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Table 1.43 gives values for \(g(t),\) a periodic function. (a) Estimate the period and amplitude for this function. (b) Estimate \(g(34)\) and \(g(60)\). Table 1.43 $$\begin{array}{|c|c|c|c|c|c|c|c|c|}\hline t & 0 & 2 & 4 & 6 & 8 & 10 & 12 & 14 \\\\\hline g(t) & 14 & 19 & 17 & 15 & 13 & 11 & 14 & 19 \\\\\hline t & 16 & 18 & 20 & 22 & 24 & 26 & 28 & \\\\\hline g(t) & 17 & 15 & 13 & 11 & 14 & 19 & 17 \\\\\hline\end{array}$$

Short Answer

Expert verified
Period: 12, Amplitude: 4, \(g(34) = 11\), \(g(60) = 14\).

Step by step solution

01

Determine the Period

The period of a periodic function is the length of the interval over which the function repeats itself. In Table 1.43, observe the values of \(g(t)\). Note that at \(t = 0\), \(g(t) = 14\) and this value repeats at \(t = 12\). Therefore, the period \(T\) is 12 units.
02

Determine the Amplitude

The amplitude of a periodic function is half the distance between its maximum and minimum values. From the table, the maximum value of \(g(t)\) is 19 and the minimum value is 11. The amplitude \(A\) is calculated as \(A = \frac{19 - 11}{2} = 4\).
03

Estimate g(34)

Since the period is 12, we can use the equivalence \(g(34) = g(34 \mod 12) = g(10)\). From the table, \(g(10) = 11\). Thus, \(g(34) = 11\).
04

Estimate g(60)

Similarly, using the period, \(g(60) = g(60 \mod 12) = g(0)\). From the table, \(g(0) = 14\). Therefore, \(g(60) = 14\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Period Estimation
A periodic function is one that repeats its values at regular intervals or periods. The period is one of the key characteristics of such functions. When estimating the period of a function given in tabular form, we look for the interval over which the function values repeat.

In our example:
  • At time point \(t = 0\), the function \(g(t)\) equals 14.
  • This value repeats itself at \(t = 12\).
Therefore, the full cycle occurs every 12 units of time, meaning the period \(T\) is 12.

The period is essential because it allows us to make predictions about the values of the function at points outside the given data range. We can extend the function infinitely in both directions using this known period, making periodic functions incredibly useful in practical scenarios, such as predicting tides or seasons.
Amplitude Calculation
The amplitude is a measure of how much a periodic function varies, essentially capturing the height of its peaks and valleys. For many functions, particularly trigonometric ones like sine and cosine, amplitude relates to the energy or intensity of the signal. It gives us an understanding of the function's variability from its average position.

To calculate amplitude:
  • Identify the maximum value of the function; here, \(g(t)\) reaches 19.
  • Find the minimum value, which is 11 in this case.
The amplitude \(A\) then becomes half of the distance between the max and min values: \(A = \frac{19 - 11}{2} = 4\).

This amplitude indicates how deeply the function dips and how high it peaks from its mean position, giving an insight into the range of the periodic signal.
Modular Arithmetic
Modular arithmetic, often thought of as "clock arithmetic," is a system which deals with integer division and finds remainder values. In periodic functions, it helps to find function values outside the immediate cycle by wrapping them around the period.

Here's how it works:
  • If we need to find \(g(34)\): Calculate \(34 \mod 12\), which results in 10, so \(g(34) = g(10) = 11\).
  • For \(g(60)\): Calculate \(60 \mod 12\), giving a remainder 0, thus \(g(60) = g(0) = 14\).
Using the modulo operation helps simplify calculations where the period of the function extends to values not immediately present in our data. It's especially useful in scenarios where periodic behaviors are repeated over time, such as studying cyclical patterns in data analysis or designing periodic signals in engineering.

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Most popular questions from this chapter

A quantity \(P\) is an exponential function of time \(t .\) Use the given information about the function \(P=P_{b} a^{t}\) to: (a) Find values for the parameters \(a\) and \(P_{0}\). (b) State the initial quantity and the percent rate of growth or decay. \(P=320\) when \(t=5\) and \(P=500\) when \(t=3\)

The Bay of Fundy in Canada has the largest tides in the world. The difference between low and high water levels is 15 meters (nearly 50 feet). At a particular point the depth of the water, \(y\) meters, is given as a function of time, \(t,\) in hours since midnight by $$y=D+A \cos (B(t-C))$$ (a) What is the physical meaning of \(D ?\) (b) What is the value of \(A ?\) (c) What is the value of \(B ?\) Assume the time between successive high tides is 12.4 hours. (d) What is the physical meaning of \(C ?\)

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A city's population is 1000 and growing at \(5 \%\) a year. (a) Find a formula for the population at time \(t\) years from now assuming that the \(5 \%\) per year is an: (i) Annual rate (ii) Continuous annual rate (b) In each case in part (a), estimate the population of the city in 10 years.

For Problems \(1-16,\) solve for \(t\) using natural logarithms. $$40=100 e^{-0.03 t}$$

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