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91Ó°ÊÓ

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If \(E\) is an event of an experiment, then \(P(E)+P\left(E^{c}\right)=1\).

Short Answer

Expert verified
The statement is true. The rule of complementary events states that the probabilities of an event and its complement must sum up to \(1\). Mathematically, this can be written as \(P(E) + P(E^c) = 1\), where \(E\) is an event of an experiment and \(E^c\) is its complement. Since \(E\) and \(E^c\) cover all the possible outcomes in the sample space, their probabilities must sum up to \(1\).

Step by step solution

01

Understanding Event and its Complement

Let \(E\) be an event of an experiment. Then, we can define its complement, denoted by \(E^c\), as the set of all outcomes in the sample space that are not in \(E\). In other words, when the experiment takes place, either \(E\) occurs or \(E^c\) occurs, but not both simultaneously.
02

Rule of Complementary Events

The probabilities of complementary events sum up to \(1\). In mathematical terms, this can be written as: \[P(E) + P(E^c) = 1\]
03

Explaining the Statement

The given statement states that if \(E\) is an event of an experiment, then \(P(E) + P(E^c) = 1\). This statement is true based on the rule of complementary events, which we stated earlier. Since \(E\) and \(E^c\) cover all the possible outcomes in the sample space (meaning one of them will always occur), their probabilities must sum up to \(1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complementary Events
Complementary events are a fundamental concept in probability theory, describing outcomes that collectively cover all possibilities in an experiment. Any given event, say \(E\), will have a complement, referred to as \(E^c\). This complement \(E^c\) consists of all the possible outcomes that are not part of the event \(E\) itself.

For example, if a dice is rolled, and \(E\) represents the event 'rolling an even number', then \(E^c\) would be 'rolling an odd number'. Such complementary events are mutually exclusive, meaning they cannot occur at the same time.

In any experiment, either one event or its complement will occur, but not both. This relationship highlights their complete coverage of the sample space and is captured mathematically as \(P(E) + P(E^c) = 1\).
Sample Space
Sample space refers to the set of all possible outcomes of a random experiment. Understanding the sample space is crucial for calculating probabilities accurately. Whenever an event occurs, it must be part of this larger collection of outcomes.

Think of the sample space like a bowl holding all the possible results of an experiment, whether it's flipping coins, rolling dice, or drawing cards. In practice, the sample space can be finite or infinite, and each potential outcome of our experiment is a member of this sample space.
  • For a coin toss, the sample space would be \(\{\text{Heads}, \text{Tails}\}\).
  • For a six-sided die, the sample space is \(\{1, 2, 3, 4, 5, 6\}\).
It's important to clearly define the sample space before analyzing any probabilities. Doing so ensures we have included all possible events and their respective complements.
Probability Formula
The probability formula is a key pillar in quantitative reasoning, enabling us to compute the likelihood of different events. When we talk about the probability of an event \(E\), denoted \(P(E)\), we are examining the fraction of the event's favorable outcomes relative to the total number of possible outcomes in the sample space.

The formula is given by: \[P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}\]

When dealing with complementary events, the formula adapts to allow for simpler calculations. Using the complementary rule \(P(E) + P(E^c) = 1\), if you know the probability of one event, you can easily find its complement's probability with \(P(E^c) = 1 - P(E)\). This is particularly useful in cases where calculating \(P(E^c)\) is more straightforward than finding \(P(E)\) directly.

Thus, the probability formula serves as a versatile tool that equips us with necessary insights into possible experiment outcomes.

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Most popular questions from this chapter

List the simple events associated with each experiment. A nickel and a dime are tossed, and the result of heads on tails is recorded for each coin.

In a television game show, the winner is asked to select three prizes from five different prizes, \(A, B\), \(\mathrm{C}, \mathrm{D}\), and \(\mathrm{E} .\) a. Describe a sample space of possible outcomes (order is not important). b. How many points are there in the sample space corresponding to a selection that includes A? c. How many points are there in the sample space corresponding to a selection that includes \(\mathrm{A}\) and \(\mathrm{B}\) ? d. How many points are there in the sample space corresponding to a selection that includes either \(\mathrm{A}\) or \(\mathrm{B}\) ?

According to a survey of 176 retailers, \(46 \%\) of them use electronic tags as protection against shoplifting and employee theft. If one of these retailers is selected at random, what is the probability that he or she uses electronic tags as antitheft devices?

In a Los Angeles Times poll of 1936 California residents conducted in February 2004 , the following question was asked: Do you favor or oppose an amendment to the U.S. Constitution barring same-sex marriage? The following results were obtained: $$ \begin{array}{lccc} \hline \text { Opinion } & \text { Favor } & \text { Oppose } & \text { Don't know } \\ \hline \text { Respondents } & 910 & 891 & 135 \\ \hline \end{array} $$ Determine the empirical probability distribution associated with these data.

In a survey of 200 employees of a company regarding their \(401(\mathrm{k})\) investments, the following data were obtained: 141 had investments in stock funds. 91 had investments in bond funds. 60 had investments in money market funds. 47 had investments in stock funds and bond funds. 36 had investments in stock funds and money market funds. 36 had investments in bond funds and money market funds. 22 had investments in stock funds, bond funds, and money market funds. What is the probability that an employee of the company chosen at random a. Had investments in exactly two kinds of investment funds? b. Had investments in exactly one kind of investment fund? c. Had no investment in any of the three types of funds?

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