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Let \(k_{1}, k_{2}, \ldots, k_{n}\) be a random sample from the geometric probability function $$ p_{X}(k ; p)=(1-p)^{k-1} p, \quad k=1,2, \ldots $$ Find \(\lambda\), the generalized likelihood ratio for testing \(H_{0}: p=\) \(p_{0}\) versus \(H_{1}: p \neq p_{0}\).

Short Answer

Expert verified
The generalized likelihood ratio is given by \(\lambda = \left(\frac{p_0}{\hat{p}}\right)^n \left(\frac{1 - p_0}{1 - \hat{p}}\right)^{\sum_{i=1}^n k_i - n}\), where \(\hat{p}\) is the value that maximizes the likelihood function under \(H_{1}\) and is given by \(\hat{p} = \frac{n}{\sum_{i=1}^n k_i}\).

Step by step solution

01

Definition

The likelihood function under the given geometric distribution with parameters \(k\) and \(p\) is: \[L(k; p) = p(1-p)^{k-1}\] for \(k = 1, 2, ...\). Here \(k\) is the number of trials before the first success.
02

Likelihood Function and Log-Likelihood Function

Now, consider a random sample \(k_{1}, k_{2}, ..., k_{n}\), hence the joint likelihood function is given by: \[L(k_{1}, k_{2}, ..., k_{n}; p) = p^n(1 - p)^{\sum_{i=1}^n (k_i - 1)}\] To simplify the computation, instead of the likelihood function, the log-likelihood function \(l(k_{1}, k_{2}, ..., k_{n}; p)\) is considered: \[l = n \log(p) + (\sum_{i=1}^n k_i - n) \log(1 - p)\]
03

Maximum Log-Likelihood

The parameter value that maximizes the log-likelihood function is obtained by solving the derivative of this function with respect to the parameter \(p\), and setting it to zero: \[l^\prime = \frac{n}{\hat{p}} - \frac{\sum_{i=1}^n k_i - n}{1 - \hat{p}} = 0\] From this equation, we find \(\hat{p}\), which maximizes the log-likelihood function under \(H_{1}\): \[\hat{p} = \frac{n}{\sum_{i=1}^n k_i}\]
04

Generalized Likelihood Ratio

The generalized likelihood ratio \(\lambda\) for testing \(H_{0}: p = p_{0}\) versus \(H_{1}: p ≠ p_{0}\) is given by: \[\lambda = \frac{L(k_{1}, k_{2}, ..., k_{n}; p_0)}{L(k_{1}, k_{2}, ..., k_{n}; \hat{p})} = \left(\frac{p_0}{\hat{p}}\right)^n \left(\frac{1 - p_0}{1 - \hat{p}}\right)^{\sum_{i=1}^n k_i - n}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Probability Function
The geometric probability function describes the number of trials required to achieve the first success in repeated, independent Bernoulli trials, where each trial has the same probability of success, noted as p. This type of probability distribution is useful in modeling scenarios where you're interested in the 'waiting time' until an event occurs.

For example, if you are tossing a fair coin and want to know the probability that the first 'heads' will appear on the third toss, you would use the geometric probability function: \[p_{X}(k; p) = (1-p)^{k-1} p \]where k is the number of trials (in this case, k=3), and p is the probability of getting 'heads' on a single coin toss (for a fair coin, p=0.5). This function tells us that the likelihood of seeing the first 'heads' on the third toss is determined by the chance of not seeing 'heads' in the first two tosses, multiplied by the chance of seeing it on the third one.
Likelihood Function
The likelihood function is a fundamental concept in statistical inference, particularly in the fields of parameter estimation and hypothesis testing. It provides a measure of how likely it is to observe a given set of data under different parameter values of a statistical model.

The likelihood for a set of independent observations is the product of the probability of each observation. For our geometric distribution example, if we have a series of trials leading to the first success, the likelihood of this sequence given a certain value of p is: \[L(k_1, k_2, ..., k_n; p) = p^n(1 - p)^{\sum_{i=1}^n (k_i - 1)} \]The likelihood function thus combines all our single observations and links them with a theoretical model, here being the geometric distribution. This allows us to estimate the unknown parameter p that would make the observed data most likely.
Log-Likelihood Function
Dealing with likelihoods often involves products of many probabilities, which can be computationally intensive and lead to numerical underflow on computers. To tackle this, statisticians use the log-likelihood function, which converts products into sums, making the calculations much simpler and more stable.

Continuing from the likelihood function in the geometric distribution, the log-likelihood transforms the product into a sum: \[l = n \log(p) + (\sum_{i=1}^n k_i - n) \log(1 - p) \]By taking the logarithm, we have greatly simplified the multiplication of probabilities into addition, which also turns exponentiated terms into multipliers. This is particularly useful when we need to find the maximum likelihood estimate (MLE) of our parameter, as the differentiation becomes more straightforward.
Maximum Likelihood Estimation
Maximum Likelihood Estimation (MLE) is a method to estimate the parameters of a statistical model, where the estimated values maximize the likelihood function, meaning they make the observed data as probable as possible.

For our geometric distribution, the MLE of p is found by differentiating the log-likelihood function with respect to p and finding where this derivative is zero: \[\hat{p} = \frac{n}{\sum_{i=1}^n k_i} \]This calculated value \hat{p} is where the log-likelihood reaches its maximum, the peak of the curve so to speak. MLE is widely used due to its simplicity and desirable properties, such as consistency (the estimates converge to the true value as the sample size grows) and asymptotic normality (they become normally distributed as the sample size increases).
Hypothesis Testing in Statistics
Hypothesis testing is a statistical process used to determine if there is enough evidence in a sample of data to infer that a certain condition is true for the entire population. In our context, we might want to test the hypothesis that the probability of success p in a geometric distribution is equal to a specific value p_0 (the null hypothesis H_0), against the alternative H_1 that p is not equal to p_0.

The generalized likelihood ratio, noted as \lambda, is a tool we can use for this testing: \[\lambda = \frac{L(k_1, k_2, ..., k_n; p_0)}{L(k_1, k_2, ..., k_n; \hat{p})} \]The value of \lambda compares the likelihoods of the null and alternative hypotheses. A small value of \lambda indicates that the data is much less likely if the null hypothesis is true compared to the alternative, providing evidence against H_0. Decisions about which hypothesis is supported are typically made using a comparison to a critical value or through a p-value.

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Most popular questions from this chapter

Let \(k\) denote the number of successes observed in a sequence of \(n\) independent Bernoulli trials, where \(p=P\) (success). (a) Show that the critical region of the likelihood ratio test of \(H_{0}: p=\frac{1}{2}\) versus \(H_{1}: p \neq \frac{1}{2}\) can be written in the form \(k \cdot \ln (k)+(n-k) \cdot \ln (n-k) \geq \lambda^{* *}\) (b) Use the symmetry of the graph of $$ f(k)=k \cdot \ln (k)+(n-k) \cdot \ln (n-k) $$ to show that the critical region can be written in the form $$ \left|\bar{k}-\frac{1}{2}\right| \geq c $$ where \(c\) is a constant determined by \(\alpha\).

If \(H_{0}: \mu=30\) is tested against \(H_{1}: \mu>30\) using \(n=16\) observations (normally distributed) and if \(1-\beta=0.85\) when \(\mu=34\), what does \(\alpha\) equal? Assume that \(\sigma=9\).

A series of \(n\) Bernoulli trials is to be observed as data for testing $$ \begin{gathered} H_{0}: p=\frac{1}{2} \\ \text { versus } \\ H_{1}: p>\frac{1}{2} \end{gathered} $$ The null hypothesis will be rejected if \(k\), the observed number of successes, equals \(n\). For what value of \(p\) will the probability of committing a Type II error equal \(0.05 ?\)

Will \(n=45\) be a sufficiently large sample to test \(H_{0}: \mu=10\) versus \(H_{1}: \mu \neq 10\) at the \(\alpha=0.05\) level of significance if the experimenter wants the Type II error probability to be no greater than \(0.20\) when \(\mu=12 ?\) Assume that \(\sigma=4\).

As input for a new inflation model, economists predicted that the average cost of a hypothetical "food basket" in east Tennessee in July would be \( 145.75\). The standard deviation \((\sigma)\) of basket prices was assumed to be \( 9.50\), a figure that has held fairly constant over the years. To check their prediction, a sample of twenty-five baskets representing different parts of the region were checked in late July, and the average cost was \(\$ 149.75 .\) Let \(\alpha=0.05 .\) Is the difference between the economists' prediction and the sample mean statistically significant?

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