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91Ó°ÊÓ

List the simple events associated with each experiment. A nickel and a dime are tossed, and the result of heads on tails is recorded for each coin.

Short Answer

Expert verified
The simple events associated with this experiment are: \( (H, H), (H, T), (T, H),\) and \( (T, T) \).

Step by step solution

01

Identify the possible outcomes for each individual coin

For each coin, there are two possible outcomes: heads (H) and tails (T). So the nickel can either result in H (heads) or T (tails), and the dime can also result in H (heads) or T (tails).
02

Create a sample space of all possible combinations of outcomes for the experiment

Now, we need to find all possible combinations of outcomes between the nickel and the dime. We can represent the outcomes as ordered pairs (N, D) where N represents the outcome for the nickel and D represents the outcome for the dime. There are four possible combinations of outcomes: 1. (H, H): Both the nickel and the dime show heads. 2. (H, T): The nickel shows heads and the dime shows tails. 3. (T, H): The nickel shows tails and the dime shows heads. 4. (T, T): Both the nickel and the dime show tails. So, the simple events associated with this experiment are (H, H), (H, T), (T, H), and (T, T).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Simple Events
Imagine you're flipping a nickel and a dime and recording whether each one lands on heads or tails. In the world of probability, each outcome of this experiment is known as a 'simple event.' A simple event is a single outcome that cannot be broken down into simpler components. In our coin toss scenario, the simple events are the possible outcomes of heads or tails for each coin.

For the nickel, we have either 'heads' (denoted as H) or 'tails' (denoted as T). Similarly, the dime also has these two simple events, H or T. When we list these out per coin, we have not considered one coin's result affecting the other's; we are focused on the individual possibilities. A key takeaway is that simple events are the most basic outcomes on which we build our probability models.
Determining Probability Outcomes
When dealing with probability, 'outcomes' refer to the results of a particular event. In our coin flipping example, we record the result of heads or tails for both a nickel and a dime. Each combination of nickel and dime results is a unique outcome. Since every coin has two sides, there are two possible outcomes for the nickel, and two for the dime.

Using a sample space, we can list all the possible paired outcomes of this two-coin toss as (H, H), (H, T), (T, H), and (T, T). Probability outcomes lay the foundation for predicting the likelihood of various scenarios. Understanding how to enumerate all the potential outcomes is crucial because it informs us of the sample space size, which is directly used to calculate the probability of events occurring.
The Role of Combinatorial Analysis
Combinatorial analysis is a branch of mathematics that deals with counting, arranging, and combination of elements within sets, often to solve problems related to probability and statistics. In our problem, we apply combinatorial analysis to find all possible combinations of the nickel and dime outcomes.

The coin tosses are independent events, meaning the outcome of one coin does not affect the outcome of the other. By calculating the total number of outcomes for one event and multiplying it by the total number of outcomes for the other, we find there are four possible paired outcomes when tossing a nickel and a dime. This multiplication principle is a fundamental concept in combinatorial analysis. It tells us the size of the sample space, which is critical to understanding the probabilities of different events within that space.

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Most popular questions from this chapter

A poll was conducted among 250 residents of a certain city regarding tougher gun-control laws. The results of the poll are shown in the table: $$ \begin{array}{lccccc} \hline & \begin{array}{c} \text { Own } \\ \text { Only a } \\ \text { Handgun } \end{array} & \begin{array}{c} \text { Own } \\ \text { Only a } \\ \text { Rifle } \end{array} & \begin{array}{c} \text { Own a } \\ \text { Handgun } \\ \text { and a Rifle } \end{array} & \begin{array}{c} \text { Own } \\ \text { Neither } \end{array} & \text { Total } \\ \hline \text { Favor } & & & & & \\ \text { Tougher Laws } & 0 & 12 & 0 & 138 & 150 \\ \hline \begin{array}{l} \text { Oppose } \\ \text { Tougher Laws } \end{array} & 58 & 5 & 25 & 0 & 88 \\ \hline \text { No } & & & & & \\ \text { Opinion } & 0 & 0 & 0 & 12 & 12 \\ \hline \text { Total } & 58 & 17 & 25 & 150 & 250 \\ \hline \end{array} $$ If one of the participants in this poll is selected at random, what is the probability that he or she a. Favors tougher gun-control laws? b. Owns a handgun? c. Owns a handgun but not a rifle? d. Favors tougher gun-control laws and does not own a handgun?

The arrival times of the 8 a.m. Bostonbased commuter train as observed in the suburban town of Sharon over 120 weekdays is summarized below: $$ \begin{array}{lc} \hline & \begin{array}{c} \text { Frequency of } \\ \text { Arrival Time, } \boldsymbol{x} \end{array} & \text { Occurrence } \\ \hline 7: 56 \text { a.m. }

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