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Let \(A\) be a set with \(|A|=n\). Determine (a) \(\left|A^{3}\right|\) (b) \(\mid\\{(a, b, c) \mid a, b, c \in A\) and each coordinate is different \(\\} \mid\)

Short Answer

Expert verified
(a) \(|A^3| = n^3\); (b) \(n(n-1)(n-2)\).

Step by step solution

01

Understand the problem

We are given a set \(A\) with \(|A| = n\). We need to find the size of two different mathematical sets derived from \(A\). The first is the Cartesian product \(A^3\), and the second includes ordered triples \((a, b, c)\) where each element is unique.
02

Calculate \(\left|A^3\right|\)

The Cartesian product \(A^3\) consists of triples \((a, b, c)\) where each of \(a, b,\) and \(c\) comes from the set \(A\). Since each of the three indices (\(a, b, c\)) can independently take any of \(n\) elements, we have \(n \times n \times n = n^3\). Thus, \(\left|A^3\right| = n^3\).
03

Define the condition for unique coordinates

For part (b), we are interested in tuples where the elements \((a, b, c)\) are distinct. This means that each of the indices must represent different elements of the set \(A\).
04

Calculate \(\mid\{ (a, b, c) \mid a, b, c \in A\) and each coordinate is different\}\mid\)

Choose \(a\) first, which can be any of the \(n\) elements in \(A\). Choose \(b\), which must be different from \(a\), so there are \(n-1\) choices. Finally, choose \(c\), which must be different from both \(a\) and \(b\), leaving \(n-2\) choices. Therefore, the total number of such triples is \(n(n-1)(n-2)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Set Theory
In mathematics, set theory is a fundamental concept that deals with collections of objects. A "set" is simply a collection of distinct objects, considered as an object in its own right. These objects can be anything: numbers, letters, or even other sets.
\( \mid A \mid = n \) denotes the cardinality of set \( A \), meaning that there are \( n \) elements within the set. This basic idea lays the groundwork for more complex structures like Cartesian products and ordered tuples, which we explore in other sections. By understanding set theory, we gain insights into how mathematical collections are structured and how they interact with each other.
A significant topic within set theory is the idea of a power set, which includes all possible subsets of a set, including the empty set and the set itself. However, when dealing with Cartesian products, we are more concerned with combinations and arrangements of set elements as explained in upcoming sections.
Ordered Triples
Ordered triples are sequences of three elements, often represented as \( (a, b, c) \), where each element comes from a predetermined set. Unlike sets, ordered triples actually consider the sequence in which these elements appear. This means that \( (a, b, c) \) is not the same as \( (b, a, c) \), highlighting the importance of order in these structures.
The Cartesian product \( A^3 \) refers to a set which contains all possible ordered triples formed by taking elements from the set \( A \). If \( A \) contains \( n \) elements, then \( A^3 \,=\, A \times A \times A \), resulting in a total of \( n^3 \) unique ordered triples. This is because each element \( a, b, \) and \( c \) in the ordered triple can independently take any of the \( n \) elements from the set \( A \), leading to a multiplication of possibilities.
Ordered triples are especially useful in scenarios where it is necessary to maintain the sequence of items, such as in computing and databases.
Distinct Elements
The concept of distinct elements in a set or sequence emphasizes that no two elements are identical. In the context of ordered triples, "distinct elements" means that each component of the triple \( (a, b, c) \) must be different from the others.
For example, to form a triple with distinct elements when \( A \) has \( n \) elements, you start by picking the first element \( a \) from the entire set \( A \). This gives you \( n \) choices. Once \( a \) is chosen, \( b \) must be selected differently, leaving \( n-1 \) choices. Similarly, \( c \) has to be chosen from the remaining elements, resulting in \( n-2 \) options. Hence, the total number of ordered triples with distinct elements is \( n(n-1)(n-2) \).
Understanding distinct elements is crucial in many applications, such as generating permutations or designing experiment setups where repetition is not allowed for validity of results.

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