/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Zariski Spaces. A topological sp... [FREE SOLUTION] | 91Ó°ÊÓ

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Zariski Spaces. A topological space \(X\) is a Zariski space if it is noetherian and every (nonempty) closed irreducible subset has a unique generic point (Ex. 2.9 ). For example, let \(R\) be a discrete valuation ring, and let \(T=\operatorname{sp}(\operatorname{Spec} R)\). Then \(T\) consists of two points \(t_{0}=\) the maximal ideal, \(t_{1}=\) the zero ideal. The open subsets are \(\varnothing,\left\\{t_{1}\right\\},\) and \(T .\) This is an irreducible Zariski space with generic point \(t_{1}\). (a) Show that if \(X\) is a noetherian scheme, then \(\operatorname{sp}(X)\) is a Zariski space. (b) Show that any minimal nonempty closed subset of a Zariski space consists of one point. We call these closed points. (c) Show that a Zariski space \(X\) satisfies the axiom \(T_{0}\) : given any two distinct points of \(X\), there is an open set containing one but not the other (d) If \(X\) is an irreducible Zariski space, then its generic point is contained in every nonempty open subset of \(X\) (e) If \(x_{0}, x_{1}\) are points of a topological space \(X,\) and if \(x_{0} \in\left\\{x_{1}\right\\}^{-},\) then we say that \(x_{1}\) specializes to \(x_{0},\) written \(x_{1} \leadsto \rightarrow x_{0} .\) We also say \(x_{0}\) is a specialization of \(x_{1},\) or that \(x_{1}\) is a generization of \(x_{0} .\) Now let \(X\) be a Zariski space. Show that the minimal points, for the partial ordering determined by \(x_{1}>x_{0}\) if \(x_{1} \leadsto x\) \(x_{0},\) are the closed points, and the maximal points are the generic points of the irreducible components of \(X .\) Show also that a closed subset contains every specialization of any of its points. (We say closed subsets are stable under specialization. . Similarly, open subsets are stable under generization. (f) Let \(t\) be the functor on topological spaces introduced in the proof of (2.6) If \(X\) is a noetherian topological space, show that \(t(X)\) is a Zariski space. Furthermore \(X\) itself is a Zariski space if and only if the \(\operatorname{map} \alpha: X \rightarrow t(X)\) is a homeomorphism.

Short Answer

Expert verified
The exercise determines various properties of Zariski spaces using knowledge from topological spaces and noetherian schemes.

Step by step solution

01

Part a

To show \(\operatorname{sp}(X)\) is a Zariski space, first note that \(X\) as a noetherian scheme is a noetherian topological space. Next, recall that for a noetherian topological space, every nonempty closed subset can be expressed as a finite union of irreducible closed subsets. Then, each irreducible closed subset in a scheme has a unique generic point where the generic point of irreducible closed subset \(Y\) of a scheme \(X\) is the unique point \(y\) such that \(\overline{\{y\}} = Y\). Hence \(\operatorname{sp}(X)\) is a Zariski space.
02

Part b

By definition, in a Zariski space, every nonempty closed irreducible subset \(Y\) has one unique generic point. So, if we have a minimal nonempty closed subset, it must be irreducible and contains exactly one point, its own unique generic point.
03

Part c

The axiom \(T_{0}\) can be shown with the fact that the ZaRiski topology is defined by closed sets that are either the empty set or finite complements of singletons. Hence given two distinct points, one can always find an open set (or the complement of a closed set) that contains one of the points but not the other.
04

Part d

The statement can be proven by contradiction. Assume there exists a nonempty open subset \(O\) in \(X\) not containing the generic point \(g\). The complement of \(O\) in \(X\), being a closed subset, must be a finite union of irreducible closed subsets of \(X\). Since \(X\) is irreducible and the union does not contain \(g\), we get a contradiction. Hence the generic point must be in every nonempty open subset.
05

Part e

The 'specializes to' relation on a space induces a partial ordering on its points. The 'closed points' are minimal elements of this ordering and 'generic point' of an irreducible component are maximal elements. If \(x_{1} \leadsto x_{0}, x_{1}\) is in the closure of the singleton set \(\{x_{0}\}\), hence any closed subset containing \(x_{1}\) must contain \(x_{0}\). Thus a closed subset contains all specializations of its points.
06

Part f

The functor \(t\) introduced in 2.6 transforms \(X\) into its specialization preorder set equipped with the order topology. Since \(X\) is noetherian, so is its specialization preorder set because it has the same number of points. And each point can be associated with a unique closed set and thus a unique irreducible subset. Hence the \(t(X)\) is a Zariski space. \(X\) is a Zariski space itself if only if the condition of unique generic point is preserved under the homeomorphism \(\alpha\), i.e., \(\alpha\) maps generic points to generic points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Noetherian Scheme
A Noetherian scheme is a foundational concept in algebraic geometry and topology. It characterizes a type of scheme with properties that make it manageable and predictable.

To understand Noetherian schemes, it's vital to know what it means for a scheme to be Noetherian.
  • A scheme is Noetherian if its underlying topological space is Noetherian. This means every descending chain of closed subsets eventually stabilizes, or equivalently, any open subset is compact.
  • In a Noetherian scheme, every non-empty closed subset can be represented as a finite union of irreducible closed subsets.
  • Practically, Noetherian schemes simplify various proofs and constructions in algebraic geometry due to their compact nature.
This concept is essential when dealing with Zariski spaces, as it ensures each non-empty closed subset has a unique minimal decomposition.
Generic Point
The concept of a generic point is central when discussing Zariski spaces and plays a critical role in understanding the structure and behavior of irreducible subsets.

A generic point for an irreducible closed subset is a special type of point with unique properties:
  • There is a unique point in each irreducible closed subset of a Noetherian topology, known as its generic point.
  • This point is characterized by the closure of the singleton set containing it being the entire subset.
  • In other words, when you have an irreducible closed subset \(Y\), and point \(y\) such that \(\overline{\{y\}} = Y\), then \(y\) is the generic point of \(Y\).
The importance of the generic point comes from its role in understanding minima in partially ordered spaces and establishing the uniqueness of certain minimal conditions.
Closed Subset
In the context of a Zariski space, closed subsets are crucial for defining its topological properties. Understanding closed subsets helps unravel the structure of such spaces.

Closed subsets have specific characteristics in a Zariski space:
  • They are stable under specialization, meaning any specializations (points in the closure of a singleton set) within a space reside within the same closed subset that includes the point it specializes from.
  • A minimal non-empty closed subset in a Zariski space contains exactly one point and is known as a closed point.
  • Closed subsets, particularly under the Zariski topology, can provide insights into how the space's irreducible components interact and overlap.
Closed subsets effectively highlight the intricacies of Zariski spaces and facilitate easier handling of topological dimensions.
Specialization
Specialization is a key operation in the study of Zariski spaces, revealing how points are related and interact in topological spaces.

The specialization relation can be understood as follows:
  • Given two points \(x_0\) and \(x_1\) within a topological space \(X\), \(x_1\) specializes to \(x_0\) (written as \(x_1 \leadsto x_0\)) if \(x_0\) is in the closure of \(\{x_1\}\).
  • Specialization induces a partial ordering among the points of a space, linking minima and maxima to closed and generic points, respectively.
  • Minimals with regards to specialization are closed points, while maximals are generic points in their irreducible components.
Understanding specialization helps in discerning the "flow" of points within a space under the given topological order, enhancing insight into the structure and behavior of Zariski spaces.

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Most popular questions from this chapter

Closed Subschemes of Proj \(S\). (a) Let \(\varphi: S \rightarrow T\) be a surjective homomorphism of graded rings, preserving degrees. Show that the open set \(U\) of \((\mathrm{Ex} .2 .14)\) is equal to Proj \(T,\) and the morphism \(f: \operatorname{Proj} T \rightarrow\) Proj \(S\) is a closed immersion. (b) If \(I \subseteq S\) is a homogeneous ideal, take \(T=S / I\) and let \(Y\) be the closed subscheme of \(X=\) Proj \(S\) defined as image of the closed immersion \(\operatorname{Proj} S / I \rightarrow X\) Show that different homogeneous ideals can give rise to the same closed subscheme. For example, let \(d_{0}\) be an integer,and let \(I^{\prime}=\bigoplus_{d \geqslant d_{0}} I_{d} .\) Show that \(I\) and \(I^{\prime}\) determine the same closed subscheme. We will see later (5.16) that every closed subscheme of \(X\) comes from a homogeneous ideal \(I\) of \(S\) (at least in the case where \(S\) is a polynomial ring over \(S_{0}\) ).

Let \(\left(X, C_{X}\right)\) be a scheme, and let \(U \subseteq X\) be any open subset. Show that \(\left(U,\left.C_{X}\right|_{l}\right)\) is a scheme. We call this the induced scheme structure on the open set \(l\), and we refer to \(\left(U .\left.C x\right|_{c}\right)\) as an open subscheme of \(X\). (a) Show that \(\left(X, \mathscr{C}_{X}\right)\) is reduced if and only if for every \(P \in X\), the local ring \(\varphi_{X, P}\) has no nilpotent elements (b) Let \(\left(X, C_{X}\right)\) be a scheme. Let \((C, 1)\), be the sheaf associated to the presheaf \(U \mapsto \mathscr{C}_{x}(U)_{\mathrm{red}},\) where for any ring \(A,\) we denote by \(A_{\mathrm{red}}\) the quotient of \(A\) by its ideal of nilpotent elements. Show that \((X,(c, 1), d)\) is a scheme. We call it the reduced scheme associated to \(X\). and denote it by \(X\), Show that there is a morphism of schemes \(X_{\text {red }} \rightarrow X\), which is a homeomorphism on the underlying topological spaces. (c) Let \(f: X \rightarrow Y\) be a morphism of schemes. and assume that \(X\) is reduced. Show that there is a unique morphism \(y: X \rightarrow Y_{\text {red }}\) such that \(f\) is obtained by composing \(g\) with the natural \(\operatorname{map} Y_{\mathrm{red}} \rightarrow 1\).

If \(V, W\) are two varieties over an algebraically closed field \(k,\) and if \(V \times W\) is their product, as defined in (I, Ex. 3.15,3.16 ), and if \(t\) is the functor of (2.6) then \(t(V \times W)=t(V) \times_{\text {spec } k} t(W)\).

Blowing up a Nonsingular Subvariety. As in \((8.24),\) let \(X\) be a nonsingular variety, let \(Y\) be a nonsingular subvariety of codimension \(r \geqslant 2\), let \(\pi: \tilde{X} \rightarrow X\) be the blowing-up of \(X\) along \(Y\), and let \(Y^{\prime}=\pi^{-1}(Y)\) (a) Show that the maps \(\pi^{*}:\) Pic \(X \rightarrow\) Pic \(\tilde{X}\), and \(\mathbf{Z} \rightarrow\) Pic \(X\) defined by \(n \mapsto\) class of \(n Y^{\prime},\) give rise to an isomorphism Pic \(\tilde{X} \cong \operatorname{Pic} X \oplus \mathbf{Z}\) (b) Show that \(\omega_{\tilde{X}} \cong f^{*} \omega_{X} \otimes \mathscr{L}\left((r-1) Y^{\prime}\right) .[\) Hint: By (a) we can write in any \(\operatorname{case} \omega_{\tilde{X}} \cong f^{*} \mathscr{M} \otimes \mathscr{L}\left(q Y^{\prime}\right)\) for some invertible sheaf \(\mathscr{M}\) on \(X,\) and some integer \(q .\) By restricting to \(\tilde{X}-Y^{\prime} \cong X-Y\), show that \(\mathscr{M} \cong \omega_{X} .\) To determine \(q\) proceed as follows. First show that \(\omega_{Y^{\prime}} \cong f^{*} \omega_{X} \otimes O_{Y^{\prime}}(-q-1) .\) Then take a closed point \(y \in Y\) and let \(Z\) be the fibre of \(Y^{\prime}\) over \(y .\) Then show that \(\omega_{z} \cong\) \(\left.\mathcal{O}_{\mathbf{z}}(-q-1) . \text { But since } Z \cong \mathbf{P}^{r-1}, \text { we have } \omega_{\mathbf{Z}} \cong \mathcal{O}_{\mathbf{z}}(-r), \text { so } q=r-1 .\right]\)

Let \(X\) be a variety of dimension \(n\) over \(k .\) Let \(\mathscr{E}\) be a locally free sheaf of \(\operatorname{rank}>n\) on \(X,\) and let \(V \subseteq \Gamma(X, \mathscr{E})\) be a vector space of global sections which generate \(\mathscr{E} .\) Then show that there is an element \(s \in V\), such that for each \(x \in X,\) we have \(s_{x} \notin \mathrm{m}_{x} \mathscr{E}_{x} .\) Conclude that there is a morphism \(\mathscr{O}_{x} \rightarrow \mathscr{E}\) giving rise to an exact sequence \\[ 0 \rightarrow \mathscr{O}_{X} \rightarrow \mathscr{E} \rightarrow \mathscr{E}^{\prime} \rightarrow 0 \\] where \(\mathscr{E}^{\prime}\) is also locally free. \([\text {Hint}:\) Use a method similar to the proof of Bertini's theorem \((8.18) .]\)

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