/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 The following are differential e... [FREE SOLUTION] | 91Ó°ÊÓ

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The following are differential equations stated in words. Find the general solution of each. The derivative of a function at each point is itself.

Short Answer

Expert verified
The general solution is \( y = Ae^x \), where \( A \) is a constant.

Step by step solution

01

Translate the Words into a Mathematical Equation

The problem states that the derivative of a function at each point is itself. In mathematical terms, this means if the function is denoted by \( y \), then \( \frac{dy}{dx} = y \). This is a first-order differential equation.
02

Recognize the Type of Differential Equation

The differential equation \( \frac{dy}{dx} = y \) is a first-order, separable differential equation. Identifying the type is crucial for determining the appropriate method to solve it.
03

Separate Variables

To solve \( \frac{dy}{dx} = y \), we can rearrange the terms to separate the variables. Thus, we rewrite it as \( \frac{1}{y} \, dy = dx \). This allows us to integrate both sides independently.
04

Integrate Both Sides

Integrate the left side with respect to \( y \), and the right side with respect to \( x \):\[ \int \frac{1}{y} \, dy = \int dx \]The integral results in:\( \ln |y| = x + C \), where \( C \) is the constant of integration.
05

Solve for y

To solve for \( y \), we exponentiate both sides to obtain:\[ |y| = e^{(x + C)} \]This simplifies to:\( y = \pm e^C e^x \)We can denote \( A = \pm e^C \) (where \( A \) is a new constant), giving the solution:\( y = Ae^x \).
06

Express the General Solution

Thus, the general solution to the differential equation \( \frac{dy}{dx} = y \) is \( y = Ae^x \), where \( A \) is any constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

General Solution
The general solution of a differential equation is an expression that includes all possible solutions of the equation. In these equations, especially in a first-order ordinary differential equation like the one we are considering, the general solution typically includes a constant that can be any real number. This constant is included because when we solve a differential equation by integration, we add a constant of integration. In this context, for the equation \( \frac{dy}{dx} = y \), the general solution is expressed as:
  • \( y = Ae^x \)
Here, \( A \) represents the constant, allowing for a family of solutions that satisfy the differential equation based on different initial conditions. Understanding the concept of the general solution is crucial because it informs us of all possible outcomes that satisfy the given differential equation.
Separable Differential Equation
A separable differential equation is a specific type of differential equation where the variables can be separated on opposite sides of the equation. This means you can rearrange terms so that all terms containing one variable and its differential are on one side of the equation and all terms containing the other variable and its differential are on the other side.
For the given problem, the equation \( \frac{dy}{dx} = y \) can be rewritten into a separable form by moving all terms involving \( y \) to one side and all terms involving \( x \) to the other side. This results in the expression:
  • \( \frac{1}{y} \, dy = dx \)
Solving separable differential equations involves integrating both sides independently. This step is possible because once we separate the variables, the equation is effectively simplified into a product of separate integrals, which leads directly into the next crucial phase: integration.
Integration
Integration is a fundamental concept in calculus and an essential step in solving differential equations, particularly when dealing with separable differential equations. It involves finding the antiderivative of a function, which essentially reverses the process of differentiation.
For a separable differential equation like \( \frac{1}{y} \, dy = dx \), the integration process involves integrating each side:
  • \( \int \frac{1}{y} \, dy = \int dx \)
The result of these integrations will lead us to:
\( \ln |y| = x + C \), where \( C \) is the constant of integration. To find \( y \), we exponentiate both sides:
\( |y| = e^{x+C} \), which simplifies further to:
  • \( y = Ae^x \)
Here \( A = \pm e^C \), introducing a constant that reflects the indefinite nature of integration and covering all potential solutions to our original differential equation. Understanding how to integrate each side of an equation independently is crucial for solving separable differential equations.

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Most popular questions from this chapter

You deposit \(\$ 8000\) into a bank account paying \(5 \%\) interest compounded continuously, and you withdraw funds continuously at the rate of \(\$ 1000\) per year. Therefore, the amount \(y(t)\) in the account after \(t\) years satisfies $$ \begin{aligned} y^{\prime} &=0.05 y-1000 \\ y(0) &=8000 \end{aligned} $$ a. Solve this differential equation and initial value. b. Graph your solution on a graphing calculator and find how long it will take until the account is empty.

A medical examiner called to the scene of a murder will usually take the temperature of the body. A corpse cools at a rate proportional to the difference between its temperature and the temperature of the room. If \(y(t)\) is the temperature (in degrees Fahrenheit) of the body \(t\) hours after the murder, and if the room temperature is \(70^{\circ},\) then \(y\) satisfies $$ \begin{aligned} y^{\prime} &=-0.32(y-70) \\ y(0) &=98.6 \text { (body temperature initially } \left.98.6^{\circ}\right) \end{aligned}$$ a. Solve this differential equation and initial condition. b. Use your answer to part (a) to estimate how long ago the murder took place if the temperature of the \text { body when it was discovered was } 80^{\circ} .

For each initial value problem, calculate the Euler approximation for the solution on the interval [0,1] using \(n=4\) segments. Draw the graph of your approximation. (Carry out the calculations "by hand" with the aid of a calculator, rounding to two decimal places. Answers may differ slightly, depending on when you do the rounding.) $$ \begin{array}{l} y^{\prime}+2 y=e^{4 x} \\ y(0)=2 \end{array} $$

When you swallow a pill, the medication passes through your stomach lining into your bloodstream, where some is absorbed by the cells of your body and the rest continues to circulate for future absorption. The amount \(y(t)\) of medication remaining in the bloodstream after \(t\) hours can be modeled by the differential equation $$ \frac{d y}{d t}=a b e^{-b t}-c y $$ for constants \(a, b,\) and \(c\) (respectively the dosage of the pill, the dissolution constant of the pill, and the absorption constant of the medication). For the given values of the constants: a. Substitute the constants into the stated differential equation. b. Solve the differential equation (with the initial condition of having no medicine in the bloodstream at time \(t=0)\) to find a formula for the amount of medicine in the bloodstream at any time \(t\) (hours). c. Use your solution to find the amount of medicine in the bloodstream at time \(t=2\) hours. d. Graph your solution on a graphing calculator and find when the amount of medication in the bloodstream is maximized. \(a=30 \mathrm{mg}, \quad b=5, \quad c=0.3\)

Solve each differential equation in two ways: first by using an integrating factor, and then by separation of variables. $$ y^{\prime}=y+1 $$

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