/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Find an equation of the line tha... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find an equation of the line that passes through the point \((1,-2)\) and is perpendicular to the line passing through the points \((-2,-1)\) and \((4,3)\)

Short Answer

Expert verified
The equation of the line passing through the point \((1, -2)\) and perpendicular to the line passing through the points \((-2, -1)\) and \((4,3)\) is \(y + 2 = -\frac{3}{2}(x - 1)\).

Step by step solution

01

Calculate the slope of the line passing through the points \((-2,-1)\) and \((4,3)\)

To find the slope (m) of the line, we can use the formula: \[m=\frac{y2-y1}{x2-x1}\] Let point \(A (-2,-1)\) have coordinates \((x1, y1)\) and point \(B (4,3)\) have coordinates \((x2, y2).\) Substitute the given coordinates to find the slope: \[m = \frac{3-(-1)}{4-(-2)}\]
02

Calculate the negative reciprocal of the slope

Calculate the value of \(m\): \[m = \frac{3+1}{4+2} = \frac{4}{6} = \frac{2}{3}\] Now, we need to find the negative reciprocal of the slope \(m\). The negative reciprocal of \(\frac{2}{3}\) is \(-\frac{3}{2}\).
03

Use the point-slope form of the line equation to find the equation of the line

Now that we have the slope \(m' = -\frac{3}{2}\) of the line we want to find and a point \((1, -2)\) on that line, we can use the point-slope form of the line equation: \[(y-y1) = m'(x-x1)\] Substitute the values of the slope and the coordinates of the given point: \[(y-(-2)) = -\frac{3}{2}(x-1)\] Simplify the equation to get the equation of the perpendicular line: \[y + 2 = -\frac{3}{2}(x-1)\] You can rewrite the equation in slope-intercept form, or you can leave it in point-slope form. The final equation of the line is: \[y + 2 = -\frac{3}{2}(x - 1) \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equations of Lines
In analytic geometry, an equation of a line can represent the infinite points that form a straight line on a plane. There are different forms of line equations, but they all serve the same purpose of describing the relationship between the x and y coordinates of points on that line. Common forms include:

• **Slope-Intercept Form:** \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. This form is very useful for easily identifying the slope and y-intercept.
• **Point-Slope Form:** \((y - y_1) = m(x - x_1)\), where \(m\) is the slope and \((x_1, y_1)\) is a point on the line.

By learning different equations of a line, we can easily switch the form based on what information we know about the line. This flexibility is crucial for solving a wide range of geometry problems.
Perpendicular Lines
Perpendicular lines are two lines that intersect at a right angle (90 degrees). In the context of a coordinate plane, their slopes share a special relationship. If you know the slope of one line, the slope of a line perpendicular to it is the negative reciprocal. For example, if a line has a slope of \(\frac{2}{3}\), the slope of any line perpendicular to it will be \(-\frac{3}{2}\).

This relationship is essential when tasks require finding new lines, such as drawing a perpendicular line through a given point or solving more complex geometric problems. Understanding the behavior of perpendicular lines helps in maintaining the orthogonal integrity of many structures and shapes within analytical geometry.
Point-Slope Form
The point-slope form of a line equation is particularly useful when you know the slope of a line, as well as one point it passes through. The formula is expressed as \((y - y_1) = m(x - x_1)\), where \(m\) is the slope and \((x_1, y_1)\) is a known point on the line.

To use this form, substitute the known slope and coordinates into the formula. For example, if the slope is \(-\frac{3}{2}\) and the point is \((1, -2)\), the equation becomes \((y + 2) = -\frac{3}{2}(x - 1)\). This form directly associates the change in y with the change in x, making it easy to calculate additional points or rearrange into another form, such as slope-intercept form.
Slope Calculation
Slope represents the steepness and direction of a line. It is calculated using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\), where \((x_1, y_1)\) and \((x_2, y_2)\) are coordinates of two distinct points on the line.

To find the slope:
  • Subtract the y-value of the first point from the y-value of the second point.
  • Do the same subtraction for the x-values.
  • Divide the y-difference by the x-difference.
For example, given the points \((-2, -1)\) and \((4, 3)\), the slope is calculated as \(\frac{3 - (-1)}{4 - (-2)} = \frac{4}{6} = \frac{2}{3}\). This process helps us describe the line's direction and angle, essential for any analysis involving line equations and properties on a coordinate plane.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Patricia wishes to have a rectangularshaped garden in her backyard. She has \(80 \mathrm{ft}\) of fencing with which to enclose her garden. Letting \(x\) denote the width of the garden, find a function \(f\) in the variable \(x\) giving the area of the garden. What is its domain?

SuppLY Functions The supply function for the Luminar desk lamp is given by $$ p=0.1 x^{2}+0.5 x+15 $$ where \(x\) is the quantity supplied (in thousands) and \(p\) is the unit price in dollars. Sketch the graph of the supply function. What unit price will induce the supplier to make 5000 lamps available in the marketplace?

According to the World Wildlife Fund, a group in the forefront of the fight against illegal ivory trade, the price of ivory (in dollars/kilo) compiled from a variety of legal and black market sources is approximated by the function $$ f(t)=\left\\{\begin{array}{ll} 8.37 t+7.44 & \text { if } 0 \leq t \leq 8 \\ 2.84 t+51.68 & \text { if } 8

The estimated monthly profit realizable by the Cannon Precision Instruments Corporation for manufacturing and selling \(x\) units of its model \(\mathrm{M} 1\) cameras is $$ P(x)=-0.04 x^{2}+240 x-10,000 $$ dollars. Determine how many cameras Cannon should produce per month in order to maximize its profits.

Following the introduction in 1950 of the nation's first credit card, the Diners Club Card, credit cards have proliferated over the years. More than 720 different cards are now used at more than 4 million locations in the United States. The average U.S. credit card debt (per household) in thousands of dollars is approximately given by $$ D(t)=\left\\{\begin{array}{ll} 4.77(1+t)^{0.2676} & \text { if } 0 \leq t \leq 2 \\ 5.6423 t^{0.1818} & \text { if } 2

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.