/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 A group of five students studyin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A group of five students studying for a bar exam has formed a study group. Each member of the group will be responsible for preparing a study outline for one of five courses. In how many different ways can the five courses be assigned to the members of the group?

Short Answer

Expert verified
The number of ways the five courses can be assigned to the members of the group is 120. This can be calculated using the permutation formula P(5,5) = \(\frac{5!}{(5-5)!}\) = \(\frac{120}{1}\) = 120.

Step by step solution

01

Understand the factorial function

The factorial function, often denoted by an exclamation mark (n! for a positive integer n), is the product of all positive integers less than or equal to n. For example, 3! = 3*2*1 = 6.
02

Use the permutation formula

In a permutation problem, we are interested in the number of ways to arrange objects in a specific order. The general formula for the number of permutations of n objects taken r at a time is: P(n,r) = n! / (n-r)! In our case, we have 5 students (n = 5) and each student will be assigned one of the 5 courses (r = 5). So, the number of permutations of 5 objects taken 5 at a time is: P(5,5) = 5! / (5-5)!
03

Calculate the factorial

Now we need to calculate the factorial for the values 5 and 0. For 5!: 5! = 5 * 4 * 3 * 2 * 1 = 120 For 0!: By definition, 0! = 1
04

Compute the permutations

Now, we can plug in the factorial values into the permutation formula: P(5,5) = 5! / (5-5)! P(5,5) = 120 / 1 So, there are 120 different ways the courses can be assigned to the students.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorial Function
The factorial function plays a central role in combinatorics and permutations. It is represented by an exclamation point and provides a way to calculate the product of an integer and all the integers below it, down to one. For instance, the factorial of 4, denoted as \(4!\), can be calculated as \(4 \times 3 \times 2 \times 1 = 24\).

An interesting and important aspect of factorial is that the factorial of zero \(0!\) is defined to be 1. This might seem counterintuitive at first, but it is essential for many mathematical formulas, including those related to permutations and combinations.

Understanding how the factorial function grows is also important—the value of factorial increases exponentially with larger numbers, which implies that the number of ways to arrange items grows rapidly as the number of items increases.
Combinatorics
Combinatorics is the branch of mathematics focused on counting, both as an abstract concept and in concrete settings. It's the math of collecting, combining, and arranging objects. Within combinatorics, we find the concept of permutations—where we're interested in the order of arrangement—and combinations, where order does not matter.

In the study group problem, we are specifically dealing with a permutation problem. To effectively solve these problems, knowledge of factorial function, as previously described, is essential. The permutation formula involves factorials and helps in determining the number of possible arrangements, where order is important.

The understanding of combinatorics extends to many areas such as probability theory, algebra, and geometry, making it a powerful tool in solving various mathematical and practical problems.
Arrangement of Objects
The arrangement of objects refers to the different ways in which a set of items can be ordered or organized. Each unique sequence is counted as a distinct arrangement. In permutations, each arrangement is sensitive to the order of objects; swapping two items creates a new permutation.

For example, if we have three books A, B, and C, they can be arranged in \(3! = 6\) different ways: ABC, ACB, BAC, BCA, CAB, and CBA. When we have to assign unique items to unique places or roles, such as assigning courses to students, each distinct permutation accounts for a different possible outcome.

An exercise involving the arrangement of objects, like the study group scenario, can enhance comprehension by utilizing practical examples. A useful exercise improvement tip is to encourage students to visualize the problem, perhaps by lining up objects or using illustrations to represent the items being arranged. This visual aid can make the concept more tangible and enhance understanding.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A time study was conducted by the production manager of Universal Instruments to determine how much time it took an assembly worker to complete a certain task during the assembly of its Galaxy home computers. Results of the study indicated that \(20 \%\) of the workers were able to complete the task in less than \(3 \mathrm{~min}, 60 \%\) of the workers were able to complete the task in 4 min or less, and \(10 \%\) of the workers required more than 5 min to complete the task. If an assembly-line worker is selected at random from this group, what is the probability that a. He or she will be able to complete the task in 5 min or less? b. He or she will not be able to complete the task within 4 min? c. The time taken for the worker to complete the task will be between 3 and 4 min (inclusive)?

A leading manufacturer of kitchen appliances advertised its products in two magazines: Good Housekeeping and the Ladies Home Journal. A survey of 500 customers revealed that 140 learned of its products from Good Housekeeping, 130 learned of its products from the Ladies Home Journal, and 80 learned of its products from both magazines. What is the probability that a person selected at random from this group saw the manufacturer's advertisement in a. Both magazines? b. At least one of the two magazines? c. Exactly one magazine?

In an online survey of 1962 executives from 64 countries conducted by Korn/Ferry International between August and October 2006 , the executives were asked if they would try to influence their children's career choices. Their replies: A (to a very great extent), \(\mathrm{B}\) (to a great extent), \(\mathrm{C}\) (to some extent), D (to a small extent), and \(\mathrm{E}\) (not at all) are recorded below: $$ \begin{array}{lccccc} \hline \text { Answer } & \text { A } & \text { B } & \text { C } & \text { D } & \text { E } \\ \hline \text { Respondents } & 135 & 404 & 1057 & 211 & 155 \\ \hline \end{array} $$ What is the probability that a randomly selected respondent's answer was \(\mathrm{D}\) (to a small extent) or \(\mathrm{E}\) (not at all)?

If a ball is selected at random from an urn containing three red balls, two white balls, and five blue balls, what is the probability that it will be a white ball?

A certain airport hotel operates a shuttle bus service between the hotel and the airport. The maximum capacity of a bus is 20 passengers. On alternate trips of the shuttle bus over a period of \(1 \mathrm{wk}\), the hotel manager kept a record of the number of passengers arriving at the hotel in each bus. a. What is an appropriate sample space for this experiment? b. Describe the event \(E\) that a shuttle bus carried fewer than ten passengers. c. Describe the event \(F\) that a shuttle bus arrived with a full load.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.