/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Evaluate \(h(2)\), where \(h=g \... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate \(h(2)\), where \(h=g \circ f\). \(f(x)=\sqrt[3]{x^{2}-1} ; g(x)=3 x^{3}+1\)

Short Answer

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\(h(2) = 10\)

Step by step solution

01

Understand function composition

Function composition is a way to combine two functions into a single function. The composition of functions \(g\) and \(f\), denoted as \(g \circ f\), is defined as follows: \((g \circ f)(x) = g(f(x))\) This means that you first evaluate the function \(f(x)\) and then use the result as the input for the function \(g(x)\).
02

Find the composition of the given functions

We are given two functions and need to find their composition, \(g \circ f\). We know that: \((g \circ f)(x) = g(f(x))\) We've been given the definitions of both functions: \(f(x) = \sqrt[3]{x^2 - 1}\) and \(g(x) = 3x^3 + 1\) Thus, the composition of these functions is: \((g \circ f)(x) = g(f(x)) = g(\sqrt[3]{x^2 - 1})\) Now, we need to substitute the expression for \(f(x)\) into the function \(g(x)\): \((g \circ f)(x) = 3(\sqrt[3]{x^2 - 1})^3 + 1\)
03

Evaluate h(2)

We are asked to find the value of \(h(2)\), where \(h = g \circ f\). Using the expression for \(g \circ f\) from Step 2, we have: \(h(2) = (g \circ f)(2) = 3(\sqrt[3]{2^2 - 1})^3 + 1\) To calculate the value of \(h(2)\), we first evaluate the expression inside the cube root: \(\sqrt[3]{2^2 - 1} = \sqrt[3]{4 - 1} = \sqrt[3]{3}\) Now, we can evaluate the whole expression: \(h(2) = 3(\sqrt[3]{3})^3 + 1\) Since \((\sqrt[3]{3})^3 = 3\), we get: \(h(2) = 3(3) + 1\) Finally, we can calculate the value of \(h(2)\): \(h(2) = 9 + 1 = 10\) So, \(h(2) = 10\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Functions
Mathematical functions are fundamental building blocks in mathematics, providing a process or rule that relates a set of inputs to a single output from another set. In simpler terms, think of a function as a machine that takes an input, processes it, and gives an output. The notation of a function typically appears as:
  • \( f(x) \): Indicates a function named \( f \) with \( x \) as the input variable.
  • The output is determined by substituting \( x \) into the expression defined by \( f \).
Functions have wide applications in various fields and can handle numbers, shapes, and even other functions as inputs or outputs. For instance, in solving problems involving motion, electricity, and growth rates, functions help in modeling these situations.
By understanding roles like linear, quadratic, and exponential functions, one can analyze real-world phenomena effectively. However, today, let's delve into a more specific type related to our exercise: the cube root function.
Cube Root Functions
Cube root functions are a category of mathematical functions that involve finding a number which, when multiplied by itself three times (cubed), equals the original input. The general form of a cube root function can be expressed as \( f(x) = \sqrt[3]{x} \). What distinguishes cube root functions is their defined ability to handle both positive and negative numbers.
In an expression like \( \sqrt[3]{x^2 - 1} \), the cube root essentially attempts to "undo" the cubing process to retrieve a base number.
  • Cube roots are symbolized by \( \sqrt[3]{ } \), suggesting a third-degree process.
  • They accommodate inputs that may result in negative or imaginary values when involving squares and other operations, although in this example, it remains real.
Cube roots are often used in equations to determine volumes, solve polynomial equations, and model certain natural growth processes. Understanding how cube roots operate is essential for tackling higher-degree polynomial problems and appreciating the nature of cubic curves in graphing scenarios.
Function Evaluation
Function evaluation involves determining the output of a function for a specific input. It's the practice of substituting a particular value into the function's formula to find the result. In the exercise provided, we evaluated \( h(2) \), where \( h \) is the composition of two functions \( g \circ f \). The process of evaluating functions can be straightforward or complex, depending on the function's nature.
Here's how you can approach function evaluation:
  • Identify the function's definition and substitute the input value into the variable.
  • Follow the order of operations: start with operations inside parenthesis, and then proceed with exponents, multiplication/division, and finally addition/subtraction.
  • For complex functions involving compositions like \( g(f(x)) \), evaluate the internal function \( f(x) \) first, and then apply the result to \( g(x) \).
Properly evaluating functions is critical as it serves not just in mathematical exercises but also in real-world computations, such as calculating profit, determining speed, or predicting trends in data analytics. These evaluations allow us to understand and predict outcomes based on mathematical modeling.

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Most popular questions from this chapter

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