Chapter 11: Problem 49
Graph each polynomial function. Factor first if the expression is not in factored form. Use the rational zeros theorem as necessary. \(f(x)=x^{3}+x^{2}-8 x-12\)
Short Answer
Expert verified
The polynomial has zeros at \(x = -2\) (multiplicity 2) and \(x = 3\) (multiplicity 1).
Step by step solution
01
- Identify the polynomial
The given polynomial function is: \[f(x) = x^3 + x^2 - 8x - 12\]
02
- Apply the Rational Zeros Theorem
List all possible rational zeros using the Rational Zeros Theorem: the factors of the constant term (-12) divided by the factors of the leading coefficient (1). Possible rational zeros: ±1, ±2, ±3, ±4, ±6, ±12.
03
- Test the possible zeros
Evaluate the polynomial using possible rational zeros to find one that works.\[f(1) = 1^3 + 1^2 - 8(1) - 12 = 1 + 1 - 8 - 12 = -18\] (Not a zero)\[f(-1) = (-1)^3 + (-1)^2 - 8(-1) - 12 = -1 + 1 + 8 - 12 = -4\] (Not a zero)\[f(2) = 2^3 + 2^2 - 8(2) - 12 = 8 + 4 - 16 - 12 = -16\] (Not a zero)\[f(-2) = (-2)^3 + (-2)^2 - 8(-2) - 12 = -8 + 4 + 16 - 12 = 0\] (Zero found)
04
- Perform polynomial division
Divide the polynomial \(f(x)\) by \(x + 2\) since \(x = -2\) is a zero.\[\text{Using synthetic division, we get:}\]\[ x^3 + x^2 - 8x - 12 \div (x + 2) = x^2 - x - 6\]
05
- Factor the quotient
Factor the quadratic polynomial obtained from the division:\[x^2 - x - 6 = (x - 3)(x + 2)\]The complete factorized form is now:\[f(x) = (x + 2)(x - 3)(x + 2)\]We can simplify this to:\[f(x) = (x + 2)^2(x - 3)\]
06
- Find the zeros and their multiplicities
The function's zeros are at:\(x = -2\) (multiplicity 2) and \(x = 3\) (multiplicity 1)
07
- Graph the polynomial function
Plot the zeros on the x-axis and note the behavior of the polynomial at each zero:At \(x = -2\), the graph touches and rebounds because of its multiplicity 2.At \(x = 3\), the graph crosses the x-axis because of its multiplicity 1.Sketch the graph considering these behaviors and the end behavior of the polynomial (since the leading term, \(x^3\), dominates and makes the ends behave as \(-∞\) to the left and \(+∞\) to the right).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rational Zeros Theorem
The Rational Zeros Theorem is a tool to find possible rational zeros for a polynomial function. It states that any rational zero of a polynomial equation, formed by coefficient terms, is a fraction where the numerator is a factor of the constant term and the denominator is a factor of the leading coefficient.
To apply this theorem to the polynomial function \(f(x) = x^3 + x^2 - 8x - 12\),
let's list the factors:
By evaluating each possible rational zero, we can determine which actual zero(s) exist. For instance, substituting \(x = -2\) into the equation results in zero, confirming -2 as a rational zero.
To apply this theorem to the polynomial function \(f(x) = x^3 + x^2 - 8x - 12\),
let's list the factors:
- The constant term is -12, so factors are \pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm 12
- The leading coefficient is 1, so factors are \pm 1
By evaluating each possible rational zero, we can determine which actual zero(s) exist. For instance, substituting \(x = -2\) into the equation results in zero, confirming -2 as a rational zero.
Polynomial Division
Polynomial division, specifically synthetic division, helps you divide a polynomial by a binomial of the form (x - c).
For our given polynomial function \(f(x) = x^3 + x^2 - 8x - 12\),
After finding that \(x = -2\) is a root using the Rational Zeros Theorem, we can use synthetic division with \(x + 2\).
The synthetic division process resembles long division but is simpler:
\ x^3 + x^2 - 8x - 12 \div (x + 2) = x^2 - x - 6\ This quotient polynomial can then be further factored.
For our given polynomial function \(f(x) = x^3 + x^2 - 8x - 12\),
After finding that \(x = -2\) is a root using the Rational Zeros Theorem, we can use synthetic division with \(x + 2\).
The synthetic division process resembles long division but is simpler:
- Write down the coefficients: 1, 1, -8, -12
- Bring down the leading coefficient (1)
- Multiply this by -2 and add the result to the next coefficient, repeating the process across all coefficients
\ x^3 + x^2 - 8x - 12 \div (x + 2) = x^2 - x - 6\ This quotient polynomial can then be further factored.
Factoring Polynomials
Factoring polynomials entails breaking down a complex polynomial into a product of simpler polynomials. For our quotient polynomial \[x^2 - x - 6\]:
\[f(x) = (x + 2)(x - 3)(x + 2) = (x + 2)^2 (x - 3)\]
This factorized form represents the polynomial function in its simplest form.
- Identify two numbers that multiply to -6 (constant term) and add to -1 (coefficient of the x term)
- In this case, we find -3 and 2
\[f(x) = (x + 2)(x - 3)(x + 2) = (x + 2)^2 (x - 3)\]
This factorized form represents the polynomial function in its simplest form.
Graphing Polynomial Functions
Graphing polynomial functions requires understanding the function's zeros and how it behaves around them. For \[f(x) = (x + 2)^2(x - 3)\]:
- Zeros are at \ x = -2 (with multiplicity 2) and x = 3 (with multiplicity 1)
- At \ x = -2 \, the graph touches and rebounds off the x-axis due to multiplicity 2
- At \ x = 3 \, it crosses the x-axis due to multiplicity 1
- As x approaches \ -\infty \, the graph heads towards \ -\infty \
- As x approaches \ \infty \, the graph heads towards \ \infty