/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Tensor Operations on Sheaves. Fi... [FREE SOLUTION] | 91Ó°ÊÓ

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Tensor Operations on Sheaves. First we recall the definitions of various tensor operations on a module. Let \(A\) be a ring, and let \(M\) be an \(A\) -module. Let \(T^{\prime \prime}(M)\) be the tensor product \(M \otimes \ldots \otimes M\) of \(M\) with itself \(n\) times, for \(n \geqslant 1\). For \(n=0\) we put \(T^{0}(M)=A .\) Then \(T(M)=\bigoplus_{n \geqslant 0} T^{\prime \prime}(M)\) is a (noncommutative) \(A\) -algebra, which we call the tensor algebra of \(M .\) We define the symmetric algebra \(S(M)=\bigoplus_{n \geqslant 0} S^{\prime \prime}(M)\) of \(M\) to be the quotient of \(T(M)\) by the two-sided ideal generated by all expressions \(x \otimes y-y \otimes x,\) for all \(x, y \in M .\) Then \(S(M)\) is a commutative \(A\) -algebra. Its component \(S^{n}(M)\) in degree \(n\) is called the \(n\) th symmetric product of \(M .\) We denote the image of \(x \otimes y\) in \(S(M)\) by \(x y,\) for any \(x, y \in M .\) As an example, note that if \(M\) is a free \(A\) -module of rank \(r,\) then \(S(M) \cong\) \(A\left[x_{1}, \ldots, x_{r}\right]\). We define the exterior algebra \(\wedge(M)=\bigoplus_{n \geqslant 0} \wedge^{\prime \prime}(M)\) of \(M\) to be the quotient of \(T(M)\) by the two- sided ideal generated by all expressions \(x \otimes x\) for \(x \in M .\) Note that this ideal contains all expressions of the form \(x \otimes y+y \otimes x\) so that \(\wedge(M)\) is a skew commutative graded \(A\) -algebra. This means that if \(u \in\) \(\wedge^{r}(M)\) and \(v \in \Lambda^{s}(M),\) then \(u \wedge v=(-1)^{r s} v \wedge u\) (here we denote by \(\wedge\) the multiplication in this algebra; so the image of \(x \otimes y\) in \(\wedge^{2}(M)\) is denoted by \(x \wedge y\) ). The \(n\) th component \(\wedge^{\prime \prime}(M)\) is called the \(n\) th exterior power of \(M\). Now let \(\left(X, O_{X}\right)\) be a ringed space, and let \(\mathscr{F}\) be a sheaf of \(\mathcal{O}_{X}\) -modules. We define the tensor algebra, symmetric algebra, and exterior algebra of \(\mathscr{F}\) by taking the sheaves associated to the presheaf, which to each open 'set \(U\) assigns the corresponding tensor operation applied to \(\mathscr{F}(U)\) as an \(\mathscr{O}_{X}(U)\) -module. The results are \(\mathcal{O}_{X^{-}}\) algebras, and their components in each degree are \(\mathscr{C}_{X}\) -modules. (a) Suppose that \(\mathscr{F}\) is locally free of rank \(n\). Then \(T^{\prime}(\mathscr{F}), S^{\prime}(\mathscr{F})\), and \(\wedge^{\prime}(\mathscr{F})\) are also locally free, of ranks \(n^{\prime},\left(\begin{array}{c}m+r-1 \\ n-1\end{array}\right),\) and \(\left(\begin{array}{c}m \\ 2\end{array}\right)\) respectively. (b) Again let \(\mathscr{F}\) be locally free of rank \(n\). Then the multiplication \(\operatorname{map} \wedge \mathscr{F} \otimes\) \(\wedge^{n-r} \mathscr{F} \rightarrow \wedge^{n} \cdot \mathscr{F}\) is a perfect pairing for any \(r,\) i.c., it induces an isomorphism of \(\wedge^{\prime \prime} \mathscr{F}\) with \(\left(\wedge^{n-r} \mathscr{F}\right)^{\sim} \otimes \wedge^{\prime \prime} \mathscr{F}\). As a special case, note if \(\mathscr{F}\) has rank 2 then \(\mathscr{F} \cong \mathscr{F}^{\sim} \otimes \wedge^{2} \mathscr{F}\) (c) Let \(0 \rightarrow \mathscr{F}^{\prime} \rightarrow \mathscr{F} \rightarrow \mathscr{F}^{\prime \prime} \rightarrow 0\) be an exact sequence of locally free sheaves. Then for any \(r\) there is a finite filtration of \(S^{\prime}(\mathscr{F})\) \\[ S^{\prime}(\mathscr{F})=F^{0} \supseteq F^{1} \supseteq \ldots \supseteq F^{\prime} \supseteq F^{r+1}=0 \\] with quotients \\[ F^{p} / F^{p+1} \cong S^{p}\left(\mathscr{F}^{\prime}\right) \otimes S^{r-p}\left(\mathscr{F}^{\prime \prime}\right) \\] for each \(p\). (d) Same statement as (c), with exterior powers instead of symmetric powers. In particular, if \(\mathscr{F}^{\prime}, \mathscr{F}, \mathscr{F}^{\prime \prime}\) have ranks \(n^{\prime}, n, n^{\prime \prime}\) respectively, there is an isomorphism \(\wedge^{n} \mathscr{F} \cong \wedge^{n^{\prime} \mathscr{F}^{\prime}} \otimes \wedge^{n^{\prime \prime}} \mathscr{F}^{\prime \prime}\) (e) Let \(f: X \rightarrow Y\) be a morphism of ringed spaces, and let \(\mathscr{F}\) be an \(\mathscr{U}_{Y}\) -module. Then \(f^{*}\) commutes with all the tensor operations on \(\mathscr{F},\) i.e., \(f^{*}\left(S^{n}(\mathscr{F})\right)=\) \(S^{\prime \prime}\left(f^{*} \mathscr{F}\right)\) etc.

Short Answer

Expert verified
These tensor operations when applied to a locally free sheaf of a certain rank yield other locally free sheaves. Tensors operations on sheafs behave similarly as on modules. Hence, these properties and outcomes are preserved when applied through an exact sequence of locally free sheaves or along with a morphism of ringed spaces.

Step by step solution

01

Part (a)

This part requires the use of the property that if \( \mathscr{F}\) is locally free of rank \( n\), then \( T^{\prime}(\mathscr{F}), S^{\prime}(\mathscr{F})\), and \( \wedge^{\prime}(\mathscr{F})\) are also locally free. This is because the tensor product, symmetric product, and wedge product of locally free modules are also locally free.
02

Part (b)

For this part, use the property of the wedge product and the interaction between the wedge product of different powers. To show that the multiplication map \( \wedge \mathscr{F} \otimes \wedge^{n-r} \mathscr{F} \rightarrow \wedge^{n} \mathscr{F} \) is a perfect pairing, it's enough to look at the degrees of the components involved.
03

Part (c)

Involves understanding the tensor operations and how they function with exact sequences of locally free sheaves. If we know that \( 0 \rightarrow \mathscr{F}^{\prime} \rightarrow \mathscr{F} \rightarrow \mathscr{F}^{\prime \prime} \rightarrow 0 \) is an exact sequence, we can use that to build a filtration for \(S^{\prime}(\mathscr{F})\) with specific properties.
04

Part (d)

Much like part (c), but we're applying the same methods to the exterior powers of an exact sequence. For this, it’s enough to provide an isomorphism between the nth exterior power of \( \mathscr{F} \) and the tensor product of the nth exterior powers of \( \mathscr{F}^{\prime}, \mathscr{F}^{\prime \prime} \)
05

Part (e)

This part requires understanding how tensor operations apply in the context of ringed spaces using a morphism \( f: X \rightarrow Y \) and an \( \mathscr{U}_{Y} \) -module \( \mathscr{F} \). This step involves showing that \( f^{*} \) commutes with all the tensor operations on \(\mathscr{F}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tensor Algebra
Tensor algebra provides a framework for constructing an algebraic structure from any given module. As you delved into the tensor operations on sheaves, it's imperative to grasp the foundations of tensor algebra. In this context, when we discuss a module, say M, over a ring A, the tensor algebra T(M) comes into play. This algebra is the direct sum of all tensor powers of M, including T0(M) as the ring A itself.

What makes tensor algebra particularly versatile is its ability to construct other algebraic structures. By modulating it with certain ideals, we can derive new algebras like symmetric and exterior algebras, each holding unique properties and applications. The noncommutative nature of tensor algebra also subtly hints at the geometric and topological nuances that these structures model in higher mathematics.
Symmetric Algebra
Generated from the tensor algebra, the symmetric algebra S(M) is attained by constraining elements to commute, effectively polishing the tensor algebra to a commutative counterpart. In essence, symmetric algebra is the quotient of the tensor algebra by the relations x ⊗ y = y ⊗ x for all elements x, y in M. This commutative property demarcates it from the tensor algebra, making it an invaluable tool in situations like polynomial rings where commutativity is paramount.

The symmetric algebra can also encapsulate the idea of symmetric powers of a module, revealing the potential creativity in combining module elements without considering order. For students exploring geometry, it's analogous to studying shapes where orientation and arrangements are immaterial, such as the sphere, which remains unchanged under various rotations.
Exterior Algebra
A leap from symmetric to exterior algebra involves introducing antisymmetry through the construction of a skew-commutative algebra. By factoring out the tensor algebra with the two-sided ideal generated by x ⊗ x for each x in M, the exterior algebra ∧(M) is realized. Here, skew-commutativity dominates, meaning the wedge product x ∧ y is the negative of y ∧ x.

Exterior algebra encapsulates the concept of orientation, crucial in various areas including geometric and algebraic topologies, such as when determining the orientation of a manifold. The nomenclature 'exterior' often translates to 'outside' in everyday language, which is a helpful mnemonic for associating this algebra with properties that extend beyond the usual symmetrical interactions.
Exact Sequence of Sheaves
In the realm of algebraic topology and algebraic geometry, sheaves serve as tools to study local-global phenomena. An exact sequence of sheaves is a sequence where the image of one homomorphism is exactly the kernel of the subsequent one. This conveys a refined balance within a progression of sheaves, revealing intricate structural relationships.

The exact sequence is a powerful notion, particularly when dealing with locally free sheaves—sheaves of modules that look locally like free modules. They allow for the construction of complex objects from simpler ones and for the probing of cohomological properties. Exact sequences offer a pathway to understanding the continuity and interplay between local and global properties in geometrical spaces, analogous to a well-orchestrated symphony where each note perfectly transitions into the next.
Locally Free Modules
The concept of locally free modules is an extension of free modules in a localized context, pivotal to the comprehension of sheaf cohomology. In the setting of sheaves, the term 'locally free' is analogous to 'free,' but with an emphasis on local behavior. A module M is locally free if each point has an open neighborhood where the restriction of M resembles a free module.

Students might find it helpful to consider 'locally free' akin to being 'flexible' in specific neighborhoods, much as a city might have localized regulations while being part of a larger structured country. The significance of locally free modules illustrates how global properties of spaces can emerge from stitching together their well-behaved local characteristics.
Ringed Spaces
In algebraic geometry, ringed spaces provide a fundamental framework that captures both the topological structure of a space and the algebraic data carried on it. A ringed space is a pair consisting of a topological space and a sheaf of rings defined over it. This sheaf of rings assigns to each open set a ring, tying together the algebraic and topological properties.

Ringed spaces embody a synergy between algebra and geometry, serving as an algebraic mirror for geometric concepts. Imagine a cake with different layers of frosting; similarly, a ringed space has various layers or rings of algebraic structures swept over its topological base.
Wedge Product
The wedge product, conveyed as ∧, emerges from the exterior algebra and equips us with a way to amalgamate elements from the algebra while maintaining their antisymmetric character. In many geometric contexts, the wedge product allows for the calculation of areas, volumes, and higher-dimensional analogs, reflecting the oriented intersection of geometrical objects.

Embracing these properties, the wedge product aids in computations in differential forms and is foundational in establishing the integral theorems of vector calculus, such as Stokes' and Green's theorems. Like a pair of crossed swords symbolizes conflict, the wedge product typifies the mathematical contention of elements being inversed when flipped.
Perfect Pairing in Algebraic Geometry
In algebraic geometry, the notion of perfect pairing represents a bilinear form that allows one to equate spaces that are dual to each other. It's a form of mathematical reciprocity that amplifies concepts of duality and symmetry within algebraic structures. A perfect pairing, particularly when working with sheaves that are locally free, can transform and relate different algebraic objects, facilitating a profound understanding of their underlying geometry.

Envision a dance between two partners, perfectly in sync; every step by one dancer corresponds to a matching but opposite step by the other. Perfect pairing embodies this harmony, where structures on a geometric space interlink and correspond with flawless precision, bestowing insights into the space's intrinsic properties.

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Most popular questions from this chapter

A topological space is quasi-compact if every open cover has a finite subcover. (a) Show that a topological space is noetherian (I, \(\$ 1)\) if and only if every open subset is quasi-compact. (b) If \(X\) is an affine scheme. show that \(\operatorname{sp}(X)\) is quasi- compact. but not in general noetherian. We say a scheme \(X\) is quati-ciompact if \(\operatorname{sp}(X)\) is. (c) If \(A\) is a noetherian ring. show that spiSpec 1 ) is a nocthcrian topological space. (d) Give an example to show that sp(Spec \(A\) ) can be noetherian even when \(A\) is not.

Zariski Spaces. A topological space \(X\) is a Zariski space if it is noetherian and every (nonempty) closed irreducible subset has a unique generic point (Ex. 2.9 ). For example, let \(R\) be a discrete valuation ring, and let \(T=\operatorname{sp}(\operatorname{Spec} R)\). Then \(T\) consists of two points \(t_{0}=\) the maximal ideal, \(t_{1}=\) the zero ideal. The open subsets are \(\varnothing,\left\\{t_{1}\right\\},\) and \(T .\) This is an irreducible Zariski space with generic point \(t_{1}\). (a) Show that if \(X\) is a noetherian scheme, then \(\operatorname{sp}(X)\) is a Zariski space. (b) Show that any minimal nonempty closed subset of a Zariski space consists of one point. We call these closed points. (c) Show that a Zariski space \(X\) satisfies the axiom \(T_{0}\) : given any two distinct points of \(X\), there is an open set containing one but not the other (d) If \(X\) is an irreducible Zariski space, then its generic point is contained in every nonempty open subset of \(X\) (e) If \(x_{0}, x_{1}\) are points of a topological space \(X,\) and if \(x_{0} \in\left\\{x_{1}\right\\}^{-},\) then we say that \(x_{1}\) specializes to \(x_{0},\) written \(x_{1} \leadsto \rightarrow x_{0} .\) We also say \(x_{0}\) is a specialization of \(x_{1},\) or that \(x_{1}\) is a generization of \(x_{0} .\) Now let \(X\) be a Zariski space. Show that the minimal points, for the partial ordering determined by \(x_{1}>x_{0}\) if \(x_{1} \leadsto x\) \(x_{0},\) are the closed points, and the maximal points are the generic points of the irreducible components of \(X .\) Show also that a closed subset contains every specialization of any of its points. (We say closed subsets are stable under specialization. . Similarly, open subsets are stable under generization. (f) Let \(t\) be the functor on topological spaces introduced in the proof of (2.6) If \(X\) is a noetherian topological space, show that \(t(X)\) is a Zariski space. Furthermore \(X\) itself is a Zariski space if and only if the \(\operatorname{map} \alpha: X \rightarrow t(X)\) is a homeomorphism.

Extension of Coherent Sheaves. We will prove the following theorem in several steps: Let \(X\) be a noetherian scheme, let \(U\) be an open subset, and let \(\mathscr{F}\) be a coherent sheaf on \(U\). Then there is a coherent sheaf \(\mathscr{F}^{\prime}\) on \(X\) such that \(\left.\mathscr{F}^{\prime}\right|_{v} \cong \mathscr{F}\) (a) On a noetherian affine scheme, every quasi-coherent sheaf is the union of its coherent subsheaves. We say a sheaf \(\mathscr{F}\) is the union of its subsheaves \(\mathscr{F}\) if for every open set \(U\), the group \(\mathscr{F}(U)\) is the union of the subgroups ?\((U)\) (b) Let \(X\) be an affine noetherian scheme, \(U\) an open subset, and \(\mathscr{F}\) coherent on \(U .\) Then there exists a coherent sheaf \(\mathscr{F}^{\prime}\) on \(X\) with \(\left.\mathscr{F}^{\prime}\right|_{v} \cong \mathscr{F} .\) [Hint: Let \(\left.i: U \rightarrow X \text { be the inclusion map. Show that } i_{*} \mathscr{F} \text { is quasi-coherent, then use }(a) .\right]\) (c) With \(X, U, \mathscr{F}\) as in (b), suppose furthermore we are given a quasi-coherent sheaf \(\mathscr{G}\) on \(X\) such that \(\left.\mathscr{F} \subseteq \mathscr{G}\right|_{v} .\) Show that we can find \(\mathscr{F}^{\prime}\) a coherent subsheaf of \(\mathscr{G},\) with \(\left.\mathscr{F}^{\prime}\right|_{v} \cong \mathscr{F}\). [Hint: Use the same method, but replace \(i_{*} \mathscr{F}\) by \(\left.\rho^{-1}\left(i_{*} \mathscr{F}\right) \text { , where } \rho \text { is the natural } \operatorname{map} \mathscr{G} \rightarrow i_{*}\left(\left.\mathscr{G}\right|_{U}\right) .\right]\) (d) Now let \(X\) be any noetherian scheme, \(U\) an open subset, \(\mathscr{F}\) a coherent sheaf on \(U,\) and \(\mathscr{G}\) a quasi-coherent sheaf on \(X\) such that \(\left.\mathscr{F} \subseteq \mathscr{G}\right|_{V} .\) Show that there is a coherent subsheaf \(\mathscr{F}^{\prime} \subseteq \mathscr{G}\) on \(X\) with \(\left.\mathscr{F}^{\prime}\right|_{v} \cong \mathscr{F}\). Taking \(\mathscr{I}=i_{*} \mathscr{F}\) proves the result announced at the beginning. [Hint: Cover \(X\) with open affines, and extend over one of them at a time. (e) As an extra corollary, show that on a noetherian scheme, any quasi- coherent sheaf \(\mathscr{F}\) is the union of its coherent subsheaves. [Hint: If \(s\) is a section of \(\mathscr{F}\) over an open set \(U,\) apply (d) to the subsheaf of \(\left.\mathscr{F}\right|_{v}\) generated by s.]

If \(X\) is a scheme of finite type over a field, show that the closed points of \(X\) are dense. Give an example to show that this is not true for arbitrary schemes.

Let \(A\) be a ring, let \(S=A\left[x_{0}, \ldots, x_{r}\right]\) and let \(X=\) Proj \(S\). We have seen that a homogeneous ideal \(I\) in \(S\) defines a closed subscheme of \(X\) (Ex. 3.12 ), and that conversely every closed subscheme of \(X\) arises in this way (5.16) (a) For any homogeneous ideal \(I \subseteq S\), we define the saturation \(I\) of \(I\) to be \(\left\\{s \in S | \text { for each } i=0, \ldots, r, \text { there is an } n \text { such that } x_{i}^{n} s \in I\right\\} .\) We say that \(I\) is saturated if \(I=I .\) Show that \(T\) is a homogeneous ideal of \(S\). (b) Two homogeneous ideals \(I_{1}\) and \(I_{2}\) of \(S\) define the same closed subscheme of \(X\) if and only if they have the same saturation. (c) If \(Y\) is any closed subscheme of \(X\), then the ideal \(\Gamma_{*}\left(\mathscr{I}_{Y}\right)\) is saturated. Hence it is the largest homogeneous ideal defining the subscheme \(Y\) (d) There is a \(1-1\) correspondence between saturated ideals of \(S\) and closed subschemes of \(X\).

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