Chapter 12: Problem 28
Graph each generalized square root function. $$ f(x)=-\sqrt{25-x^{2}} $$
Short Answer
Expert verified
Graph is an upside-down semi-circle with domain [-5, 5] and range [-5, 0].
Step by step solution
01
Identify the Function Type
The given function is of the form \( f(x) = -\sqrt{25 - x^2} \). This is a generalized square root function.
02
Identify the Domain
For the square root function, the expression inside the square root must be non-negative. Thus, set up the inequality: \(25 - x^2 \geq 0\). Solve for \(x\): \(-5 \leq x \leq 5\). Therefore, the domain is \([-5, 5]\).
03
Determine the Range
Since the square root function produces non-negative results and this is multiplied by \(-1\), the range is non-positive values. Thus, \(f(x) \leq 0\). Since \(\sqrt{25 - x^2}\) achieves its maximum value of 5 when \(x = 0\), the range is \([-5, 0]\).
04
Find Key Points
Plug in key values of \(x\) within the domain to find corresponding \(y\) values:\(x = 0\): \(f(0) = -\sqrt{25} = -5\)\(x = 5\) and \(x = -5\): \(f(5) = f(-5) = -\sqrt{0} = 0\)
05
Sketch the Graph
Plot the key points \((0, -5)\), \((5, 0)\), and \((-5, 0)\). Draw a smooth curve that outlines an upside-down semi-circle connecting these points, opening downward starting from \(x = -5\) to \(x = 5\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain
In mathematics, the domain of a function is the set of all possible input values (usually represented by 'x') for which the function is defined. For our function, which is a generalized square root function, it's essential to ensure the expression under the square root sign is non-negative because square roots of negative values are not real numbers.
Given the function:\[f(x) = -\sqrt{25 - x^2}\],
we need the expression inside the square root to be greater than or equal to zero.
Thus, solve the inequality:
\[25 - x^2 \geq 0\].
Rewriting, we get:
\[-5 \leq x \leq 5\]
This means that the domain of the function is all values of \(x\) from \(-5\) to \(5\).
Given the function:\[f(x) = -\sqrt{25 - x^2}\],
we need the expression inside the square root to be greater than or equal to zero.
Thus, solve the inequality:
\[25 - x^2 \geq 0\].
Rewriting, we get:
\[-5 \leq x \leq 5\]
This means that the domain of the function is all values of \(x\) from \(-5\) to \(5\).
- Always check the expression inside the square root.
- Set up the inequality and solve for \(x\).
- The domain tells us which values \(x\) can take.
Range
The range of a function is the set of all possible output values (usually represented by 'y') which a function can produce. For the function \(f(x) = -\sqrt{25 - x^2}\), let's determine the range step by step.
1. The square root function, \(\sqrt{25 - x^2}\), will always yield non-negative results (i.e., values greater than or equal to zero) because square roots of non-negative numbers are always non-negative.
2. Since our function is \(-\sqrt{25 - x^2}\), we are multiplying these non-negative results by \(-1\).
This results in non-positive values (i.e., values less than or equal to zero).
3. The maximum value of \(\sqrt{25 - x^2}\) is 5, which occurs when \(x = 0\). Thus the minimum value of our given function \(-\sqrt{25 - x^2}\) is \(-5\) at \(x = 0\).
4. The value of \(\sqrt{25 - x^2}\) decreases as \(x\) approaches \(-5\) or 5, reaching zero when \(x = \pm 5\).
At these points, our function \(-\sqrt{25 - x^2}\) equals 0.
Thus, the range of the function is all values from \(-5\) to 0. In interval notation, it's:
\[-5 \leq f(x) \leq 0\].
1. The square root function, \(\sqrt{25 - x^2}\), will always yield non-negative results (i.e., values greater than or equal to zero) because square roots of non-negative numbers are always non-negative.
2. Since our function is \(-\sqrt{25 - x^2}\), we are multiplying these non-negative results by \(-1\).
This results in non-positive values (i.e., values less than or equal to zero).
3. The maximum value of \(\sqrt{25 - x^2}\) is 5, which occurs when \(x = 0\). Thus the minimum value of our given function \(-\sqrt{25 - x^2}\) is \(-5\) at \(x = 0\).
4. The value of \(\sqrt{25 - x^2}\) decreases as \(x\) approaches \(-5\) or 5, reaching zero when \(x = \pm 5\).
At these points, our function \(-\sqrt{25 - x^2}\) equals 0.
Thus, the range of the function is all values from \(-5\) to 0. In interval notation, it's:
\[-5 \leq f(x) \leq 0\].
Graphing Functions
Graphing functions allows us to see the shape and behavior of a function. Let's graph the function \(f(x) = -\sqrt{25 - x^2}\) by following a few steps.
1. **Identify Key Points**:
Evaluate the function at strategic points within the domain - specifically, at the endpoints and midpoints.
2. **Plot the Points**:
Plot the points \((0, -5)\), \((5, 0)\), and \((-5, 0)\).
3. **Draw the Curve**:
Draw a smooth curve connecting these points. The shape resembles an upside-down semicircle opening downward, since it covers the range from \(-5\) to 0 and exists over the domain \([-5, 5]\).
1. **Identify Key Points**:
Evaluate the function at strategic points within the domain - specifically, at the endpoints and midpoints.
- At \(x = 0\): \(f(0) = -\sqrt{25} = -5\).
- At \(x = 5\): \(f(5) = -\sqrt{0} = 0\).
- At \(x = -5\): \(f(-5) = -\sqrt{0} = 0\).
2. **Plot the Points**:
Plot the points \((0, -5)\), \((5, 0)\), and \((-5, 0)\).
3. **Draw the Curve**:
Draw a smooth curve connecting these points. The shape resembles an upside-down semicircle opening downward, since it covers the range from \(-5\) to 0 and exists over the domain \([-5, 5]\).
- Always check key values in the domain.
- Plot these points on the graph accurately.
- Draw smooth curves to connect the points.