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Support. Let \(\mathscr{F}\) be a sheaf on \(X\), and let \(s \in \mathscr{F}(U)\) be a section over an open set \(U\) The support of \(s\), denoted Supp s, is defined to be \(\left\\{P \in U | s_{P} \neq 0\right\\},\) where \(s_{P}\) denotes the germ of s in the stalk \(\overline{\mathscr{F}}_{p}\). Show that Supp s is a closed subset of \(U\). We define the support of \(\overline{\mathscr{F}}, \operatorname{Supp}, \overline{\mathscr{F}},\) to be \(\left\\{P \in X | \mathscr{F}_{P} \neq 0\right\\},\) It need not be a closed subset.

Short Answer

Expert verified
The support of a section \(s\) is a closed subset of \(U\), while the support of the sheaf itself need not be closed.

Step by step solution

01

Definition of Support

The support of a section \(s\) of a sheaf \(\mathscr{F}\) on \(X\) over an open set \(U\), denoted by Supp \(s\), is defined as the set \(\left\{P \in U | s_{P} \neq 0\right\}\), where \(s_{P}\) denotes the germ of \(s\) at \(P\) in the stalk \(\overline{\mathscr{F}}_{p}\). This is the set of points in \(U\) where \(s\) is 'felt' or non-zero. Similarly, the support of a sheaf, denoted by Supp \(\overline{\mathscr{F}}\), is defined as the set \(\left\{P \in X | \mathscr{F}_{P} \neq 0\right\}\).
02

Show that Supp s is closed in \(U\)

To show that Supp \(s\) is closed, it's enough to show that its complement in \(U\) is open. The complement of Supp \(s\) in \(U\) is \(\left\{P \in U | s_{P} = 0\right\}\). This is the set of all points \(P\) in \(U\) where the germ of \(s\) is zero. Because the section is zero, this set is open by the definition of a sheaf. Therefore, Supp \(s\) is closed in \(U\).
03

Contrast with Support of a Sheaf

For contrast, note that the support of a sheaf \(\mathscr{F}\) itself, Supp \(\overline{\mathscr{F}}\), need not be a closed subset of \(U\). This is because we are considering all sections of the sheaf, not just a single section. Its support is the set of points where some section of the sheaf is nonzero, so it could be that at some points, some sections vanish while others do not.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sheaf
In the language of topology and abstract algebra, a sheaf is a tool for systematically tracking locally defined data attached to the open sets of a topological space. Think of it as a way to understand how local pieces of information fit together to form global data on a space.

For instance, a sheaf might assign to each open set of a space a collection of functions defined on that set. These functions should behave nicely - if you have a function on a larger open set and you restrict it to a smaller open set, it should be part of the collection assigned to the smaller set. This property is known as 'locality'. Likewise, if you have a bunch of functions on overlapping sets that agree where they overlap, you should be able to stitch them together into a single function on the union of those sets. This is called 'gluing'.

These properties make sheaves exceptionally useful in many areas of mathematics, including differential geometry, algebraic geometry, complex analysis, and more. They allow mathematicians to patch local solutions to differential equations or piece together local bits of shapes to understand the larger structure of geometrical objects.
Stalk of a Sheaf
The 'stalk' of a sheaf might conjure up images of a plant stem, but in mathematics, it's a bit more abstract. A stalk at a point 'P' within the topological space X provides a bird's-eye view of all the information the sheaf has about 'P'.

You can think of it this way: for every open set containing 'P', look at the data the sheaf assigns to that open set and then zoom in on what that data says specifically about 'P'. The stalk at 'P' collects all these little bits of information into a single algebraic structure, typically a group or a ring.

Now, why is this useful? The stalk allows us to understand the 'behavior' of sheaf data right at the point 'P' without getting distracted by what's happening away from 'P'. It's all about local data. To calculate the stalk, we actually look at 'germs' of sections — essentially, the relevant elements of the sheaf that are attached to neighborhoods of 'P'.

Within the context of our exercise, the germ of a section is what tells us whether the support of a section will include the point 'P' or not. The support, therefore, is essentially the 'footprint' of the section where it has a non-zero presence.
Closed Subset
When we step back into the broader field of topological spaces, a subset is 'closed' if it contains all its limit points; it's complete and 'sealed off' in a sense. Intuitively, if you have a sequence of points in the closed subset that gets closer and closer to some boundary point, that boundary point must also be in the set.

In our scenario, proving that the support of a section is a closed subset involves showing that 'outside' the support, the section is consistently zero. In topological terms, the complement of the support (the part of the open set 'U' not in the support) has to be an open set itself. Since sections of a sheaf obey the locality and gluing properties, if a section is zero at some point it must be zero in some vicinity of that point - which allows us to see how the whole complement is open.

This is an attractive property because it falls in line with how we naturally think of 'vanishing': if a function is zero at a point and is continuous, we expect it to be zero in a surrounding region. That is precisely what's reflected in the topology when we proclaim that the support is closed. It affirms that within 'U', the behavior of the section has clear boundaries - it's present or 'felt' up to a particular frontier and beyond that, it simply doesn't exist.

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Most popular questions from this chapter

Let \(S\) be a scheme, let \(X\) be a reduced scheme over \(S\), and let \(Y\) be a separated scheme over \(S\). Let \(f\) and \(g\) be two \(S\) -morphisms of \(X\) to \(Y\) which agree on an open dense subset of \(X .\) Show that \(f=g .\) Give examples to show that this result fails if either (a) \(X\) is nonreduced, or (b) \(Y\) is nonseparated. [Hint: Consider the \(\left.\operatorname{map} h: X \rightarrow Y \times_{S} Y \text { obtained from } f \text { and } g .\right].\)

Extending a Sheaf by Zero. Let \(X\) be a topological space, let \(Z\) be a closed subset. let \(i: Z \rightarrow X\) be the inclusion, let \(U=X-Z\) be the complementary open subset and let \(j: U \rightarrow X\) be its inclusion. (a) Let \(\mathscr{J}\) be a sheaf on \(Z\). Show that the stalk \(\left(i_{*}, \overline{\mathscr{H}}\right)_{p}\) of the direct image sheaf on \(X\) is \(\mathscr{F}_{P}\) if \(P \in Z, 0\) if \(P \notin Z\). Hence we call \(i_{*}\). \(\bar{y}\) the sheaf obtained by extending of \(i_{*} \overline{\mathscr{H}},\) and say "consider \(\mathscr{F}\) as a sheaf on \(X\)," when we mean "consider \(i_{*}\). (b) Now let \(\overline{\mathscr{H}}\) be a sheaf on \(U\). Let \(j\), \((\overrightarrow{\mathscr{H}})\) be the sheaf on \(X\) associated to the presheaf \(V \mapsto \mathscr{F}(V)\) if \(V \subseteq U, V \mapsto 0\) otherwise. Show that the stalk \((j,(\mathscr{F}))_{P}\) is equal to \(\overline{\mathscr{I}}_{p}\) if \(P \in U, 0\) if \(P \notin U\), and show that \(j\), \(\overline{\mathscr{H}}\) is the only sheafon \(X\) which has this property, and whose restriction to \(U\) is \(\mathscr{F}\). We call \(j\). F. Fhe sheaf obtained by extending \(\mathscr{F}\) by zero outside \(U\) (c) Now let \(\mathscr{F}\) be a sheaf on \(X\). Show that there is an exact sequence of sheaves on \(X\) $$0 \rightarrow j \cdot\left(\left.\overline{\mathscr{H}}\right|_{c}\right) \rightarrow \overline{\mathscr{H}} \rightarrow i_{*}\left(\left.\mathscr{F}\right|_{Z}\right) \rightarrow 0$$

Show that a morphism of sheaves is an isomorphism if and only if it is both injective and surjective.

Tensor Operations on Sheaves. First we recall the definitions of various tensor operations on a module. Let \(A\) be a ring, and let \(M\) be an \(A\) -module. Let \(T^{\prime \prime}(M)\) be the tensor product \(M \otimes \ldots \otimes M\) of \(M\) with itself \(n\) times, for \(n \geqslant 1\). For \(n=0\) we put \(T^{0}(M)=A .\) Then \(T(M)=\bigoplus_{n \geqslant 0} T^{\prime \prime}(M)\) is a (noncommutative) \(A\) -algebra, which we call the tensor algebra of \(M .\) We define the symmetric algebra \(S(M)=\bigoplus_{n \geqslant 0} S^{\prime \prime}(M)\) of \(M\) to be the quotient of \(T(M)\) by the two-sided ideal generated by all expressions \(x \otimes y-y \otimes x,\) for all \(x, y \in M .\) Then \(S(M)\) is a commutative \(A\) -algebra. Its component \(S^{n}(M)\) in degree \(n\) is called the \(n\) th symmetric product of \(M .\) We denote the image of \(x \otimes y\) in \(S(M)\) by \(x y,\) for any \(x, y \in M .\) As an example, note that if \(M\) is a free \(A\) -module of rank \(r,\) then \(S(M) \cong\) \(A\left[x_{1}, \ldots, x_{r}\right]\). We define the exterior algebra \(\wedge(M)=\bigoplus_{n \geqslant 0} \wedge^{\prime \prime}(M)\) of \(M\) to be the quotient of \(T(M)\) by the two- sided ideal generated by all expressions \(x \otimes x\) for \(x \in M .\) Note that this ideal contains all expressions of the form \(x \otimes y+y \otimes x\) so that \(\wedge(M)\) is a skew commutative graded \(A\) -algebra. This means that if \(u \in\) \(\wedge^{r}(M)\) and \(v \in \Lambda^{s}(M),\) then \(u \wedge v=(-1)^{r s} v \wedge u\) (here we denote by \(\wedge\) the multiplication in this algebra; so the image of \(x \otimes y\) in \(\wedge^{2}(M)\) is denoted by \(x \wedge y\) ). The \(n\) th component \(\wedge^{\prime \prime}(M)\) is called the \(n\) th exterior power of \(M\). Now let \(\left(X, O_{X}\right)\) be a ringed space, and let \(\mathscr{F}\) be a sheaf of \(\mathcal{O}_{X}\) -modules. We define the tensor algebra, symmetric algebra, and exterior algebra of \(\mathscr{F}\) by taking the sheaves associated to the presheaf, which to each open 'set \(U\) assigns the corresponding tensor operation applied to \(\mathscr{F}(U)\) as an \(\mathscr{O}_{X}(U)\) -module. The results are \(\mathcal{O}_{X^{-}}\) algebras, and their components in each degree are \(\mathscr{C}_{X}\) -modules. (a) Suppose that \(\mathscr{F}\) is locally free of rank \(n\). Then \(T^{\prime}(\mathscr{F}), S^{\prime}(\mathscr{F})\), and \(\wedge^{\prime}(\mathscr{F})\) are also locally free, of ranks \(n^{\prime},\left(\begin{array}{c}m+r-1 \\ n-1\end{array}\right),\) and \(\left(\begin{array}{c}m \\ 2\end{array}\right)\) respectively. (b) Again let \(\mathscr{F}\) be locally free of rank \(n\). Then the multiplication \(\operatorname{map} \wedge \mathscr{F} \otimes\) \(\wedge^{n-r} \mathscr{F} \rightarrow \wedge^{n} \cdot \mathscr{F}\) is a perfect pairing for any \(r,\) i.c., it induces an isomorphism of \(\wedge^{\prime \prime} \mathscr{F}\) with \(\left(\wedge^{n-r} \mathscr{F}\right)^{\sim} \otimes \wedge^{\prime \prime} \mathscr{F}\). As a special case, note if \(\mathscr{F}\) has rank 2 then \(\mathscr{F} \cong \mathscr{F}^{\sim} \otimes \wedge^{2} \mathscr{F}\) (c) Let \(0 \rightarrow \mathscr{F}^{\prime} \rightarrow \mathscr{F} \rightarrow \mathscr{F}^{\prime \prime} \rightarrow 0\) be an exact sequence of locally free sheaves. Then for any \(r\) there is a finite filtration of \(S^{\prime}(\mathscr{F})\) \\[ S^{\prime}(\mathscr{F})=F^{0} \supseteq F^{1} \supseteq \ldots \supseteq F^{\prime} \supseteq F^{r+1}=0 \\] with quotients \\[ F^{p} / F^{p+1} \cong S^{p}\left(\mathscr{F}^{\prime}\right) \otimes S^{r-p}\left(\mathscr{F}^{\prime \prime}\right) \\] for each \(p\). (d) Same statement as (c), with exterior powers instead of symmetric powers. In particular, if \(\mathscr{F}^{\prime}, \mathscr{F}, \mathscr{F}^{\prime \prime}\) have ranks \(n^{\prime}, n, n^{\prime \prime}\) respectively, there is an isomorphism \(\wedge^{n} \mathscr{F} \cong \wedge^{n^{\prime} \mathscr{F}^{\prime}} \otimes \wedge^{n^{\prime \prime}} \mathscr{F}^{\prime \prime}\) (e) Let \(f: X \rightarrow Y\) be a morphism of ringed spaces, and let \(\mathscr{F}\) be an \(\mathscr{U}_{Y}\) -module. Then \(f^{*}\) commutes with all the tensor operations on \(\mathscr{F},\) i.e., \(f^{*}\left(S^{n}(\mathscr{F})\right)=\) \(S^{\prime \prime}\left(f^{*} \mathscr{F}\right)\) etc.

Let \(A\) be a ring. Show that the following conditions are equivalent: (i) Spec \(A\) is disconnected : (ii) there exist nonzero elements \(e_{1}, e_{2} \in A\) such that \(e_{1} e_{2}=0, e_{1}^{2}=e_{1}, e_{2}^{2}=e_{2}\) \(e_{1}+e_{2}=1\) (these elements are called orthogonal idempotents): (iii) \(A\) is isomorphic to a direct product \(A_{1} \times A_{2}\) of two nonzero rings.

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