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Determine whether each differential equation is separable. (Do not solve it, just find whether it's separable.) $$y^{\prime}=x+y$$

Short Answer

Expert verified
The differential equation \( y' = x + y \) is not separable.

Step by step solution

01

Understanding Separable Differential Equations

A differential equation is considered separable if it can be expressed in the form \( N(y) \frac{dy}{dx} = M(x) \), where \( N(y)\) is a function of \( y\) alone and \( M(x)\) is a function of \( x\) alone. This allows the equation to be separated into two integrals: one with respect to \( y\) and the other with respect to \( x\).
02

Analyze the Given Differential Equation

The differential equation given is \( y' = x + y \). We need to check if we can rearrange this equation in the form \( N(y) \frac{dy}{dx} = M(x) \).
03

Find a Way to Rearrange the Equation

Rewriting the given equation, \( y' = x + y \), as \( \frac{dy}{dx} = x + y \), it becomes clear that this equation contains both \( x \) and \( y \) terms on the right-hand side. To be separable, we should isolate \( \frac{dy}{dx} \) multiplied by a function of \( y \) only equal to a function of \( x \) only.
04

Attempt Separation

Let's try to rearrange: \( \frac{dy}{dx} = x + y \) into a separable form. Subtract \( y \) from both sides: \( \frac{dy}{dx} - y = x \). This equation cannot be expressed solely as a product of a function of \( y \) and a function of \( x \), as there is no clear method to separate the variables \( y \) and \( x\).
05

Conclusion on Separability

Since we cannot rearrange \( y' = x + y \) into a form where only functions of \( y \) and \( x \) are separate, the differential equation is not separable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separation of Variables
Understanding the concept of separation of variables is crucial when dealing with differential equations. This technique involves rewriting a differential equation so that each variable and its differential can be isolated on separate sides of the equation. The goal is to rearrange the equation into a format where one side depends solely on the variable \( x \) (and its differential \( dx \)), and the other on the variable \( y \) (and its differential \( dy \)).When successfully separated, solving the equation typically involves integrating both sides: one equation with respect to \( x \) and the other with respect to \( y \). While this may sound straightforward, the challenge lies in rearranging the original equation to reach this desired form.Here are key steps to apply separation of variables:
  • Identify terms in the differential equation to be associated with each variable.
  • Rearrange the equation, ensuring that each side depends on only one variable.
  • If rearrangement is possible, solve by integrating each side separately.
By following these steps, you can determine if a differential equation is separable and proceed to solve it accordingly.
Differential Equations Analysis
To analyze a differential equation, like \( y' = x + y \), for separability, we need to inspect the structure and form of the equation. Analysis involves determining whether or not the equation can be manipulated to separate \( y \) and \( x \) into two distinct sides.During the analysis, the equation is typically rearranged into \( \frac{dy}{dx} \), equating it to an expression involving both \( x \) and \( y \). This provides insight into whether variables are intertwined or if they can be isolated.Here's how you can analyze a differential equation:
  • Convert to \( \frac{dy}{dx} \) form to identify the involved functions.
  • Check if both variables can appear on opposite sides of the equation.
  • If impossible to separate, the equation is deemed non-separable.
This process aids in understanding the underlying structure and behavior of the equation, and if it's amenable to the separation of variables method.
Separable Equations Form
The form of a separable equation is specific and follows the convention \( N(y) \frac{dy}{dx} = M(x) \). Here, \( N(y) \) is a function involving only \( y \), while \( M(x) \) is a function involving only \( x \). This characteristic form is what allows us to "separate" the equation.In practice, an equation must be carefully rearranged or sometimes transformed to emerge into this separable form. If this configuration is achieved, each variable can be integrated independently of the other, providing a pathway to solve the equation.Considerations for determining if an equation is in separable form include:
  • Inspect if the equation can be factorized or rearranged into \( N(y) \cdot dy = M(x) \cdot dx \).
  • Look for transformations that may help achieve a separable structure.
  • Verify if only one variable and its differential appear on each side of the equation after manipulation.
Being able to identify this form is crucial and saves valuable time when working with differential equations.

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Most popular questions from this chapter

Your company has developed a new product, and your marketing department has predicted how it will sell. Let \(y(t)\) be the (monthly) sales of the product after \(t\) months. a. Write a differential equation that says that the rate of growth of the sales will be six times the twothirds power of the sales. b. Write an initial condition that says that at time \(t=0\) sales were 1000 c. Solve this differential equation and initial value. d. Use your solution to predict the sales at time \(t=12\) months.

The following are differential equations stated in words. Find the general solution of each. The derivative of a function at each point is itself.

The following are differential equations stated in words. Find the general solution of each. The derivative of a function at each point is 6 .

Solve each differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition. $$\left\\{\begin{array}{l} y^{\prime}=\sqrt{y} e^{x}-\sqrt{y} \\ y(0)=1 \end{array}\right.$$

For each initial value problem: a. Use an Euler's method graphing calculator program to find the estimate for \(y(2)\). Use the interval [0,2] with \(n=50\) segments. b. Solve the differential equation and initial condition exactly by separating variables or using an integrating factor. c. Evaluate the solution that you found in part (b) at \(x=2\). Compare this actual value of \(y(2)\) with the estimate of \(y(2)\) that you found in part (a). $$ \begin{array}{l} y^{\prime}=-x y \\ y(0)=1 \end{array} $$

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