/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Let \(S=\\{a, b, c, d, e, f\\}\)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(S=\\{a, b, c, d, e, f\\}\) be a sample space of an experiment and let \(E=\\{a, b\\}, F=\\{a, d, f\\}\), and \(G=\\{b, c, e\\}\) be events of this experiment. Find the events \(F \cup G\) and \(F \cap G\).

Short Answer

Expert verified
The union of events \(F\) and \(G\) is \(F \cup G = \{a, b, c, d, e, f\}\), and the intersection of events \(F\) and \(G\) is \(F \cap G = \emptyset\).

Step by step solution

01

Write down the given information

We are given that the sample space \(S = \{a, b, c, d, e, f\}\), and the events \(E = \{a, b\}\), \(F = \{a, d, f\}\), and \(G = \{b, c, e\}\).
02

Find the union of events F and G, denoted F ∪ G

To find the union of events \(F\) and \(G\), we combine all the unique outcomes of each event, i.e., all outcomes that belong to either \(F\) or \(G\). This can be written as: \[F \cup G = \{a, d, f\} \cup \{b, c, e\}\] Next, we list all the unique outcomes of \(F\) and \(G\): \[F \cup G = \{a, b, c, d, e, f\}\]
03

Find the intersection of events F and G, denoted F ∩ G

To find the intersection of events \(F\) and \(G\), we look for the outcomes that belong to both \(F\) and \(G\). This can be written as: \[F \cap G = \{a, d, f\} \cap \{b, c, e\}\] Since there are no common elements in the two sets, the intersection of \(F\) and \(G\) is an empty set: \[F \cap G = \emptyset\]
04

Write down the final answer

The union of events \(F\) and \(G\) is: \[F \cup G = \{a, b, c, d, e, f\}\] The intersection of events \(F\) and \(G\) is: \[F \cap G = \emptyset\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Space
In the world of probability, a **sample space** is the set of all possible outcomes of an experiment. It is a fundamental concept as it lays the groundwork for studying events and their probabilities. In our exercise, the sample space is represented as:
  • \(S = \{a, b, c, d, e, f\}\)
This means that when you perform the experiment, the outcome will be one of these elements. Each element in this set is considered an outcome. When experimenting, every possible result must appear in the sample space.

For clarity, think about rolling a die. The sample space would be \(\{1, 2, 3, 4, 5, 6\}\), representing all possible numbers that could land on top. Similarly, our sample space \(S\) relates to an experiment that could result in the outcomes \(a, b, c, d, e,\) or \(f\). A well-defined sample space ensures that we correctly analyze and understand different possible events within an experiment.
Union of Events
The **union of events** refers to the combination of two or more events in a way that includes all outcomes that belong to either event. In probabilistic terms, if you want to know the probability of either event 'A' or event 'B' occurring, you use the union of those events, denoted as \(A \cup B\). In our problem, the events \(F\) and \(G\) are given as:
  • \(F = \{a, d, f\}\)
  • \(G = \{b, c, e\}\)
To find the union \(F \cup G\), we simply merge all unique elements from both sets:
  • \(F \cup G = \{a, d, f\} \cup \{b, c, e\}\)
  • \(F \cup G = \{a, b, c, d, e, f\}\)
The result is a set that includes every outcome from both \(F\) and \(G\). This makes sense because the combination of these events allows for any result that occurs in \(F\), \(G\), or both. This approach helps us understand the occurrence of any one of the events without considering overlaps since, in unions, we treat duplicates as one entry in the resulting set.
Intersection of Events
An **intersection of events** captures outcomes that two sets have in common. When looking to calculate the intersection of events, you're interested in occurrences that are both in event 'A' and event 'B'. The intersection is symbolically denoted as \(A \cap B\). In our specific example, we have:
  • \(F = \{a, d, f\}\)
  • \(G = \{b, c, e\}\)
To discover the intersection \(F \cap G\), we identify common elements:\[F \cap G = \{a, d, f\} \cap \{b, c, e\}\]After comparing the elements in both sets, we find:\[F \cap G = \emptyset\]This indicates that there are no elements common to both sets \(F\) and \(G\), resulting in an empty set for their intersection. Understanding intersections helps us determine the probability of two events occurring simultaneously, which can be critical, particularly in complex probability scenarios where joint occurrence matters.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(S=\left\\{s_{1}, s_{2}, s_{3}, s_{4}, s_{5}, s_{6}\right\\}\) be the sample space associated with an experiment having the probability distribution shown in the accompanying table. If \(A=\left\\{s_{1}, s_{2}\right\\}\) and \(B=\left\\{s_{1}, s_{5}, s_{6}\right\\}\), find a. \(P(A), P(B)\) b. \(P\left(A^{c}\right), P\left(B^{c}\right)\) c. \(P(A \cap B)\) d. \(P(A \cup B)\) e. \(P\left(A^{c} \cap B^{c}\right)\) f. \(P\left(A^{c} \cup B^{c}\right)\) $$ \begin{array}{cc} \hline \text { Outcome } & \text { Probability } \\ \hline s_{1} & \frac{1}{3} \\ \hline s_{2} & \frac{1}{8} \\ \hline s_{3} & \frac{1}{6} \\ \hline s_{4} & \frac{1}{6} \\ \hline s_{5} & \frac{1}{12} \\ \hline s_{6} & \frac{1}{8} \\ \hline \end{array} $$

A certain airport hotel operates a shuttle bus service between the hotel and the airport. The maximum capacity of a bus is 20 passengers. On alternate trips of the shuttle bus over a period of \(1 \mathrm{wk}\), the hotel manager kept a record of the number of passengers arriving at the hotel in each bus. a. What is an appropriate sample space for this experiment? b. Describe the event \(E\) that a shuttle bus carried fewer than ten passengers. c. Describe the event \(F\) that a shuttle bus arrived with a full load.

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If \(E\) is an event of an experiment, then \(P(E)+P\left(E^{c}\right)=1\).

In a survey conducted in the fall 2006, 800 homeowners were asked about their expectations regarding the value of their home in the next few years; the results of the survey are summarized below: $$ \begin{array}{lc} \hline \text { Expectations } & \text { Homeowners } \\ \hline \text { Decrease } & 48 \\ \hline \text { Stay the same } & 152 \\ \hline \text { Increase less than } 5 \% & 232 \\ \hline \text { Increase 5-10\% } & 240 \\ \hline \text { Increase more than 10\% } & 128 \\ \hline \end{array} $$ If a homeowner in the survey is chosen at random, what is the probability that he or she expected his or her home to a. Stay the same or decrease in value in the next few years? b. Increase \(5 \%\) or more in value in the next few years?

In a Los Angeles Times poll of 1936 California residents conducted in February 2004 , the following question was asked: Do you favor or oppose an amendment to the U.S. Constitution barring same-sex marriage? The following results were obtained: $$ \begin{array}{lccc} \hline \text { Opinion } & \text { Favor } & \text { Oppose } & \text { Don't know } \\ \hline \text { Respondents } & 910 & 891 & 135 \\ \hline \end{array} $$ Determine the empirical probability distribution associated with these data.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.