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The number of telephone calls that arrive at a phone exchange is often modeled as a Poisson random variable. Assume that on the average there are 10 calls per hour. (a) What is the probability that there are exactly 5 calls in one hour? (b) What is the probability that there are 3 or fewer calls in one hour? (c) What is the probability that there are exactly 15 calls in two hours? (d) What is the probability that there are exactly 5 calls in 30 minutes?

Short Answer

Expert verified
(a) Use PMF for \( k=5, \lambda=10 \). (b) Sum PMFs for \( k=0 \) to \( 3 \), \( \lambda=10 \). (c) Use PMF for \( k=15, \lambda=20 \). (d) Use PMF for \( k=5, \lambda=5 \).

Step by step solution

01

Understanding the Poisson Distribution

The Poisson distribution is useful for modeling the number of events that happen within a specific time period. It is defined by the parameter \( \lambda \), which is the average number of events in the given time period. Here, \( \lambda = 10 \) for one hour.
02

Calculation for Question (a)

To find the probability of exactly 5 calls in one hour, we use the Poisson probability mass function (PMF): \[ P(X = k) = \frac{e^{-\lambda} \cdot \lambda^k}{k!} \] where \( k = 5 \) and \( \lambda = 10 \). Thus: \[ P(X = 5) = \frac{e^{-10} \cdot 10^5}{5!} \] Evaluating this gives the probability of exactly 5 calls in one hour.
03

Calculation for Question (b)

To find the probability of 3 or fewer calls in one hour, sum the probabilities of obtaining 0, 1, 2, and 3 calls: \[ P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) \] Use the Poisson PMF to calculate each of these probabilities with \( \lambda = 10 \) and sum them to find the result.
04

Calculation for Question (c)

For 15 calls in two hours, we first adjust our \( \lambda \) for the new time period. Since \( \lambda = 10 \) for one hour, \( \lambda = 20 \) for two hours. Use the PMF for \( k = 15 \) and \( \lambda = 20 \): \[ P(X = 15) = \frac{e^{-20} \cdot 20^{15}}{15!} \] Calculate this probability to get the result for exactly 15 calls in two hours.
05

Calculation for Question (d)

To find the probability of exactly 5 calls in 30 minutes, we again adjust \( \lambda \) to correspond to 30 minutes. Thus, \( \lambda = 5 \). Use the Poisson PMF for \( k = 5 \) and \( \lambda = 5 \): \[ P(X = 5) = \frac{e^{-5} \cdot 5^5}{5!} \] Evaluate this expression to find the probability of exactly 5 calls in 30 minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Mass Function
The Probability Mass Function (PMF) is a central concept in understanding discrete probability distributions like the Poisson Distribution. For any given random variable, the PMF provides the probability that the random variable equals a specific value. In simpler terms, it tells you how likely it is for a particular outcome to occur. For the Poisson distribution, the PMF is given by the formula: \[ \P(X = k) = \frac{e^{-\lambda} \cdot \lambda^k}{k!} \] Here, \(X\) is the random variable representing the number of events, \(k\) is the number of events you are interested in, and \(\lambda\) is the average rate of occurrence within a given time frame. For phone calls arriving at an exchange, \(\lambda\) might be 10 calls per hour. The PMF helps us calculate probabilities for exact counts, like exactly 5 calls in one hour, using the given rate of event occurrence, \(\lambda\). Understanding the PMF allows students to tackle various probability questions efficiently, like determining the likelihood of specific numbers of calls in different timespans.
Random Variable
A Random Variable is a sophisticated yet crucial concept in probability and statistics. It's a variable whose possible values are numerical outcomes of a random process. Random variables can be classified into two main types: discrete and continuous. In our case, we focus on discrete random variables, where each value represents a countable outcome, like the number of calls to a phone exchange in an hour. For instance, let \(X\) denote the number of calls. When we say \(X\) is a Poisson random variable, it means:
  • It's the result of counting the occurrence of events (calls) in fixed intervals (time).
  • Each event happens independently of the others.
  • The average number of events (\(\lambda\)) is constant over periods of the same length.
Understanding random variables is key to setting up and solving probability questions with the Poisson distribution. It's about recognizing which outcomes need to be calculated and why, turning real-world scenarios, like phone calls, into a mathematical model that can be analyzed.
Statistical Modeling
Statistical Modeling involves crafting a mathematical framework that represents real-world data scenarios. The Poisson Distribution is an excellent example of a statistical model, where it is applied to situations capturing the occurrence of events over set periods. This type of modeling helps interpret and predict data patterns by analyzing event rates and distributions. When dealing with telephone calls at a phone exchange, statistical modeling allows us to make predictions and assess probabilities for specific numbers of phone calls in defined intervals. Consider key characteristics of good statistical models:
  • They should fit the data and scenario well, capturing the essence of what's happening.
  • Models must account for independent events, constant average rates, and discrete outcomes.
  • They provide valuable insights for decision-making and can be optimized to improve predictions.
Grasping the basics of statistical modeling ensures that students can apply it to a variety of fields, from telecommunications to inventory management, enriching their analytical toolbox with practical, data-driven solutions.

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