/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 Solve each inequality. Graph the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each inequality. Graph the solution set, and write it using interval notation. \(-1 \leq \frac{2 x-5}{6} \leq 5\)

Short Answer

Expert verified
The solution set is \[ -\frac{1}{2}, 17.5 \].

Step by step solution

01

Understand the Given Inequality

The given compound inequality is \[\begin{equation} -1 \leq \frac{2x-5}{6} \leq 5 \end{equation}\]
02

Break Down the Inequality into Two Parts

Break the compound inequality into two separate inequalities: \[\begin{equation} -1 \leq \frac{2x-5}{6} \end{equation}\] \ and \[\begin{equation} \frac{2x-5}{6} \leq 5 \end{equation}\]
03

Solve the First Inequality

Start with \[\begin{equation} -1 \leq \frac{2x-5}{6} \end{equation}\]. Multiply both sides by 6: \[\begin{equation} -6 \leq 2x-5 \end{equation}\]Add 5 to both sides: \[\begin{equation} -1 \leq 2x \end{equation}\]. Now, divide both sides by 2: \[\begin{equation} -\frac{1}{2} \leq x \end{equation}\]
04

Solve the Second Inequality

Now solve \[\begin{equation} \frac{2x-5}{6} \leq 5 \end{equation}\]. Multiply both sides by 6: \[\begin{equation} 2x-5 \leq 30 \end{equation}\]Add 5 to both sides: \[\begin{equation} 2x \leq 35 \end{equation}\]. Divide both sides by 2: \[\begin{equation} x \leq 17.5 \end{equation}\]
05

Combine the Solutions

Combine the results of both inequalities: \[\begin{equation} -\frac{1}{2} \leq x \leq 17.5 \end{equation}\]
06

Graph the Solution Set

Graph the solution set on a number line: Draw a closed circle at \[\begin{equation} x = -\frac{1}{2} \end{equation}\] and another closed circle at \[\begin{equation} x = 17.5 \end{equation}\], with a shaded line connecting the two points indicating all the values between them including the endpoints.
07

Write the Interval Notation

The interval notation for the solution set is: \[\begin{equation} \left[ -\frac{1}{2}, 17.5 \right] \end{equation}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Compound Inequalities
Compound inequalities involve two separate inequalities that are combined into one statement. They are often joined by the words 'and' or 'or.' An 'and' compound inequality indicates that both conditions must be true simultaneously. For example, in the inequality \(-1 \leq \frac{2x-5}{6} \leq 5\), both inequalities must be satisfied at the same time.
To solve a compound inequality, you split it into two individual inequalities, solve each one separately, and then combine the results. This ensures that all parts of the compound statement hold true.

In the given exercise, we break the compound inequality into two simpler inequalities and solve them one by one. After that, we combine the results to get the final solution set. This step-by-step approach leads to an accurate and clear solution.
Using Interval Notation
Interval notation is a shorthand way of writing inequalities that describe a range of values. It uses brackets and parentheses to show which part of the inequality is included or excluded.

For example:
  • \([a, b]\): Includes both endpoints 'a' and 'b'.
  • \((a, b)\): Excludes both endpoints.
  • \([a, b)\) or \((a, b]\): Includes one endpoint but excludes the other.
In the context of our exercise, after solving the inequalities, the solution set is written as \([-\frac{1}{2}, 17.5]\), which means 'x' includes both -0.5 and 17.5, as well as every number in between. This concise representation makes it easier to understand and communicate the solution set of an inequality.
Graphing Inequalities
Graphing inequalities on a number line helps visualize the solution set. It shows all the possible values that satisfy the inequality.To graph our solution set, \([-\frac{1}{2}, 17.5]\), follow these steps:
  • Identify the endpoints: -0.5 and 17.5.
  • Place a closed circle (since the endpoints are included) at -0.5 and 17.5.
  • Draw a line connecting these points, shading between the circles to indicate all the values in this range are part of the solution.
Graphing makes it clear which values are part of the solution set and enhances understanding of the inequality by providing a visual representation.

When combined with interval notation, graphing provides a complete picture of the solution, making it easier to comprehend and verify the result of the inequality.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Scott scored 92 and 96 on his first two tests in "Methods in Teaching Mathematics." What score must he make on his third test to keep an average of 90 or greater?

The 10 tallest buildings in Houston, Texas, are listed along with their heights. $$ \begin{array}{|l|c|} \hline \quad {\text { Building }} & \text { Height (in feet) } \\ \hline \text { JPMorgan Chase Tower } & 1002 \\ \text { Wells Fargo Plaza } & 992 \\ \text { Williams Tower } & 901 \\ \text { Bank of America Center } & 780 \\ \text { Texaco Heritage Plaza } & 762 \\ \text { 609 Main at Texas } & 757 \\ \text { Enterprise Plaza } & 756 \\ \text { Centerpoint Energy Plaza } & 741 \\ \text { 1600 Smith St. } & 732 \\ \text { Fulbright Tower } & 725 \\ \hline \end{array} $$ Use this information. Work each of the following. (a) Write an absolute value inequality that describes the height of a building that is not within \(95 \mathrm{ft}\) of the average. (b) Solve the inequality from part (a). (c) Use the result of part (b) to list the buildings that are not within \(95 \mathrm{ft}\) of the average. (d) Confirm that the answer to part (c) makes sense by comparing it with the answer to Exercise 131 .

Solve each equation or inequality. $$ |5 x-2|=0 $$

Solve each investment problem. Mona received a year-end bonus of \(\$ 17,000\) from her company and invested the money in an account paying \(6.5 \%\). How much additional money should she deposit in an account paying \(5 \%\) so that the return on the two investments will be \(6 \% ?\)

Find the open interval in which \(x\) must lie in order for the given condition to hold. \(y=5 x+12,\) and the difference of \(y\) and 4 is less than 0.0001.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.