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How many eight-letter words can be formed from the 26 letters in the alphabet? Even without concerning ourselves about whether the words make sense, there are two interpretations of this problem. Answer both.

Short Answer

Expert verified
With repetition: \(26^8\). Without repetition: \(26 \times 25 \times 24 \times 23 \times 22 \times 21 \times 20 \times 19\).

Step by step solution

01

Understanding the first interpretation

In the first interpretation, we assume that each letter of the word can be any of the 26 letters from the alphabet, and letters can be repeated. This means for each of the 8 positions in the word, we have 26 choices.
02

Calculating total permutations with repetition

Since each position in the 8-letter word can be filled with any of the 26 letters, the total number of different words is calculated as follows: \[ 26^8 \] Calculate this by raising 26 to the power of 8 to get the total number of permutations.
03

Understanding the second interpretation

In the second interpretation, we assume that no letter repeats in the 8-letter word. Each letter chosen from the alphabet is not replaced, meaning the number of available letters decreases by 1 with each step.
04

Calculating permutations without repetition

For the first letter, there are 26 choices. For the second letter, there are 25 choices, then 24 for the third, and so on, until 19 choices for the eighth letter. The total number of different words is:\[ 26 imes 25 imes 24 imes 23 imes 22 imes 21 imes 20 imes 19 \] Calculate this product to find the number of words possible without repetition.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutations
Permutations play a crucial role in combinatorics, helping us determine different ways to arrange a set of items. For example, imagine needing to arrange a bunch of books on a shelf. If you care about the order in which these books are arranged, you're looking at permutations.
In permutations, every item has a distinct place, and the order is significant. In our exercise, the problem gives us an eight-letter word derived from the 26 letters of the alphabet. When we talk about permutations without repetition, each letter is used once; that's why, as letters are placed, fewer options remain for the following spots.
Remember, with permutations, we're specifically interested in where and how things are lined up in sequence, making it different from combinations, where order doesn't usually matter.
Repetition in permutations
Repetition in permutations refers to scenarios where each item in a set can appear more than once when forming arrangements. This is like having infinite copies of each item. It's a common situation in tasks involving letters, numbers, and other alike items where you can re-use the elements freely.
In our exercise's first interpretation, forming an eight-letter word allows each letter to be any one of the 26 alphabet letters repeatedly. So, for each spot, you constantly have 26 choices, leading to a massive number of permutations. This formula can be mathematically expressed as:
\[ 26^8 \]This equation is derived from multiplying 26 (choices per position) by itself for each of the eight positions available. It shows just how large the total permutations can become when repetition is allowed.
Counting principles
Counting principles are essential in tackling complex problems by breaking them into manageable parts. Two such principles often used in combinatorics are the multiplication principle and the addition principle.
For permutations, especially as seen in our exercise, the multiplication principle is invaluable. It states that if you have a process with several independent steps, the total number of outcomes is the product of the number of choices at each step. That's what we applied in both interpretations of the problem:
  • With repetition: Each of the 8 positions offers 26 independent choices, resulting in \(26^8\) possible arrangements.
  • Without repetition: Each choice successively reduces by one as letters are removed from future options, calculated by multiplying a descending sequence from 26 to 19.
Understanding and applying these counting principles enable clearer and more efficient problem-solving in combinatorial mathematics.

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Most popular questions from this chapter

A builder of modular homes would like to impress his potential customers with the variety of styles of his houses. For each house there are blueprints for three different living rooms, four different bedroom configurations, and two different garage styles. In addition, the outside can be finished in cedar shingles or brick. How many different houses can be designed from these plans?

(a) How many ways can a gardener plant five different species of shrubs in a circle? (b) What is the answer if two of the shrubs are the same? (c) What is the answer if all the shrubs are identical?

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