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In the layout of a printed circuit board for an electronic product, there are 12 different locations that can accommodate chips. (a) If five different types of chips are to be placed on the board, how many different layouts are possible? (b) If the five chips that are placed on the board are of the same type, how many different layouts are possible?

Short Answer

Expert verified
(a) 95,040 layouts; (b) 792 layouts.

Step by step solution

01

Understanding the Problem - Part A

Firstly, we need to answer part (a), which asks us to find the number of different layouts when 5 different types of chips are placed on 12 positions.
02

Calculating Different Layouts - Part A

For part (a), we are arranging 5 different types of chips in 12 locations. We have 12 choices for the first chip, 11 for the second, and so on up to the fifth chip. This is a permutation problem where the number of permutations of 12 items taken 5 at a time is calculated by:\[P(n, r) = \frac{n!}{(n-r)!}\]where \( n = 12 \) and \( r = 5 \).\[P(12, 5) = \frac{12!}{(12-5)!} = \frac{12!}{7!} = 12 \times 11 \times 10 \times 9 \times 8\]
03

Executing Calculation - Part A

Now, execute the multiplication to get the exact number.\[12 \times 11 \times 10 \times 9 \times 8 = 95040\]Thus, there are 95,040 different layouts possible when arranging 5 different types of chips.
04

Understanding the Problem - Part B

For part (b), we consider 5 chips all of the same type placed on 12 locations. This is now a combination problem where we need to choose 5 out of 12 positions for placing chips of the same type.
05

Calculating Different Layouts - Part B

This is calculated using combinations, given by:\[C(n, r) = \frac{n!}{r!(n-r)!}\]where \( n = 12 \) and \( r = 5 \).\[C(12, 5) = \frac{12!}{5!(12-5)!} = \frac{12!}{5!7!}\]
06

Executing Calculation - Part B

Perform the calculation:\[\frac{12!}{5!7!} = \frac{12 \times 11 \times 10 \times 9 \times 8}{5 \times 4 \times 3 \times 2 \times 1} = 792\]So, there are 792 different layouts possible when placing 5 chips of the same type.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
Permutations are used when you want to arrange items, and the order is important. Consider choosing slots on a circuit board for placing different types of chips. In this scenario, each arrangement of chips matters; placing one chip in a different position results in a new arrangement.

To calculate permutations, the formula is \( P(n, r) = \frac{n!}{(n-r)!} \). Here, \( n \) is the total number of items to choose from, and \( r \) is how many you are arranging. **Factorial**, denoted by an exclamation mark \( n! \), represents the product of all positive integers up to \( n \).

  • For example, let's calculate the number of ways to arrange 5 chips in 12 positions.
  • Using the permutation formula: \( P(12, 5) = \frac{12!}{7!} \).
  • Breaking it down: \( 12 \times 11 \times 10 \times 9 \times 8 \).

This calculation yields 95,040 different ways to arrange the chips, showing the multitude of arrangements possible when order is considered.
Combinations
Combinations differ from permutations because the order in which you choose items does not matter. If you have multiple identical items, combinations are the way to go. Consider arranging five identical chips on a circuit board with 12 available slots. Here, the focus is on which positions are filled, not the order in which they are filled.

The formula for combinations is \( C(n, r) = \frac{n!}{r!(n-r)!} \). This accounts for the total number of ways to choose \( r \) items from \( n \) items, without considering different orders for the same group.

  • To place 5 chips on any 12 positions: \( C(12, 5) = \frac{12!}{5!7!} \).
  • Calculate step-by-step: \( \frac{12 \times 11 \times 10 \times 9 \times 8}{5 \times 4 \times 3 \times 2 \times 1} = 792 \).

So, there are 792 unique ways to choose 5 positions for identical chips, emphasizing that order is not a factor here.
Probability
Probability measures the likelihood of an event happening. Though it wasn't the main focus of the original problem, understanding the concept helps to connect permutations and combinations with real-world scenarios.

Probability is interpreted as a ratio of favorable outcomes over total outcomes. The more likely an event is to occur, the higher its probability value, which ranges from 0 to 1.

Probability often works hand-in-hand with combinatorics to solve questions about random event outcomes, such as selecting certain chips from a batch:
  • You might calculate the probability of picking a specific arrangement or combination from the possible ones computed using permutations or combinations.
  • If selecting from a shuffled set, each choice could represent an outcome, and summing these offers a complete probabilistic picture.

Through understanding these concepts together, students develop skills to solve even more intricate problems in mathematics and beyond.

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Most popular questions from this chapter

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