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Let \(X\) be a noetherian scheme, and let \(\mathscr{F}\) be a coherent sheaf. (a) If the stalk \(\mathscr{F}_{x}\) is a free \(\mathscr{C}_{x}\) -module for some point \(x \in X,\) then there is a neighborhood \(U\) of \(x\) such that \(\left.\mathscr{F}\right|_{v}\) is free. (b) \(\mathscr{F}\) is locally free if and only if its stalks \(\mathscr{F}_{x}\) are free \(\mathscr{O}_{x}\) -modules for all \(x \in X\) (c) \(\mathscr{F}\) is invertible (i.e., locally free of rank 1 ) if and only if there is a coherent sheaf \(\mathscr{G}\) such that \(\mathscr{F} \otimes \mathscr{G} \cong \mathscr{O}_{X} .\) (This justifies the terminology invertible: it means that \(\mathscr{F}\) is an invertible element of the monoid of coherent sheaves under the operation \(\otimes .\)

Short Answer

Expert verified
1. If a stalk is free, in a noetherian neighborhood, it implies that the whole sheaf is free in the neighborhood. \n2. A sheaf is locally free if and only if its stalks are free. \n3. A sheaf is invertible, or locally free of rank 1, if and only if it has a tensor product with another sheaf that is isomorphic to the structure sheaf.

Step by step solution

01

- Understanding and proving the first statement

First, let's focus on the first statement that says 'If the stalk \(\mathscr{F}_{x}\) is a free \(\mathscr{C}_{x}\) -module for some point \(x \in X,\) then there is a neighborhood \(U\) of \(x\) such that \(\left.\mathscr{F}\right|_{v}\) is free'. \nOne point to note is that any free module over a ring is projective. As \(\mathscr{F}_{x}\) is a free \(\mathscr{C}_{x}\) -module for some point \(x \in X\), we know that \(\mathscr{F}_{x}\) is projective. Since \(X\) is noetherian, either by Serre's criterion or by Hopkin's theorem, the coherent module \(\mathscr{F}_{x}\) is free. Therefore, there is a neighborhood \(U\) of \(x\) such that \(\left.\mathscr{F}\right|_{v}\) is free.
02

- Understanding and proving the second statement

Now, let's look at the second statement '\(\mathscr{F}\) is locally free if and only if its stalks \(\mathscr{F}_{x}\) are free \(\mathscr{O}_{x}\) -modules for all \(x \in X\)'. A sheaf is said to be locally free of rank n if in a neighborhood around every point, it is isomorphic to the direct sum of n copies of the structure sheaf. Therefore, the stalk at a point \(x\) of a sheaf that is locally free of rank n will be free \(\mathscr{O}_{x}\) -module of rank n. Conversely, if all the stalks are free, then the sheaf is locally free.
03

- Understanding and proving the third statement

Finally, let's prove the last statement '\(\mathscr{F}\) is invertible (i.e., locally free of rank 1 ) if and only if there is a coherent sheaf \(\mathscr{G}\) such that $\mathscr{F} \otimes \mathscr{G} \cong \mathscr{O}_{X} .$'. If $\mathscr{F} \otimes \mathscr{G} \cong \mathscr{O}_{X} .$, then \(\mathscr{F}\) is locally free of rank 1 because a sheaf is invertible if it locally free of rank 1. Conversely, if \(\mathscr{F}\) is an invertible element of the monoid of coherent sheaves under the operation \(\otimes\), then there exists a coherent sheaf \(\mathscr{G}\) such that $\mathscr{F} \otimes \mathscr{G} \cong \mathscr{O}_{X}$.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coherent Sheaf
A coherent sheaf is one of the foundational concepts in algebraic geometry, providing a bridge between the geometric and algebraic worlds. Imagine that you're observing a patchwork quilt. Each patch can be thought of as an open subset of your shape, and the stitching together of these patches is akin to the local behavior of functions. In the context of a Noetherian scheme, which is essentially a space that satisfies a certain finiteness condition, a coherent sheaf embodies this locally stitched structure of algebraic sections.

More formally, a sheaf \( \mathscr{F} \) on a scheme \( X \) is called coherent if it is both of finite type and locally presentable. This means the sheaf looks 'simple' enough near any point, allowing us to approximate it by algebraic equations with finitely many terms. This condition on the sheaf ensures that its properties are manageable and similar to those of finite-dimensional vector spaces, despite sheaf theory being a vast ocean where the geometric configuration of our space meets the algebraic study of functions.

  • Homogeneity: Near each point in the scheme, the sections of the sheaf are generated by a finite set of elements.
  • Persistence: These generators give rise to homomorphisms that locally behave like polynomial equations, hence are locally solvable.
An essential property of coherent sheaves on Noetherian schemes is that their stalk at each point is a finitely generated module over the local ring. This allows for a beautiful connection to be drawn between the local and global properties of the sheaf, simplifying the complex undertaking of understanding the underlying geometry.
Locally Free Sheaf
To grasp the concept of a locally free sheaf, picture yourself wearing a knitted sweater. The sweater stretches and conforms to your shape. In a similar fashion, a locally free sheaf on a scheme adapts to the local structure of the space it inhabits, like a perfectly tailored garment. It represents a central notion in algebraic geometry, tying closely to the idea of vector bundles in topology.

A sheaf \( \mathscr{F} \) is locally free on a scheme if, around any point, you can find an open neighborhood where the sheaf behaves exactly like several copies of the structure sheaf stacked together. This flexibility means the sheaf doesn't just mimic the structure sheaf in isolation; it does so in a coordinated fashion across the entire neighborhood, with each 'layer' or 'copy' being synchronized.

Internally, this means the sections over that neighborhood form a free module, possessing a basis that allows linear combinations to be taken, akin to how vectors behave in a vector space. This property is incredibly valuable because locally free sheaves are easier to work with, mirroring the simplicity and familiarity that come with working with vector spaces.

Take for instance, a sheaf \( \mathscr{F} \) on a Noetherian scheme \( X \). If at a point \( x \), the stalk \( \mathscr{F}_x \) is free over the local ring \( \mathscr{O}_x \) – meaning we have a basis and can freely form linear combinations – then it indicates that the sheaf is locally free in the vicinity of \( x \). Locally free sheaves are pivotal as they often correspond to vector bundles on the scheme and offer us a deep insight into the geometric structure inherent within the algebraic framework.
Free Module
The concept of a free module can be likened to a toolkit filled with standard, uncoupled tools; each tool can be used independently to build or fix something. In algebra, a free module provides an analogous toolkit for building algebraic structures. It's the algebraist's sandbox, providing a set of independent 'tools' that can be used to construct more complex algebraic entities.

A free module over a ring is essentially a module with a basis, similar to how a vector space over a field has a basis. This implies that every element in the module can be uniquely expressed as a linear combination of basis elements. The coefficients come from the ring, and the basis elements provide the structure and framework needed for construction.

  • Convenience: A module being free is tremendously convenient, mainly because it mirrors our understanding of vector spaces, making it easier to navigate algebraic problems.
  • Flexibility: Free modules allow for an element-wise construction, giving us the freedom to tailor complex algebraic structures 'element' by 'element' (pun intended!).
In the context of Noetherian schemes and coherent sheaves, the notion of free modules is central. If the stalk of a coherent sheaf at a point is a free module, then we have a level of algebraic tractability that can typically be extended to a neighborhood around the point. This links back to the notion that free modules, like a well-organized toolkit, allow for the local construction and examination of the algebraic object (in this case, the sheaf) in a structured and systematic way, leading to a comprehensive understanding of both its algebraic and geometric properties.

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Most popular questions from this chapter

Flasque Sheares. A sheaf \(\bar{y}\) on a topological space \(X\) is flasque if for every inclusion \(V \subseteq U\) of open sets, the restriction \(\operatorname{map} \mathscr{F}(U) \rightarrow \mathscr{F}(V)\) is surjective. (a) Show that a constant sheaf on an irreducible topological space is flasque. See (I, 81 ) for irreducible topological spaces. (b) If \(0 \rightarrow \overline{\mathscr{H}} \rightarrow \mathscr{F} \rightarrow \mathscr{H}^{\prime \prime} \rightarrow 0\) is an exact sequence of sheaves, and if \(\bar{y}\) is flasque, then for any open set \(U\). the sequence \(0 \rightarrow \mathscr{F}^{\prime}(U) \rightarrow \mathscr{F}(U) \rightarrow\) \(\mathscr{F}^{\prime \prime}\left(L^{\prime}\right) \rightarrow 0\) of abelian groups is also exact. (c) If \(0 \rightarrow \mathscr{H} \rightarrow \mathscr{H} \rightarrow \mathscr{H}^{\prime \prime} \rightarrow 0\) is an exact sequence of sheaves, and if \(\mathscr{H}^{\prime}\) and \(\overline{\mathscr{H}}\) are flasque, then \(\mathscr{F}^{\prime \prime}\) is flasque. (d) If \(f: X \rightarrow Y\) is a continuous map, and if \(\mathscr{F}\) is a flasque sheaf on \(X\), then \(f_{*} \overline{\mathscr{H}}\) is a flasque sheaf on \(Y\) (e) Let \(\overline{\mathscr{F}}\) be any sheaf on \(X\). We define a new sheaf \(\mathscr{G}\), called the sheaf of discontinuous sections of \(\mathscr{F}\) as follows. For each open set \(U \subseteq X, \mathscr{G}(U)\) is the set of

Closed Subschemes. (a) Closed immersions are stable under base extension: if \(f: Y \rightarrow X\) is a closed immersion, and if \(X^{\prime} \rightarrow X\) is any morphism, then \(f^{\prime}: Y \times_{X} X^{\prime} \rightarrow X^{\prime}\) is also a closed immersion. (b) If \(Y\) is a closed subscheme of an affine scheme \(X=\operatorname{Spec} A\), then \(Y\) is also affine, and in fact \(Y\) is the closed subscheme determined by a suitable ideal \(\mathfrak{a} \subseteq A\) as the image of the closed immersion \(\operatorname{Spec} A / \mathfrak{a} \rightarrow \operatorname{Spec} A\). [Hints: First show that \(Y\) can be covered by a finite number of open affine subsets of the form \(D\left(f_{i}\right) \cap Y,\) with \(f_{i} \in A .\) By adding some more \(f_{i}\) with \(D\left(f_{i}\right) \cap Y=\varnothing\) if necessary, show that we may assume that the \(D\left(f_{i}\right)\) cover \(X .\) Next show that \(f_{1}, \ldots, f_{r}\) generate the unit ideal of \(A .\) Then use (Ex. 2.17 b) to show that \(Y\) is affine, and (Ex. \(2.18 \mathrm{d}\) ) to show that \(Y\) comes from an ideal \(\mathfrak{a} \subseteq\) A. .] Note: We will give another proof of this result using sheaves of ideals later (5.10). (c) Let \(Y\) be a closed subset of a scheme \(X\), and give \(Y\) the reduced induced subscheme structure. If \(Y^{\prime}\) is any other closed subscheme of \(X\) with the same underlying topological space, show that the closed immersion \(Y \rightarrow X\) factors through \(Y^{\prime} .\) We express this property by saying that the reduced induced structure is the smallest subscheme structure on a closed subset. (d) Let \(f: Z \rightarrow X\) be a morphism. Then there is a unique closed subscheme \(Y\) of \(X\) with the following property: the morphism \(f\) factors through \(Y\), and if \(Y^{\prime}\) is any other closed subscheme of \(X\) through which \(f\) factors, then \(Y \rightarrow X\) factors through \(Y^{\prime}\) also. We call \(Y\) the scheme-theoretic image of \(f\). If \(Z\) is a reduced scheme, then \(Y\) is just the reduced induced structure on the closure of the image \(f(Z)\)

Extending a Sheaf by Zero. Let \(X\) be a topological space, let \(Z\) be a closed subset. let \(i: Z \rightarrow X\) be the inclusion, let \(U=X-Z\) be the complementary open subset and let \(j: U \rightarrow X\) be its inclusion. (a) Let \(\mathscr{J}\) be a sheaf on \(Z\). Show that the stalk \(\left(i_{*}, \overline{\mathscr{H}}\right)_{p}\) of the direct image sheaf on \(X\) is \(\mathscr{F}_{P}\) if \(P \in Z, 0\) if \(P \notin Z\). Hence we call \(i_{*}\). \(\bar{y}\) the sheaf obtained by extending of \(i_{*} \overline{\mathscr{H}},\) and say "consider \(\mathscr{F}\) as a sheaf on \(X\)," when we mean "consider \(i_{*}\). (b) Now let \(\overline{\mathscr{H}}\) be a sheaf on \(U\). Let \(j\), \((\overrightarrow{\mathscr{H}})\) be the sheaf on \(X\) associated to the presheaf \(V \mapsto \mathscr{F}(V)\) if \(V \subseteq U, V \mapsto 0\) otherwise. Show that the stalk \((j,(\mathscr{F}))_{P}\) is equal to \(\overline{\mathscr{I}}_{p}\) if \(P \in U, 0\) if \(P \notin U\), and show that \(j\), \(\overline{\mathscr{H}}\) is the only sheafon \(X\) which has this property, and whose restriction to \(U\) is \(\mathscr{F}\). We call \(j\). F. Fhe sheaf obtained by extending \(\mathscr{F}\) by zero outside \(U\) (c) Now let \(\mathscr{F}\) be a sheaf on \(X\). Show that there is an exact sequence of sheaves on \(X\) $$0 \rightarrow j \cdot\left(\left.\overline{\mathscr{H}}\right|_{c}\right) \rightarrow \overline{\mathscr{H}} \rightarrow i_{*}\left(\left.\mathscr{F}\right|_{Z}\right) \rightarrow 0$$

Zariski Spaces. A topological space \(X\) is a Zariski space if it is noetherian and every (nonempty) closed irreducible subset has a unique generic point (Ex. 2.9 ). For example, let \(R\) be a discrete valuation ring, and let \(T=\operatorname{sp}(\operatorname{Spec} R)\). Then \(T\) consists of two points \(t_{0}=\) the maximal ideal, \(t_{1}=\) the zero ideal. The open subsets are \(\varnothing,\left\\{t_{1}\right\\},\) and \(T .\) This is an irreducible Zariski space with generic point \(t_{1}\). (a) Show that if \(X\) is a noetherian scheme, then \(\operatorname{sp}(X)\) is a Zariski space. (b) Show that any minimal nonempty closed subset of a Zariski space consists of one point. We call these closed points. (c) Show that a Zariski space \(X\) satisfies the axiom \(T_{0}\) : given any two distinct points of \(X\), there is an open set containing one but not the other (d) If \(X\) is an irreducible Zariski space, then its generic point is contained in every nonempty open subset of \(X\) (e) If \(x_{0}, x_{1}\) are points of a topological space \(X,\) and if \(x_{0} \in\left\\{x_{1}\right\\}^{-},\) then we say that \(x_{1}\) specializes to \(x_{0},\) written \(x_{1} \leadsto \rightarrow x_{0} .\) We also say \(x_{0}\) is a specialization of \(x_{1},\) or that \(x_{1}\) is a generization of \(x_{0} .\) Now let \(X\) be a Zariski space. Show that the minimal points, for the partial ordering determined by \(x_{1}>x_{0}\) if \(x_{1} \leadsto x\) \(x_{0},\) are the closed points, and the maximal points are the generic points of the irreducible components of \(X .\) Show also that a closed subset contains every specialization of any of its points. (We say closed subsets are stable under specialization. . Similarly, open subsets are stable under generization. (f) Let \(t\) be the functor on topological spaces introduced in the proof of (2.6) If \(X\) is a noetherian topological space, show that \(t(X)\) is a Zariski space. Furthermore \(X\) itself is a Zariski space if and only if the \(\operatorname{map} \alpha: X \rightarrow t(X)\) is a homeomorphism.

Let \(X\) be a scheme of finite type over a field \(k\) (not necessarily algebraically closed). (a) Show that the following three conditions are equivalent (in which case we say that \(X\) is geometrically irreducible). (i) \(X \times_{k} \bar{k}\) is irreducible, where \(\bar{k}\) denotes the algebraic closure of \(k .\) abuse of notation, we write \(X \times_{k} \bar{k}\) to denote \(X \times_{\text {spec } k}\) Spec \(\bar{k} .\) (ii) \(X \times_{k} k_{s}\) is irreducible, where \(k_{s}\) denotes the separable closure of \(k\) (iii) \(X \times_{k} K\) is irreducible for every extension field \(K\) of \(k\) (b) Show that the following three conditions are equivalent (in which case we say \(X\) is geometrically reduced) (i) \(X \times_{k} \bar{k}\) is reduced. (ii) \(X \times_{k} k_{p}\) is reduced, where \(k_{p}\) denotes the perfect closure of \(k\) (iii) \(X \times_{k} K\) is reduced for all extension fields \(K\) of \(k\) (c) We say that \(X\) is geometrically integral if \(X \times_{k} \bar{k}\) is integral. Give examples of integral schemes which are neither geometrically irreducible nor geometrically reduced.

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