Chapter 2: Problem 26
Let \(f(x)=-3 x+4\) and \(g(x)=-x^{2}+4 x+1 .\) Find the following $$ f(3 t-2) $$
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Chapter 2: Problem 26
Let \(f(x)=-3 x+4\) and \(g(x)=-x^{2}+4 x+1 .\) Find the following $$ f(3 t-2) $$
These are the key concepts you need to understand to accurately answer the question.
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Graph each line passing through the given point and having the given slope. (-4,2)\(; m=\frac{1}{2}\)
An equation that defines \(y\) as a function \(f\) of \(x\) is given. (a) Solve for \(y\) in terms of \(x\), and write each equation using function notation \(f(x) .\) (b) Find \(f(3)\). $$ x-4 y=8 $$
Graph the union of each pair of inequalities. $$ 3 x+2 y<6 \text { or } x-2 y>2 $$
For each function, find (a) \(f(2)\) and (b) \(f(-1)\) $$ f=\\{(-2,2),(-1,-1),(2,-1)\\} $$
Forensic scientists use the lengths of certain bones to calculate the height of a person. Two such bones are the tibia \((t),\) the bone from the ankle to the knee, and the femur \((r),\) the bone from the knee to the hip socket. A person's height \((h)\) in centimeters is determined from the lengths of these bones using the following functions. For men: \(\quad h(r)=69.09+2.24 r\) or \(\quad h(t)=81.69+2.39 t\) For women: \(\quad h(r)=61.41+2.32 r\) or \(h(t)=72.57+2.53 t\) (a) Find the height of a man with a femur measuring \(56 \mathrm{~cm}\). (b) Find the height of a man with a tibia measuring \(40 \mathrm{~cm} .\) (c) Find the height of a woman with a femur measuring \(50 \mathrm{~cm}\). (d) Find the height of a woman with a tibia measuring \(36 \mathrm{~cm}\).
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