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Chapter 9: Problem 54

Evaluate each expression. [-5]

Short Answer

Expert verified
-5

Step by step solution

01

Identify the Expression

Identify the expression to be evaluated. Here, the expression is -5
02

Determine the Context

Recognize that the expression -5 is simply a constant value. Thus, no further operations are required.
03

Conclude the Evaluation

Since the expression -5 is already evaluated, the final value is -5

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Constant Values
In mathematics, a constant value is a specific number that does not change. It stands alone without variables or operations to alter it. For example, in the given exercise, -5 is a constant value. It is simply a number and is already fully evaluated. This makes constant values straightforward. You don't need to perform calculations. They are what they are. Constant values can be either positive or negative and can include integers, fractions, and irrational numbers. Remember, recognizing a constant value means identifying that no further work is needed to find its worth.
Basic Arithmetic Simplified
Basic arithmetic involves fundamental math operations like addition, subtraction, multiplication, and division. These skills are essential for evaluating expressions. Understanding basic arithmetic helps in recognizing when no further operations are needed. In our example, it's crucial to see that -5 is not paired with any arithmetic operation. This lack of addition, subtraction, multiplication, or division indicates that the expression is already complete. So, when you encounter such basic expressions for homework, always check if you need to perform any arithmetic operations. If none are required, the value remains as is.
Dealing with Negative Numbers
Negative numbers are numbers less than zero, represented with a minus sign (-). They can be tricky, especially when combined with other arithmetic operations. Here, we simply have -5. But it's important to understand negative numbers for tackling more complex expressions. A negative sign in front of a number indicates its direction on the number line, away from positive values. If you were to add or subtract negative numbers, keep in mind:
  • Adding a negative number moves left on the number line.
  • Subtracting a negative number moves right.
Negative numbers are just as valid and useful as positive numbers in math. Always ensure you handle them properly.

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Most popular questions from this chapter

The snow depth in a particular location varies throughout the winter. In a typical winter, the snow depth in inches might be approximated by the following function. $$ f(x)=\left\\{\begin{array}{ll} 6.5 x & \text { if } 0 \leq x \leq 4 \\ -5.5 x+48 & \text { if } 4

A function \(f\) is an even function if \(f(-x)=f(x)\) for all \(x\) in the domain of \(f\). A function \(f\) is an odd function if \(f(-x)=-f(x)\) for all \(x\) in the domain of \(f\). To see how these ideas relate to symmetry, work in order. If a function is even, what do we know about its symmetry?

Graph each piecewise linear function. \(f(x)=\left\\{\begin{array}{ll}5 x-4 & \text { if } x \geq 1 \\ x & \text { if } x<1\end{array}\right.\)

The tables give some selected ordered pairs for functions \(f\) and \(g\). $$\begin{array}{r|r}{x} & f(x) \\\\\hline-1 & 1 \\\\\hline 2 & -1 \\\\\hline 5 & 9\end{array}$$ $$\begin{array}{c|c}x & g(x) \\\\\hline 2 & -1 \\\\\hline 7 & 5 \\\\\hline 1 & 9 \\\\\hline 9 & 20\end{array}$$ Find each of the following. $$ (f \circ g)(7) $$

In each problem, find the following. (a) A function \(R(x)\) that describes the total revenue received (b) The graph of the function from part (a) (c) The number of unsold seats that will produce the maximum revenue (d) The maximum revenue A charter flight charges a fare of \(\$ 200\) per person, plus \(\$ 4\) per person for each unsold seat on the plane. The plane holds 100 passengers. Let \(x\) represent the number of unsold seats. (Hint: To find \(R(x),\) multiply the number of people flying, \(100-x\), by the price per ticket, \(200+4 x\).)
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