/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 123 If \(P(A \mid B)=0.3, P(B)=0.8,\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If \(P(A \mid B)=0.3, P(B)=0.8,\) and \(P(A)=0.3,\) are the events \(B\) and the complement of \(A\) independent?

Short Answer

Expert verified
Yes, the events \(B\) and the complement of \(A\) are independent.

Step by step solution

01

Understand the Definition of Independence

Two events are independent if the occurrence of one event does not affect the occurrence of the other. For events \(B\) and \(A^c\) to be independent, it must be that \(P(A^c \mid B) = P(A^c)\). We will check this condition.
02

Find the Probability of the Complement of Event A

The complement of event \(A\), denoted \(A^c\), is such that \(P(A^c) = 1 - P(A)\). Given \(P(A) = 0.3\), we find: \[P(A^c) = 1 - 0.3 = 0.7\].
03

Calculate \(P(A^c \, \cap \, B)\) Using \(P(A \, \cap \, B)\)

We know \(P(A \mid B) = 0.3\) and \(P(B) = 0.8\). Hence, \(P(A \, \cap \, B) = P(A \mid B) \cdot P(B) = 0.3 \times 0.8 = 0.24\). Thus, \(P(A^c \, \cap \, B) = P(B) - P(A \, \cap \, B) = 0.8 - 0.24 = 0.56\).
04

Calculate \(P(A^c \, \mid \, B)\)

To find \(P(A^c \mid B)\), use the formula \(P(A^c \mid B) = \frac{P(A^c \, \cap \, B)}{P(B)}\). Substituting the known values, we get: \[P(A^c \mid B) = \frac{0.56}{0.8} = 0.7\].
05

Compare \(P(A^c \, \mid \, B)\) and \(P(A^c)\)

We have found that \(P(A^c \mid B) = 0.7\) and \(P(A^c) = 0.7\). Since these probabilities are equal, events \(B\) and \(A^c\) are independent.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is all about determining the likelihood of an event occurring, given that another event has already occurred. In simpler terms, it answers the question: 'What is the probability of Event A happening if Event B has definitely happened?'
Let's represent this mathematically with notation: if you want to find the probability of Event A happening given that Event B is true, you write it as \( P(A \mid B) \). This is read as "the probability of A given B."
  • In the given exercise, \( P(A \mid B) = 0.3 \) means there's a 30% chance of Event A happening, knowing that Event B occurs.
  • Conditional probability helps us understand relationships between events and make informed predictions.
  • It's particularly useful in fields like statistics, machine learning, and decision-making.
To calculate conditional probability, we use the formula:\[P(A \mid B) = \frac{P(A \cap B)}{P(B)}\]This formula calculates how likely Event A and Event B occur together, divided by the likelihood of Event B alone.
Independent Events
Independent events are a core concept in probability, describing situations where the occurrence or outcome of one event does not affect another.
To consider two events independent, \( P(A \mid B) = P(A) \) must be true, meaning the probability of A happening remains the same whether or not B has occurred.
  • In the exercise, we are checking if the event \'B\' and the complement of \(A\) are independent.
  • By using the formula \( P(A^c \mid B) = P(A^c) \), we confirm their independence if both probabilities are equal.
  • In scenarios involving multiple decisions or experiments, assuming independence simplifies calculations and predictions.
Understanding whether events are independent helps make judgments on how events interact, especially in complex systems or real-life processes.
Complementary Events
Complementary events are two mutually exclusive events that together encompass all possible outcomes of a particular scenario.
If you sum up the probabilities of an event and its complement, they equal 1.
This can be described mathematically as \(P(A) + P(A^c) = 1\). Here, \(A^c\) is the complement of A.
  • From the exercise, since \( P(A) = 0.3 \), we calculate the complement \(P(A^c)\) as 0.7.
  • Complementary events are often used together with other probability concepts, making it easier to solve complex probability problems.
  • Knowing an event's complement can quickly let you calculate the probability of an event not happening.
By understanding complementary events, problems like the one in the exercise, where independence is checked using complements, become more manageable. Complementary and conditional probabilities often work hand-in-hand due to their logical interplay.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Web ad can be designed from four different colors, three font types, five font sizes, three images, and five text phrases. How many different designs are possible?

In an acid-base titration, a base or acid is gradually added to the other until they have completely neutralized each other. Because acids and bases are usually colorless (as are the water and salt produced in the neutralization reaction), \(\mathrm{pH}\) is measured to monitor the reaction. Suppose that the equivalence point is reached after approximately \(100 \mathrm{~mL}\) of a \(\mathrm{NaOH}\) solution have been added (enough to react with all the acetic acid present) but that replicates are equally likely to indicate from 95 to \(104 \mathrm{~mL}\) to the nearest \(\mathrm{mL}\). Assume that volumes are measured to the nearest \(\mathrm{mL}\) and describe the sample space. (a) What is the probability that equivalence is indicated at \(100 \mathrm{~mL} ?\) (b) What is the probability that equivalence is indicated at less than \(100 \mathrm{~mL} ?\) (c) What is the probability that equivalence is indicated between 98 and \(102 \mathrm{~mL}\) (inclusive)?

If the last digit of a weight measurement is equally likely to be any of the digits 0 through 9 , (a) What is the probability that the last digit is \(0 ?\) (b) What is the probability that the last digit is greater than or equal to \(5 ?\)

If \(A, B,\) and \(C\) are mutually exclusive events, is it possible for \(P(A)=0.3, P(B)=0.4,\) and \(P(C)=0.5 ?\) Why or why not?

If the events \(A\) and \(B\) are independent, show that \(A^{\prime}\) and \(B^{\prime}\) are independent.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.