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The \(P C R\) for a measurement is 1.5 and the control limits for an \(\bar{X}\) chart with \(n=4\) are 24.6 and 32.6 . (a) Estimate the process standard deviation \(\sigma\). (b) Assume that the specification limits are centered around the process mean. Calculate the specification limits.

Short Answer

Expert verified
(a) \( \sigma \approx 0.8889 \). (b) Specification limits are approximately 25.9 and 31.3.

Step by step solution

01

Understand the Problem

We need to estimate the process standard deviation \( \sigma \) given the \( PCR \) and the control limits for the \( \bar{X} \) chart, and then use this \( \sigma \) to find the specification limits assuming they are centered around the process mean.
02

Use PCR Formula to Estimate \( \sigma \)

The Process Capability Ratio (PCR) is defined as \( PCR = \frac{USL - LSL}{6\sigma} \). We are given \( PCR = 1.5 \). Rearrange the formula to solve for \( \sigma \):\[6\sigma = \frac{32.6 - 24.6}{1.5}\]\[6\sigma = \frac{8}{1.5} = 5.3333\]\[\sigma = \frac{5.3333}{6} \approx 0.8889\]
03

Calculate the Process Mean

The control limits for an \( \bar{X} \) chart are calculated as \( \bar{X} \pm A_2 \sigma \) where \( \bar{X} \) is the process mean and \( A_2 \) is a factor depending on sample size. Since the CLs are symmetrical, the mean \( \bar{X} \) is midway between the control limits:\[\bar{X} = \frac{24.6 + 32.6}{2} = 28.6\]
04

Calculate the Specification Limits

Assuming the specification limits are centered around the process mean \( \bar{X} = 28.6 \), the specification limits are calculated using \( 3\sigma \) on each side:\[USL = \bar{X} + 3\sigma = 28.6 + 3(0.8889) = 28.6 + 2.6667 \approx 31.3\]\[LSL = \bar{X} - 3\sigma = 28.6 - 3(0.8889) = 28.6 - 2.6667 \approx 25.9\]Thus, the specification limits are approximately 25.9 and 31.3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Process Standard Deviation
The process standard deviation, denoted by \( \sigma \), is an important metric in quality control and process management. It measures the amount of variation or spread in a process. To find \( \sigma \), we often work with various formulas, one being the Process Capability Ratio (PCR). The formula for PCR is given by:\[PCR = \frac{USL - LSL}{6\sigma}\]where \( USL \) and \( LSL \) represent the Upper and Lower Specification Limits, respectively. In our step-by-step solution, we rearrange the formula to solve for \( \sigma \), demonstrating its calculation using actual data. This calculated \( \sigma \) helps determine how well the process produces within required specifications. Understanding \( \sigma \) is crucial, as it directly influences decisions about process adjustments, helping maintain standard quality levels.
Control Limits
Control limits are essential elements in statistical process control (SPC), particularly in \( \bar{X} \) charts. They represent the boundaries within which a process operates in a stable and predictable manner. These limits are statistically calculated and are different from specification limits. They guide the process by indicating the normal range of variation.
These limits usually consist of the Upper Control Limit (UCL) and Lower Control Limit (LCL), typically set at \( \pm 3\sigma \) from the process mean \( \bar{X} \). In our exercise, control limits are given as 24.6 and 32.6, and are calculated based on the sample size and standard deviation. If the process data stays within these limits, it is considered "in control," allowing for process stability evaluations. Regular monitoring helps detect any signs of variation that fall outside these limits, prompting necessary process improvements.
Specification Limits
Specification limits denote the range of acceptable values established by design or customer requirements. Unlike control limits, they are not derived from the process itself but are externally set standards describing what the process should achieve.
In the exercise, we assume that the specification limits should be centered around the process mean. Using the estimated process standard deviation \( \sigma \), the Upper Specification Limit (USL) and the Lower Specification Limit (LSL) are calculated as \( \bar{X} \pm 3\sigma \). This assumes the process follows a Normal distribution and aims to capture most of the data points within the permissible range. Knowing the specification limits helps ensure that the output meets the required quality, providing crucial targets for process performance and quality assurance efforts.
\( \bar{X} \) Chart
The \( \bar{X} \) chart is a type of control chart primarily used to monitor the mean of a process over time. It is particularly useful for detecting shifts in the process average. By plotting sample means, it helps identify significant deviations from the process target.
The process mean \( \bar{X} \) is calculated as the average of the control limits, ensuring it accurately reflects the midpoint of the data spread. For a sample size \( n \), charts use a factor \( A_2 \) to determine control limits around this mean.
One key purpose of the \( \bar{X} \) chart is to highlight any trends or cycles in the process that may need attention. It allows for continuous quality improvement by visually displaying points that fall outside the expected normal range. This proactive monitoring helps detect irregularities early, assisting in maintaining process integrity and adherence to quality standards.

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Most popular questions from this chapter

Suppose that a quality characteristic is normally distributed with specifications at \(120 \pm 20 .\) The process standard deviation is \(6.5 .\) (a) Suppose that the process mean is \(120 .\) What are the natural tolerance limits? What is the fraction defective? Calculate \(P C R\) and \(P C R_{k}\) and interpret these ratios. (b) Suppose that the process mean shifts off-center by 1.5 standard deviations toward the upper specification limit. Recalculate the quantities in part (a). (c) Compare the results in parts (a) and (b) and comment on any differences.

An article in Quality \& Safety in Health Care ["Statistical Process Control as a Tool for Research and Healthcare Improvement"' \((2003\) Vol. \(12,\) pp. \(458-464)]\) considered a number of control charts in healthcare. An \(X\) chart was constructed for the amount of infectious waste discarded each day (in pounds). The article mentions that improperly classified infectious waste (actually not hazardous) adds substantial costs to hospitals each year. The following tables show approximate data for the average daily waste per month before and after process changes, respectively. The process change included an education campaign to provide an operational definition for infectious waste. Before Process Change $$\begin{array}{lccccccccc}\text { Month } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 \\\\\text { Waste } & 6.9 & 6.8 & 6.9 & 6.7 & 6.9 & 7.5 & 7 & 7.4 & 7 \\\\\hline \text { Month } & 13 & 14 & 15 & 16 & 17 & 18 & 19 & 20 & 21 \\\\\text { Waste } & 7.5 & 7.4 & 6.5 & 6.9 & 7.0 & 7.2 & 7.8 & 6.3 & 6.7\end{array}$$ After Process Change $$\begin{array}{lcccccccccccc}\text { Month } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 \\\\\text { Waste } & 5.0 & 4.8 & 4.4 & 4.3 & 4.6 & 4.3 & 4.5 & 3.5 & 4.0 & 4.1 & 3.8 & 5.0 \\\\\hline \text { Month } & 13 & 14 & 15 & 16 & 17 & 18 & 19 & 20 & 21 & 22 & 23 & 24 \\\\\text { Waste } & 4.6 & 4.0 & 5.0 & 4.9 & 4.9 & 5.0 & 6.0 & 4.5 & 4.0 & 5.0 & 4.5 & 4.6 \\\\\hline \text { Month } & 25 & 26 & 27 & 28 & 29 & 30 & & & & & & \\\\\text { Waste } & 4.6 & 3.8 & 5.3 & 4.5 & 4.4 & 3.8 & & & & & &\end{array}$$ (a) Handle the data before and after the process change separately and construct individuals and moving-range charts for each set of data. Assume that assignable causes can be found and eliminate suspect observations. If necessary, revise the control limits. (b) Comment on the control of each chart and differences between the charts. Was the process change effective?

\( \) An \(\bar{X}\) chart uses a sample of size \(3 .\) The center line is at \(200,\) and the upper and lower 3 -sigma control limits are at 212 and \(188,\) respectively. (a) Estimate the process \(\sigma\). (b) Suppose that the process mean shifts to \(195 .\) Determine the probability that this shift is detected on the next sample. (c) Find the ARL to detect the shift in part (b).

Suppose that a quality characteristic is normally distributed with specifications from 20 to 32 units. (a) What value is needed for \(\sigma\) to achieve a \(P C R\) of \(1.5 ?\) (b) What value for the process mean minimizes the fraction defective? Does this choice for the mean depend on the value of \(\sigma\) ?

An \(\bar{X}\) control chart with three-sigma control limits has \(U C L=48.75\) and \(L C L=42.71 .\) Suppose that the process standard deviation is \(\sigma=2.25 .\) What subgroup size was used for the chart?

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