/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Fifty raffle tickets are numbere... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Fifty raffle tickets are numbered 1 through 50 , and one of them is drawn at random. What is the probability that the number is a multiple of 5 or 7 ? Consider the following "solution": Since 10 tickets bear numbers that are multiples of 5 and since 7 tickets bear numbers that are multiples of 7 , we conclude that the required probability is $$ \frac{10}{50}+\frac{7}{50}=\frac{17}{50} $$ What is wrong with this argument? What is the correct answer?

Short Answer

Expert verified
The given solution incorrectly adds the probabilities without accounting for the double-counting of the number 35, which is a multiple of both 5 and 7. The correct answer can be calculated using the Inclusion-Exclusion principle. There are 10 multiples of 5, 7 multiples of 7, and 1 common multiple (35) in the range of ticket numbers (1 to 50). Therefore, the total number of tickets with numbers that are multiples of 5 or 7 is 16, and the correct probability is \(\frac{16}{50} = \frac{8}{25}\).

Step by step solution

01

Find the multiples of 5 and 7 within 1 to 50

List out all multiples of 5 and 7 in the range of ticket numbers (1 to 50). Multiples of 5: \(5, 10, 15, 20, 25, 30, 35, 40, 45, 50\) (10 numbers) Multiples of 7: \(7, 14, 21, 28, 35, 42, 49\) (7 numbers)
02

Identify common multiples

Find the common multiples of 5 and 7 within the ticket numbers range since these have been counted twice. Common multiples of 5 and 7: \(35\) (1 number)
03

Apply the Inclusion-Exclusion principle

To compute the total number of tickets with numbers that are multiples of 5 or 7, subtract the number of common multiples from the sum of multiples of 5 and multiples of 7 to avoid double-counting: Total = Multiples of 5 + Multiples of 7 - Common multiples Total = 10 + 7 - 1 = 16
04

Compute the probability

Now, we can calculate the probability by dividing the total number of tickets with numbers that are multiples of 5 or 7 by the total number of tickets: Probability = \(\frac{16}{50} = \frac{8}{25}\) So, the correct answer is the probability \(= \frac{8}{25}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inclusion-Exclusion Principle
In the world of probability and counting, the Inclusion-Exclusion Principle is a powerful tool. This principle helps us correctly count the number of elements in the union of multiple sets, by taking into account overlaps where elements might be double-counted.

When counting items such as raffle tickets with numbers that are multiples of 5 or 7, the principle becomes essential. Initially, you might think to simply add together the numbers of multiples of 5 and 7. However, this approach includes a common error: overcounting items present in both groups.

The critical insight provided by the Inclusion-Exclusion Principle is to subtract these common items that are counted twice. In our example, the number 35 is a multiple of both 5 and 7. If not correctly accounted for, it leads to an incorrect total, which further affects the probability calculation. Hence, the correct number of elements is the sum of different multiples, minus the overlap.
Multiples
Multiples are integers that can be divided by a specific number without leaving a remainder. In practical terms, they are the results of multiplying that number by integers. For instance, multiples of 5 are 5, 10, 15, and so on.

In our problem, we are focused on raffle tickets numbered 1 through 50. We need to calculate how many of these numbers are multiples of either 5 or 7. Finding these numbers is relatively straightforward:
  • For 5: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 (10 numbers)
  • For 7: 7, 14, 21, 28, 35, 42, 49 (7 numbers)
Notice that 35 appears in both lists because it is a multiple of both 5 and 7.
Counting Problem
A Counting Problem involves determining how many elements satisfy certain conditions from a finite set. It's a fundamental part of probability and combinatorics. In our raffle ticket example, we face a classic counting problem: identifying tickets that are either multiples of 5 or 7.

Initially, it seems simple to count achievements in separate group totals. However, complications arise due to shared elements (common multiples). The problem-solving challenge lies in correctly categorizing and counting these shared elements only once.

Our solution involves systematically listing the multiples and correctly applying the Inclusion-Exclusion Principle to ensure each element is counted the appropriate number of times. This careful counting avoids common pitfalls like overcounting shared elements.
Mathematics
Mathematics forms the foundation for solving complex counting and probability problems. It provides the tools and principles that allow us to handle seemingly simple problems accurately.

In this exercise, mathematical reasoning brings us from a straightforward observation to a precise solution. By understanding multiples, employing combinatorial techniques like the Inclusion-Exclusion Principle, and wielding probability, we navigate from data misinterpretations to a clear answer.

Mathematics, in this context, is not just about numbers but understanding the relations and structures between them. It encourages a mindset of checking every assumption, verifying results, and ensuring each calculation leads to a meaningful conclusion. Through tools like latex and logical structuring, mathematics becomes a language of clarity and precision.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In an online survey of 500 adults living with children under the age of \(18 \mathrm{yr}\), the participants were asked how many days per week they cook at home. The results of the survey are summarized below: $$ \begin{array}{lcccccccc} \hline \text { Number of Days } & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline \text { Respondents } & 25 & 30 & 45 & 75 & 55 & 100 & 85 & 85 \\ \hline \end{array} $$ Determine the empirical probability distribution associated with these data.

In a poll conducted among likely voters by Zogby International, voters were asked their opinion on the best alternative to oil and coal. The results are as follows: $$ \begin{array}{lcccccc} \hline & & & \text { Fuel } & & \text { Other/ } \\ \text { Source } & \text { Nuclear } & \text { Wind } & \text { cells } & \text { Biofuels } & \text { Solar } & \text { no answer } \\ \hline \text { Respondents, } \% & 14.2 & 16.0 & 3.8 & 24.3 & 27.9 & 13.8 \\ \hline \end{array} $$ What is the probability that a randomly selected participant in the poll mentioned a. Wind or solar energy sources as the best alternative to oil and coal? b. Nuclear or biofuels as the best alternative to oil and coal?

The customer service department of Universal Instruments, manufacturer of the Galaxy home computer, conducted a survey among customers who had returned their purchase registration cards. Purchasers of its deluxe model home computer were asked to report the length of time \((t)\) in days before service was required. a. Describe a sample space corresponding to this survey. b. Describe the event \(E\) that a home computer required service before a period of 90 days had elapsed. c. Describe the event \(F\) that a home computer did not require service before a period of 1 yr had elapsed.

In a survey conducted in 2007 of 1402 workers 18 yr and older regarding their opinion on retirement benefits, the following data were obtained: 827 said that it was better to have excellent retirement benefits with a lower-than-expected salary, 477 said that it was better to have a higher-than-expected salary with poor retirement benefits, 42 said "neither," and 56 said "not sure." If a worker in the survey is selected at random, what is the probability that he or she answered that it was better to have a. Excellent retirement benefits with a lower-than-expected salary? b. A higher-than-expected salary with poor retirement benefits?

Let \(S=\left\\{s_{1}, s_{2}, s_{3}, s_{4}, s_{5}\right\\}\) be the sample space associated with an experiment having the following probability distribution: $$ \begin{array}{lccccc} \hline \text { Outcome } & s_{1} & s_{2} & s_{3} & s_{4} & s_{5} \\ \hline \text { Probability } & \frac{1}{14} & \frac{3}{14} & \frac{6}{14} & \frac{2}{14} & \frac{2}{14} \\ \hline \end{array} $$ Find the probability of the event: a. \(A=\left\\{s_{1}, s_{2}, s_{4}\right\\}\) b. \(B=\left\\{s_{1}, s_{5}\right\\}\) c. \(C=S\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.