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The random variable \(X\) has a binomial distribution with \(n=10\) and \(p=0.5 .\) Determine the following probabilities: (a) \(P(X=5)\) (b) \(P(X \leq 2)\) (c) \(P(X \geq 9)\) (d) \(P(3 \leq X<5)\)

Short Answer

Expert verified
(a) 0.2461, (b) 0.05469, (c) 0.01074, (d) 0.3223

Step by step solution

01

Understanding the Problem

We are given a binomial distribution with parameters \(n=10\) and \(p=0.5\). To find probabilities related to this distribution, we'll use the binomial probability formula: \(P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\), where \(\binom{n}{k}\) is the binomial coefficient.
02

Calculating \(P(X=5)\)

Using the binomial formula: \[P(X=5) = \binom{10}{5} (0.5)^5 (0.5)^{10-5} = \binom{10}{5} (0.5)^{10}\]. The binomial coefficient \(\binom{10}{5} = 252\). Thus, \(P(X=5) = 252 \times (0.5)^{10} = 252 \times \frac{1}{1024} = \frac{252}{1024} = 0.2461\).
03

Calculating \(P(X \leq 2)\)

We need \(P(X=0) + P(X=1) + P(X=2)\). Calculate each using binomial formula: 1. \(P(X=0) = \binom{10}{0} (0.5)^0 (0.5)^{10} = 1 \times \frac{1}{1024} = 0.0009766\). 2. \(P(X=1) = \binom{10}{1} (0.5)^1 (0.5)^9 = 10 \times \frac{1}{1024} = 0.009766\). 3. \(P(X=2) = \binom{10}{2} (0.5)^2 (0.5)^8 = 45 \times \frac{1}{1024} = 0.04395\). Adding these gives: \(0.0009766 + 0.009766 + 0.04395 = 0.05469\).
04

Calculating \(P(X \geq 9)\)

We need \(P(X=9) + P(X=10)\). Calculate each:1. \(P(X=9) = \binom{10}{9} (0.5)^9 (0.5)^1 = 10 \times \frac{1}{1024} = 0.009766\).2. \(P(X=10) = \binom{10}{10} (0.5)^{10} = 1 \times \frac{1}{1024} = 0.0009766\).The sum is: \(0.009766 + 0.0009766 = 0.01074\).
05

Calculating \(P(3 \leq X < 5)\)

We need \(P(X=3) + P(X=4)\). Calculate each:1. \(P(X=3) = \binom{10}{3} (0.5)^3 (0.5)^7 = 120 \times \frac{1}{1024} = 0.1172\).2. \(P(X=4) = \binom{10}{4} (0.5)^4 (0.5)^6 = 210 \times \frac{1}{1024} = 0.2051\).The sum is: \(0.1172 + 0.2051 = 0.3223\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
An important concept in statistics is calculating the probability of certain outcomes given a specific probability model. Here, we are dealing with a binomial distribution where the random variable represents the number of successful outcomes given a set number of trials. When calculating these probabilities, we utilize the binomial formula:\[P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\]This formula calculates the probability that the random variable equals a specific value \(k\). To solve this, you must identify the number of trials \(n\), the specific outcome \(k\), and the probability of success \(p\) for each trial.
In simpler terms, the formula helps us calculate how likely it is to obtain exactly \(k\) successes out of \(n\) trials when each trial is a success with a probability of \(p\). The combination part of the formula, represented by the binomial coefficient, tells us how many different sequences can yield \(k\) successes.
Binomial Coefficient
The binomial coefficient is a key part of the binomial probability formula, denoted as \(\binom{n}{k}\). It signifies the number of ways \(k\) successes can occur in \(n\) trials. The calculation follows the formula:\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]Here, \(!\) indicates factorial, meaning you multiply the sequence of descending natural numbers until you reach 1. It accounts for how the successes can be arranged in the overall sequence.
For example, if you have 10 trials and want exactly 5 successes, the binomial coefficient \(\binom{10}{5}\) calculates how many different combinations of successes there are amongst the trials. This aspect is crucial because it adjusts the probability calculation to consider all possible success sequences.
Random Variable
In probability and statistics, a random variable is a variable whose possible values are numerical outcomes of a random phenomenon. In the context of a binomial distribution, it represents the number of successful outcomes out of the total trials. We denote it as \(X\) and it can take values ranging from 0 up to \(n\), where \(n\) is the number of trials.
For instance, with a binomial distribution involving 10 trials, our random variable could be any integer from 0 to 10. Each possible value of the random variable has a certain probability,calculated using the binomial formula. Understanding the random variable with its possible values is crucial when assessing probabilities in specific contexts, such as determining the likelihood of no successes or all successes.
Probability Mass Function
The probability mass function (PMF) is an expression that gives the probability that a discrete random variable is exactly equal to some value. In the case of a binomial distribution, the PMF is represented by the binomial probability formula:\[P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\]The PMF helps determine the probability of each possible value of the random variable \(X\). By evaluating the PMF for different \(k\), you discover the likelihood of achieving each number of successes, which collectively form the distribution of the random variable.
The PMF is advantageous because it visually and numerically represents the probability distribution. This function is vital in making sense of the data and exploring the randomness of a specific phenomenon. Through it, you can better understand the nature of the binomial distribution and facilitate probability calculations for varying scenarios.

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