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Determine whether common logarithms or natural logarithms would be a better choice to use for solving each equation. Do not actually solve. $$ 10^{3 x+1}=13 $$

Short Answer

Expert verified
Common logarithms (base 10) are the better choice because the base of the given exponential is 10.

Step by step solution

01

Identify the Base of the Exponential Equation

Observe that the equation is given in the form of an exponential expression. The base of this exponential equation is 10, as in the expression 10^{3x+1} = 13.
02

Choose the Common Logarithm

Since the base of the exponential expression is 10, the common logarithm (logarithm with base 10) is the more natural choice. This is because logarithms with the same base as the exponential expression simplify the process of solving.
03

Reason for Choosing Common Logarithms

Using the common logarithm log_{10}(x) simplifies computations when dealing with base 10 exponentials. Applying the common logarithm to both sides of the equation, you can simplify and solve the equation for x effectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Logarithms
The common logarithm is a type of logarithm that uses base 10. It is often written as \(\text{log}_{10}(x)\). This form is very convenient for solving problems where the exponential equation has a base of 10. For example, if you encounter an equation like \(10^{3x + 1} = 13\), you would use the common logarithm because the base of the exponential part of the equation is already 10.

Common logarithms are many times used in practical applications such as measuring the intensity of sound (decibels) or the Richter scale for earthquake magnitudes.

To apply the common logarithm, you would take the logarithm of both sides of the equation. This simplifies the exponent and makes it easier to solve for the unknown variable. For instance, applying the common logarithm to our equation would give:
\[ \text{log}_{10}(10^{3x + 1}) = \text{log}_{10}(13) \] \[ 3x + 1 = \text{log}_{10}(13) \] As a result, the equation is more manageable and allows you to solve for 'x'.
Natural Logarithms
Natural logarithms use the base 'e', where 'e' is an irrational and transcendental number approximately equal to 2.718. They are written as \( \text{ln}(x) \). Natural logarithms are particularly useful in continuous growth and decay problems, frequently found in calculus and higher-level mathematics.

One crucial application of natural logarithms is in compound interest calculations and natural growth processes like population growth or radioactive decay. When an exponential equation has the base 'e', the natural logarithm is the go-to logarithm to use.

For example, if you have an equation such as \( e^{2x} = 10 \), you would apply the natural logarithm to both sides to solve for 'x'. Here is how it looks:
\[ \text{ln}(e^{2x}) = \text{ln}(10) \] \[ 2x = \text{ln}(10) \] \[ x = \frac{\text{ln}(10)}{2} \] As you can see, this makes solving for 'x' straightforward.
Exponential Equations
Exponential equations are equations in which variables appear as exponents. These types of equations are common in many fields, including science, finance, and engineering. They follow the general form \( a^{f(x)} = b \), where 'a' is the base, 'f(x)' is an exponential function, and 'b' is a constant.

To solve exponential equations, logarithms are key. Depending on the base of the exponential function, you will either use the common logarithm or the natural logarithm. Generally, steps involved are:
  • Identify the base of the exponential term
  • Apply the corresponding logarithm to both sides of the equation
  • Simplify the resulting equation to solve for the variable

Consider the equation \( 2^{3x+4} = 16 \). Here, you would use the common logarithm since the base is 2:
\[ \text{log}_{2}(2^{3x+4}) = \text{log}_{2}(16) \] \[ 3x + 4 = \text{log}_{2}(16) \] This simplifies solving for the unknown variable 'x'.
Base 10 Logarithms
Base 10 logarithms are another name for common logarithms. These are specifically useful when dealing with exponential equations with base 10, such as \( 10^{x} \).

Practical uses of base 10 logarithms include scientific measurements and engineering applications, where they help in managing and understanding values spanning large ranges. They simplify calculations because computers and calculators are optimized for base 10 operations.

As an example, let’s revisit the given equation \[ 10^{3x + 1} = 13 \]. By applying the common logarithm to both sides of the equation, we get:
\[ \text{log}_{10}(10^{3x + 1}) = \text{log}_{10}(13) \] This reduces to:
\[ 3x + 1 = \text{log}_{10}(13) \] Therefore, solving for 'x' becomes straightforward. Base 10 logarithms are thus very handy in both educational and professional contexts.

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Most popular questions from this chapter

Why is 1 not allowed as a base for a logarithmic function?

Inverse functions can be used to send and receive coded information. A simple example might use the function \(f(x)=2 x+5 .\) (Note that it is one-to-one.) Suppose that each letter of the alphabet is assigned a numerical value according to its position, as follows. $$\begin{array}{llllllllll}\mathbf{A} & 1 & \mathbf{G} & 7 & \mathbf{L} & 12 & \mathbf{Q} & 17 & \mathbf{V} & 22 \\\\\mathbf{B} & 2 & \mathbf{H} & 8 & \mathbf{M} & 13 & \mathbf{R} & 18 & \mathbf{W} & 23 \\\\\mathbf{C} & 3 & \mathbf{I} & 9 & \mathbf{N} & 14 & \mathbf{S} & 19 & \mathbf{X} & 24 \\\\\mathbf{D} & 4 & \mathbf{J} & 10 & \mathbf{O} & 15 & \mathbf{T} & 20 & \mathbf{Y} & 25 \\\\\mathbf{E} & 5 & \mathbf{K} & 11 & \mathbf{P} & 16 & \mathbf{U} & 21 & \mathbf{Z} & 26 \\\\\mathbf{F} & 6 & & & & & & & &\end{array}$$ Using the function, the word ALGEBRA would be encoded as $$\begin{array}{lllllll}7 & 29 & 19 & 15 & 9 & 41 & 7\end{array}$$ because \(f(\mathrm{~A})=f(1)=2(1)+5=7, \quad f(\mathrm{~L})=f(12)=2(12)+5=29, \quad\) and so on The message would then be decoded using the inverse of \(f,\) which is \(f^{-1}(x)=\frac{x-5}{2}\). $$f^{-1}(7)=\frac{7-5}{2}=1=\mathrm{A}, \quad f^{-1}(29)=\frac{29-5}{2}=12=\mathrm{L}, \quad \text { and so on }$$ Use \(f(x)=x^{3}+4\) to encode your name, using the above letter/number assignment

Solve each equation. Use natural logarithms. Approximate solutions to three decimal places when appropriate. $$ e^{-0.103 x}=7 $$

Solve each equation. $$\log _{12} x=0$$

A major scientific periodical published an article in 1990 dealing with the problem of global warming. The article was accompanied by a graph that illustrated two possible scenarios. (a) The warming might be modeled by an exponential function of the form \(f(x)=\left(1.046 \times 10^{-38}\right)\left(1.0444^{x}\right)\). (b) The warming might be modeled by a linear function of the form \(g(x)=0.009 x-17.67\). In both cases, \(x\) represents the year, and the function value represents the increase in degrees Celsius due to the warming. Use these functions to approximate the increase in temperature for each year, to the nearest tenth of a degree. $$ 2000 $$

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