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If the range of \(X\) is the set \\{0,1,2,3,4\\} and \(P(X=x)\) \(=0.2,\) determine the mean and variance of the random variable.

Short Answer

Expert verified
The mean is 2 and the variance is 2.

Step by step solution

01

Understanding the Probability Distribution

Begin by identifying the probability distribution for \(X\). The random variable \(X\) takes on each of the values in the set \{0, 1, 2, 3, 4\} with probability \(P(X=x)=0.2\). Since the probabilities sum to 1, this confirms that \(X\) is a discrete uniform random variable.
02

Calculating the Mean (Expected Value)

The mean (or expected value) \(E(X)\) of a discrete random variable is calculated using the formula \(E(X) = \sum_{i=0}^{n} x_i \cdot P(X=x_i)\). Here, \(x_i\) are the values in the range of \(X\): 0, 1, 2, 3, 4. Therefore: \[E(X) = 0 \cdot 0.2 + 1 \cdot 0.2 + 2 \cdot 0.2 + 3 \cdot 0.2 + 4 \cdot 0.2\] Calculating each term, we find \(E(X) = 2\).
03

Calculating the Variance

The variance \(Var(X)\) is given by \(Var(X) = E(X^2) - [E(X)]^2\). First, calculate \(E(X^2)\): \[E(X^2) = 0^2 \cdot 0.2 + 1^2 \cdot 0.2 + 2^2 \cdot 0.2 + 3^2 \cdot 0.2 + 4^2 \cdot 0.2\]This simplifies to:\[E(X^2) = 0 + 0.2 + 0.8 + 1.8 + 3.2 = 6\]Then, calculate the variance:\[Var(X) = 6 - (2)^2 = 6 - 4 = 2\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
In probability and statistics, the expected value of a discrete random variable reflects the average or mean value of outcomes that you would expect if you were to repeat a random experiment indefinitely. This concept is fundamental because it provides insight into the central tendency of the distribution of the random variable.

To calculate the expected value, you need to multiply each possible value of the variable by its probability of occurrence and sum all those products. The formula is expressed as:
  • \( E(X) = \sum_{i=0}^{n} x_i \cdot P(X=x_i) \)
For example, in our exercise, values such as 0, 1, 2, 3, and 4 each have a probability of 0.2. Multiplying these values by their probabilities and summing gives us:
  • \( E(X) = 0 \cdot 0.2 + 1 \cdot 0.2 + 2 \cdot 0.2 + 3 \cdot 0.2 + 4 \cdot 0.2 = 2 \)
Thus, the expected value, or the mean, of this distribution is 2.
Variance
Variance measures how much the values of a random variable differ from the expected value, providing an idea of the dispersion or spread of the data around the mean. A lower variance signifies that the values are clustered closely around the mean, while a higher variance indicates a wider spread.

The variance of a discrete random variable is calculated using the formula:
  • \( Var(X) = E(X^2) - [E(X)]^2 \)
Here, you first need \(E(X^2)\), the expected value of the square of the random variable. In our exercise:
  • \( E(X^2) = 0^2 \cdot 0.2 + 1^2 \cdot 0.2 + 2^2 \cdot 0.2 + 3^2 \cdot 0.2 + 4^2 \cdot 0.2 = 6 \)
This result helps us find the variance:
  • \( Var(X) = 6 - (2)^2 = 2 \)
Hence, the variance of the distribution is 2, indicating the degree to which the values of the random variable deviate from the mean.
Discrete Random Variables
Discrete random variables are variables that take on a countable number of distinct values. These values are outcomes of a random phenomenon. Such variables are common in scenarios where outcomes can be distinctly categorized with no intermediates, such as rolling dice or counting heads in coin tosses.

Each value of a discrete random variable is associated with a probability, which adds up to 1 when all potential outcomes are considered. This allows for the calculation of measures such as expected value and variance, which give insights into the distribution's behavior.

In our exercise, the random variable \(X\) takes values from the set \{0, 1, 2, 3, 4\}, each with an equal probability of 0.2. This uniform distribution shows that each outcome is equally likely, a characteristic of discrete uniform distributions. Understanding discrete random variables helps in predicting and analyzing random events through quantitative measures.

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