ (b) Find the mean and variance of \(X\).

Short Answer

Expert verified
The MGF is \(\left(1-\frac{t}{\lambda}\right)^{-r}\), with mean \(\frac{r}{\lambda}\) and variance \(\frac{r}{\lambda^2}\).

Step by step solution

01

Understanding the Gamma distribution

The given random variable \(X\) follows a gamma distribution with probability density function (pdf) \(f(x)=\frac{\lambda}{\Gamma(r)}(\lambda x)^{r-1} e^{-\lambda x}\), for \(x>0\). This means \(X\) is characterized by two parameters: \(r\), the shape parameter, and \(\lambda\), the rate parameter.
02

Moment-generating function (MGF) definition

The moment-generating function (MGF) for a random variable \(X\) is defined as \(M_X(t) = E[e^{tX}]\), where \(E[\cdot]\) denotes the expected value. To find the MGF of \(X\), we need to compute this expectation using the gamma distribution's pdf.
03

Calculating the MGF

To find the MGF of \(X\), compute \(M_X(t) = E[e^{tX}] = \int_{0}^{\infty} e^{tx} f(x) \, dx\). Substitute the gamma pdf into the integral to get \[ M_X(t) = \int_{0}^{\infty} e^{tx} \frac{\lambda}{\Gamma(r)}(\lambda x)^{r-1} e^{-\lambda x} \, dx. \]Simplifying inside the integral:\[ M_X(t) = \frac{\lambda^{r}}{\Gamma(r)} \int_{0}^{\infty} x^{r-1} e^{-(\lambda-t)x} \, dx. \]This integral resembles the gamma function form but with a modified parameter \(\lambda - t\).
04

Using the gamma integral

Recall the definition of the gamma function: \[ \Gamma(r) = \int_{0}^{\infty} x^{r-1} e^{-x} \, dx. \]Using substitution, recognize \[ \int_{0}^{\infty} x^{r-1} e^{-(\lambda-t)x} \, dx = \frac{\Gamma(r)}{(\lambda-t)^r}. \] Therefore, \[ M_X(t) = \frac{\lambda^{r}}{\Gamma(r)} \cdot \frac{\Gamma(r)}{(\lambda-t)^r}. \]Now simplify to obtain the MGF:\[ M_X(t) = \left(1-\frac{t}{\lambda}\right)^{-r}. \] This completes the proof for part (a).
05

Mean of the gamma distribution

The mean of the gamma distribution is given by \(E[X] = \frac{r}{\lambda}\). This follows from properties of the gamma distribution, where the mean is the ratio of the shape \(r\) to the rate \(\lambda\).
06

Variance of the gamma distribution

The variance of the gamma distribution is \(\text{Var}(X) = \frac{r}{\lambda^2}\). The variance is derived from the gamma distribution properties, where variance is the shape parameter divided by the square of the rate parameter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment-Generating Function
In probability theory, the moment-generating function (MGF) is an important tool used to summarize a probability distribution. For a random variable \( X \), the MGF is defined as \( M_X(t) = E[e^{tX}] \), where \( E \) denotes the expected value. It helps in characterizing the distribution and is useful for finding moments like the mean and variance. To calculate the MGF for a gamma-distributed variable, we evaluate \( E[e^{tX}] \) using the given probability density function (pdf). The gamma distribution's pdf is \( f(x) = \frac{\lambda}{\Gamma(r)}(\lambda x)^{r-1} e^{-\lambda x} \) for \( x > 0 \). Inserting this into the integral for calculating the MGF, the expression can be simplified using properties of the gamma function. The result, \( M_{X}(t)=\left(1-\frac{t}{\lambda}\right)^{-r} \), is a standard result associated with the gamma distribution.
Mean and Variance
The mean and variance are key characteristics of any probability distribution. They provide insight into the distribution's central tendency and how much the data values spread around the mean.For the gamma distribution, both these values are linked closely to its parameters, \( r \) and \( \lambda \):
  • The mean \( E[X] = \frac{r}{\lambda} \), which represents the average value expected from numerous sampled values of the random variable.
  • The variance \( \text{Var}(X) = \frac{r}{\lambda^2} \) captures the spread or variability in the values. This particular form implies that more variability occurs when the shape parameter \( r \) is given higher values, or when the rate parameter \( \lambda \) is small.
Understanding the relationship of these parameters and their effect on the distribution aids in statistical analysis and modeling.
Probability Density Function
The probability density function (pdf) of a distribution describes the relative likelihood of a random variable to take on a specific value. For a continuous probability distribution like the gamma distribution, we use the pdf to compute probabilities over intervals. The gamma distribution's pdf is given by: \[ f(x) = \frac{\lambda}{\Gamma(r)}(\lambda x)^{r-1} e^{-\lambda x}, \quad x > 0 \]Here, \( \Gamma(r) \) is the gamma function, a generalization of factorial for non-integer values. The terms \( \lambda \) and \( r \) are crucial. \( r \) determines the shape of the distribution, while \( \lambda \) scales it horizontally. Higher values of \( r \) result in distributions with greater peaks and narrow spreads, and a higher \( \lambda \) causes the distribution to stretch, leading to a lower peak height. The pdf is integral to determining other characteristics of the distribution such as moments and cumulative probabilities.
Expected Value
Expected value is a fundamental concept in probability, offering a measure for the 'central tendency' or average outcome one can anticipate from a random process. For random variables, the expected value is akin to weighing each possible outcome by its probability and summing them up.In the context of a gamma distribution, you compute the expected value by integrating over its pdf:\[ E[X] = \int_{0}^{\infty} x f(x) \, dx \]This expected value is found to be \( \frac{r}{\lambda} \), which mirrors our intuition by aligning it with the shape to rate parameter ratio. This ratio signifies how often we expect an event, such as a system failure or a time until an event occurs, based on the context the gamma distribution models. Recognizing and utilizing expected value can help in making predictions and informed decisions in a statistical framework.

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