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Show that in a simple linear regression model the point \((\bar{x}, \bar{y})\) lies exactly on the least squares regression line.

Short Answer

Expert verified
The point \((\bar{x}, \bar{y})\) lies on the regression line because \(\bar{y} = \beta_0 + \beta_1 \bar{x}\), verifying this relationship.

Step by step solution

01

Understand the Least Squares Regression Line Equation

The least squares regression line in a simple linear regression is given by the equation: \( y = \beta_0 + \beta_1 x \), where \( \beta_0 \) is the y-intercept and \( \beta_1 \) is the slope of the line.
02

Express the Slope \(\beta_1\) of Regression Line

The slope \(\beta_1\) in the least squares regression line is calculated by: \( \beta_1 = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2} \). This formula represents how much the dependent variable \( y \) changes with a unit change in \( x \).
03

Express the Intercept \(\beta_0\) of Regression Line

The y-intercept \(\beta_0\) can be expressed as follows: \( \beta_0 = \bar{y} - \beta_1 \bar{x} \). This means that the line crosses the y-axis at the value \( \bar{y} - \beta_1 \bar{x} \).
04

Substituting \((\bar{x}, \bar{y})\) into the Regression Equation

To show that \((\bar{x}, \bar{y})\) lies on the regression line, substitute \(\bar{x}\) into the regression line equation. This gives: \( \bar{y} = \beta_0 + \beta_1 \bar{x} \).
05

Simplify the Expression

Substitute \( \beta_0 = \bar{y} - \beta_1 \bar{x} \) from Step 3 into the equation \( \bar{y} = \beta_0 + \beta_1 \bar{x} \). This yields: \( \bar{y} = (\bar{y} - \beta_1 \bar{x}) + \beta_1 \bar{x} \).
06

Verify the Equality

Simplifying the expression from Step 5, we have \( \bar{y} = \bar{y} - \beta_1 \bar{x} + \beta_1 \bar{x} \). The terms \(-\beta_1 \bar{x}\) and \(+\beta_1 \bar{x}\) cancel each other, simplifying to \( \bar{y} = \bar{y} \), thus verifying \((\bar{x}, \bar{y})\) lies on the regression line.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least Squares Regression Line
The least squares regression line is a statistical method that helps find the best-fitting straight line through a set of data points in a scatter plot. This technique aims to minimize the sum of the squared differences between the observed values and the values predicted by the line. This way, the line represents the trend of the data most accurately. The equation of a least squares regression line is typically written as \( y = \beta_0 + \beta_1 x \), where \( \beta_0 \) is the y-intercept and \( \beta_1 \) is the slope of the line.

One of the key advantages of using the least squares regression line is its ability to make predictions. By simply plugging in values of the independent variable \( x \), you can predict the corresponding values of the dependent variable \( y \). This line remains "the best fit" as it reduces the errors of prediction (the residuals).
  • Easy to compute with software tools like Excel or statistical software.
  • Widely used in many fields, including economics, finance, and the social sciences.
Slope of the Line
The slope of the line, denoted as \( \beta_1 \), is a crucial component in a simple linear regression model. It quantifies the rate of change of the dependent variable \( y \) with respect to the independent variable \( x \). In other words, it tells us how much \( y \) is expected to increase (or decrease) for each one-unit increase in \( x \).

Mathematically, the slope \( \beta_1 \) is calculated using the formula:\[ \beta_1 = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2} \]
This represents the covariance between the variables \( x \) and \( y \) divided by the variance of \( x \).
  • If \( \beta_1 > 0 \), the relationship between \( x \) and \( y \) is positive.
  • If \( \beta_1 < 0 \), the relationship is negative.
  • If \( \beta_1 = 0 \), there is no relationship.
Intercept of the Regression Line
The y-intercept of the regression line, represented as \( \beta_0 \), is the point where the line crosses the y-axis. It is the expected value of \( y \) when the independent variable \( x \) is zero. This value provides a starting point for the line on the graph.

The intercept \( \beta_0 \) is calculated using the formula:\[ \beta_0 = \bar{y} - \beta_1 \bar{x} \]
This means you subtract the product of the slope \( \beta_1 \) and the mean of \( x \) from the mean of \( y \).
  • It is essential for drawing the line correctly on a graph.
  • It may not always have a practical interpretation, especially if \( x = 0 \) is outside the range of observed data.
Dependent Variable
In a simple linear regression model, the dependent variable is the outcome or the variable that you aim to predict. It is denoted as \( y \) in the regression equation. The changes in this variable are assumed to be caused by changes in the independent variable \( x \).

The dependent variable is central to any regression analysis because it is the variable that researchers are most interested in understanding or predicting. By examining how this variable changes in response to different values of \( x \), one can draw meaningful interpretations and conclusions.
  • Helps identify how one factor affects outcomes, crucial for decision-making.
  • In experiments, it is the variable that is measured to assess the effect of changes in \( x \).

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Most popular questions from this chapter

The World Health Organization defines obesity in adults as having a body mass index (BMI) higher than \(30 .\) Of the 250 men in the study mentioned in Exercise \(11-1,23\) are by this definition obese. How good is waist (size in inches) as a predictor of obesity? A logistic regression model was fit to the data: $$\log \left (\frac{p} {1-p}\right)=-41.828+0.9864 \ \mathrm{waist} $$ where \(p\) is the probability of being classified as obese. (a) Does the probability of being classified as obese increase or decrease as a function of waist size? Explain. (b) What is the estimated probability of being classified as obese for a man with a waist size of 36 inches? (c) What is the estimated probability of being classified as obese for a man with a waist size of 42 inches? (d) What is the estimated probability of being classified as obese for a man with a waist size of 48 inches? (e) Make a plot of the estimated probability of being classified as obese as a function of waist size.

Suppose that data are obtained from 20 pairs of \((x, y)\) and the sample correlation coefficient is \(0.75 .\) (a) Test the hypothesis that \(H_{0}: \rho=0\) against \(H_{1}: \rho>0\) with \(\alpha=0.05 .\) Calculate the \(P\) -value. (b) Test the hypothesis that \(H_{1}: \rho=0.5\) against \(H_{1}: \rho>0.5\) with \(\alpha=0.05 .\) Calculate the \(P\) -value. (c) Construct a \(95 \%\) one-sided confidence interval for the correlation coefficient. Explain how the questions in parts (a) and (b) could be answered with a confidence interval.

Suppose that we have \(n\) pairs of observations \(\left(x_{i}, y_{i}\right)\) such that the sample correlation coefficient \(r\) is unity (approximately). Now let \(z_{i}=y_{i}^{2}\) and consider the sample correlation coefficient for the \(n\) -pairs of data \(\left(x_{i}, z_{i}\right)\). Will this sample correlation coefficient be approximately unity? Explain why or why not.

Determine if the following models are intrinsically linear. If yes, determine the appropriate transformation to generate the linear model. (a) \(Y=\beta_{0} x^{\beta_{1}} \epsilon\) (b) \(Y=\frac{3+5 x}{x}+\epsilon\) (c) \(Y=\beta_{0} \beta_{1}^{x} \epsilon\) (d) \(Y=\frac{x}{\beta_{0} x+\beta_{1}+x \epsilon}\)

An article in Concrete Research ["Near Surface Characteristics of Concrete: Intrinsic Permeability" (1989, Vol.41) ] presented data on compressive strength \(x\) and intrinsic permeability \(y\) of various concrete mixes and cures. Summary quantities are \(n=14, \sum y_{i}=572, \sum y_{i}^{2}=23,530, \sum x_{i}=43,\) \(\sum x_{i}^{2}=157.42,\) and \(\sum x_{i} y_{i}=1697.80 .\) Assume that the two variables are related according to the simple linear regression model. (a) Calculate the least squares estimates of the slope and intercept. Estimate \(\sigma^{2}\). Graph the regression line. (b) Use the equation of the fitted line to predict what permeability would be observed when the compressive strength is \(x=4.3 .\) (c) Give a point estimate of the mean permeability when compressive strength is \(x=3.7\) (d) Suppose that the observed value of permeability at \(x=3.7\) is \(y=46.1 .\) Calculate the value of the corresponding residual.

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