/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The diameter of holes for a cabl... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The diameter of holes for a cable harness is known to have a normal distribution with \(\sigma=0.01\) inch. A random sample of size 10 yields an average diameter of 1.5045 inch. Find a \(99 \%\) two-sided confidence interval on the mean hole diameter.

Short Answer

Expert verified
The 99% confidence interval for the mean hole diameter is [1.49636, 1.51264] inches.

Step by step solution

01

Identify Given Information

We are given that the population standard deviation \(\sigma = 0.01\) inch, the sample size \(n = 10\), and the sample mean \(\bar{x} = 1.5045\) inches. We are asked to find a 99% confidence interval for the mean diameter.
02

Find the Z-Score for 99% Confidence

For a 99% confidence level, we need to find the corresponding Z-score. From the standard normal distribution table, the Z-score for 99% confidence is approximately \(Z = 2.576\).
03

Calculate the Standard Error

The standard error (SE) of the sample mean is calculated using the formula: \(SE = \frac{\sigma}{\sqrt{n}}\). Substituting the given values, \(SE = \frac{0.01}{\sqrt{10}} \approx 0.00316\).
04

Compute the Margin of Error

The margin of error (ME) is calculated by multiplying the Z-score from Step 2 with the SE from Step 3: \(ME = Z \times SE = 2.576 \times 0.00316 \approx 0.00814\).
05

Find Confidence Interval Bounds

The 99% confidence interval is determined using the formula: \([\bar{x} - ME, \bar{x} + ME]\). Substituting the values, we get: \([1.5045 - 0.00814, 1.5045 + 0.00814]\), which simplifies to \([1.49636, 1.51264]\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
Normal distribution is a continuous probability distribution that is symmetrical around its mean. This means most of the data falls close to the mean, with values further from the mean becoming less likely as you move away. It is often represented as a bell-shaped curve. For example, in the case of our problem, the diameter of holes is normally distributed with a known standard deviation.
  • The curve of normal distribution is symmetric, which means the left side is a mirror image of the right side.
  • The highest point on the curve is the mean, median, and mode of the data.
  • The spread of the curve is determined by the standard deviation.
Understanding normal distribution helps in calculating probabilities and confidence intervals, which are useful in statistics for predicting future data points. In our exercise, we know the standard deviation of hole diameters, indicating that measurements spread around the mean in this predictable pattern.
Sample Mean
The sample mean is an average of a set of data points from a sample, which represents a larger population. It provides an estimate of the population mean when it's difficult to obtain data from the entire population. From our exercise, the average diameter measured was 1.5045 inches.
  • The formula for calculating sample mean is \(\bar{x} = \frac{\sum{x_i}}{n}\), where \(x_i\) are individual observations and \(n\) is the sample size.
  • The sample mean is sensitive to extreme values or outliers.
  • It's important in estimating parameters and constructing confidence intervals.
In statistics, the sample mean is utilized because it gives us a snapshot of the population characteristics through a smaller, manageable portion of data.
Z-Score
A Z-score indicates how many standard deviations an element is from the mean. In our problem, it is used to find the boundary for a confidence interval, which shows the degree of certainty for estimating a population parameter. For a 99% confidence interval, the Z-score used is approximately 2.576.
  • The Z-score for a particular confidence level is found from the standard normal distribution table.
  • A higher Z-score corresponds to a higher confidence level, implying that you are more statistically confident that the population parameter lies within your interval.
  • It is crucial to choose the correct Z-score for your desired confidence level to ensure the results are valid.
Z-scores help in standardizing data points, allowing us to compare different kinds of data on a common scale. In our calculation, the Z-score is crucial for determining the margin of error.
Standard Error
The standard error (SE) measures the dispersion of the sample mean estimate from the population mean. It quantifies how much the sample mean is expected to vary if different samples are taken from the same population. In the exercise, it is calculated as approximately 0.00316 inches.
  • The formula for standard error is \( SE = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the population standard deviation and \( n \) is the sample size.
  • A larger sample size \( n \) results in a smaller SE, meaning the sample mean is likely closer to the actual population mean.
  • SE is critical for constructing confidence intervals, influencing the width of the interval.
Understanding standard error is important for interpreting data that involves sampling. It allows statisticians to make inferences about the population mean with known precision, as it forms the basis for calculating the margin of error in confidence intervals.

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Most popular questions from this chapter

Suppose that \(n=100\) random samples of water from a freshwater lake were taken and the calcium concentration (milligrams per liter) measured. A \(95 \%\) CI on the mean calcium concentration is \(0.49 \leq \mu \leq 0.82\) (a) Would a \(99 \%\) CI calculated from the same sample data be longer or shorter? (b) Consider the following statement: There is a \(95 \%\) chance that \(\mu\) is between 0.49 and \(0.82 .\) Is this statement correct? Explain your answer. (c) Consider the following statement: If \(n=100\) random samples of water from the lake were taken and the \(95 \%\) CI on \(\mu\) computed, and this process were repeated 1000 times, 950 of the CIs would contain the true value of \(\mu\). Is this statement correct? Explain your answer.

A random sample of 50 suspension helmets used by motorcycle riders and automobile race-car drivers was subjected to an impact test, and on 18 of these helmets some damage was observed. (a) Find a \(95 \%\) two-sided confidence interval on the true proportion of helmets of this type that would show damage from this test. (b) Using the point estimate of \(p\) obtained from the preliminary sample of 50 helmets, how many helmets must be tested to be \(95 \%\) confident that the error in estimating the true value of \(p\) is less than \(0.02 ?\) (c) How large must the sample be if we wish to be at least \(95 \%\) confident that the error in estimating \(p\) is less than \(0.02,\) regardless of the true value of \(p ?\)

The yield of a chemical process is being studied. From previous experience, yield is known to be normally distributed and \(\sigma=3\). The past five days of plant operation have resulted in the following percent yields: \(91.6,88.75,90.8,89.95,\) and \(91.3 .\) Find a \(95 \%\) two-sided confidence interval on the true mean yield.

The life in hours of a 75 -watt light bulb is known to be normally distributed with \(\sigma=25\) hours. A random sample of 20 bulbs has a mean life of \(\bar{x}=1014\) hours. (a) Construct a \(95 \%\) two-sided confidence interval on the mean life (b) Construct a \(95 \%\) lower-confidence bound on the mean life. Compare the lower bound of this confidence interval with the one in part (a).

A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data: (38.02,61.98) and (39.95,60.05) (a) What is the value of the sample mean? (b) One of these intervals is a \(95 \% \mathrm{CI}\) and the other is a \(90 \%\)

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