/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 118 The following are the number of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The following are the number of defects observed on 15 samples of transmission units in an automotive manufacturing company. Each lot contains five transmission units. (a) Using all the data, compute trial control limits for a \(U\) control chart, construct the chart, and plot the data. (b) Determine whether the process is in statistical control. If not, assume assignable causes can be found and out-ofcontrol points eliminated. Revise the control limits. $$\begin{array}{cccc}\hline \text { Sample } & \text { No. of Defects } & \text { Sample } & \text { No. of Defects } \\\\\hline 1 & 8 & 11 & 6 \\\2 & 10 & 12 & 10 \\\3 & 24 & 13 & 11 \\\4 & 6 & 14 & 17 \\\5 & 5 & 15 & 9 \\\6 & 21 & & \\\7 & 10 & & \\\8 & 7 & & \\\9 & 9 & & \\\10 & 15 & & \\\& &\end{array}$$

Short Answer

Expert verified
Process is not in control; revise control limits after excluding out-of-control points.

Step by step solution

01

Calculate the Average Number of Defects per Unit

To calculate the average number of defects per unit, first find the total number of defects. The total defects are the sum of all defects across all samples: \[ 8 + 10 + 24 + 6 + 5 + 21 + 10 + 7 + 9 + 15 + 6 + 10 + 11 + 17 + 9 = 168 \]Since each sample consists of 5 units, the total number of units inspected is 15 samples \( \times \) 5 units each = 75 units. Thus, the average number of defects per unit (\( \bar{u} \)) is:\[ \bar{u} = \frac{168}{75} = 2.24 \]
02

Calculate Control Limits for U-Chart

The upper control limit (UCL) and the lower control limit (LCL) for a U-chart are calculated as follows:- \( \text{UCL} = \bar{u} + 3\sqrt{\frac{\bar{u}}{n}} \)- \( \text{LCL} = \bar{u} - 3\sqrt{\frac{\bar{u}}{n}} \)Given \( \bar{u} = 2.24 \) and \( n = 5 \) (number of units in each sample), compute:- \( \text{UCL} = 2.24 + 3\sqrt{\frac{2.24}{5}} = 2.24 + 3\times 0.668\approx 4.244 \)- \( \text{LCL} = 2.24 - 3\sqrt{\frac{2.24}{5}} = 2.24 - 3\times 0.668 \approx 0.236 \)Since LCL cannot be negative for a U-chart, set it to zero.
03

Plot the Control Chart

Using the calculated control limits and the sample data, plot the U-chart. Each sample's defect count normalized by the number of units (five) is a point on the chart. Points are plotted at: 1. 1.6, 2.0, 4.8, 1.2, 1.0, 4.2, 2.0, 1.4, 1.8, 3.0, 1.2, 2.0, 2.2, 3.4, 1.8. All calculations should stay within the control limits to indicate the process is in control.
04

Analyze Statistical Control

Check the plotted points against the control limits to determine if any points fall outside the UCL or LCL. If any points are outside the control limits, it indicates the process may be out of control.
05

Revise Control Limits if Needed

If any points are outside the limits, assume assignable causes and remove those points from the dataset. Recalculate the control limits with the remaining data using the methods from Step 1 and Step 2 to get new control limits.
06

Conclusion

After reviewing the plotted points against the control limits: - If all points are within the control limits, the process is in statistical control. - If points were initially out of control and were removed and recalculated as in Step 5, the revised process' control should now show statistical stability.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Control
Statistical control is an essential concept in process management that helps us understand if a manufacturing process is operating consistently and predictably. Through tools like the U control chart, we can monitor processes over time by checking if variations in data fall within calculated control limits.

The goal is to identify whether variations are part of normal operations or if they indicate a problem. Initially, you calculate control limits from sample data. By plotting your data and observing whether points fall inside these control limits, you can judge the process's stability.

In this exercise, statistical control means verifying whether all plotted points on a U-chart lie within the calculated limits. If they don't, it suggests the presence of special causes of variation. Statistical control allows us to maintain consistent quality, manage defects effectively, and improve manufacturing processes through systematic analysis.
Control Limits
Control limits are crucial for interpreting data in a U control chart. They provide boundaries that signify the expected range of variation in a process due to common causes.

The upper control limit (UCL) and lower control limit (LCL) are calculated based on the average number of defects per unit and the sample size. It is essential to understand that these limits are not "specification" limits but statistical thresholds indicating the point at which variations may be unacceptable or require attention.- **Calculating Limits**: The formula to calculate control limits for a U chart is: - UCL = \( \bar{u} + 3\sqrt{\frac{\bar{u}}{n}} \) - LCL = \( \bar{u} - 3\sqrt{\frac{\bar{u}}{n}} \) Here, \( \bar{u} \) is the average defects per unit, and \( n \) is the sample size.- **Interpreting the Limits**: If observational points on the chart fall outside these boundaries, it may indicate special causes of variation, suggesting that some aspects of the process might need improvement or adjustment.

Establishing proper control limits is imperative as it helps you monitor the process reliably and take corrective actions to maintain statistical control.
Defects Analysis
Defects analysis is a method to evaluate and understand anomalies in manufacturing quality. In the context of a U control chart, it involves analyzing the number of defects across samples to assess process performance.

The purpose is to distinguish between common cause variations and special causes. Common cause variations are inherent and typically random fluctuations. On the other hand, special causes are unusual or systemic factors that have led to changes in process outputs. When analyzing defects: - **Identify Patterns**: Look at plotted data to note any patterns or outliers. Consistent patterns may suggest underlying issues not immediately visible. - **Investigate Causes**: If defects fall outside control limits or if there are trends, further investigation is required. You need to find if there are any assignable causes why some points deviate from the norm. - **Take Action**: Based on analysis, corrective actions might include process adjustments, equipment maintenance, or personnel training to eliminate the identified special causes.

This analysis assists in maintaining a higher quality in production by addressing the root causes of defects, thus leading to fewer reworks, waste reduction, and increased customer satisfaction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An EWMA chart with \(\lambda=0.5\) and \(L=3.07\) is to be used to monitor a process. Suppose that the process mean is \(\mu_{0}=10\) and \(\sigma=2\) (a) Assume that \(n=1\). What is the ARL without any shift in the process mean? What is the ARL to detect a shift to \(\mu=12\) (b) Assume that \(n=4\). Repeat part (a) and comment on your conclusions.

Consider an \(\bar{X}\) control chart with k-sigma control limits and subgroup size \(n\). Develop a general expression for the probability that a point plots outside the control limits when the process mean has shifted by \(\delta\) units from the center line.

The \(P C R\) for a measurement is 1.5 and the control limits for an \(\bar{X}\) chart with \(n=4\) are 24.6 and 32.6 . (a) Estimate the process standard deviation \(\sigma\). (b) Assume that the specification limits are centered around the process mean. Calculate the specification limits.

A process mean is centered between the specification limits and \(P C R=1.33 .\) Assume that the process mean increases by \(1.5 \sigma\). (a) Calculate \(P C R\) and \(P C R_{k}\) for the shifted process. (b) Calculate the estimated fallout from the shifted process and compare your result to those in Table \(15-4 .\) Assume a normal distribution for the measurement.

Suppose that the average number of defects in a unit is known to be 8 . If the mean number of defects in a unit shifts to \(16,\) what is the probability that it is detected by a \(U\) chart on the first sample following the shift (a) if the sample size is \(n=4 ?\) (b) if the sample size is \(n=10 ?\) Use a normal approximation for \(U\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.