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\text { The 8th term of } \frac{1}{2}, \frac{1}{6}, \frac{1}{18}, \frac{1}{54}, \ldots, \frac{1}{4374}

Short Answer

Expert verified
The 8th term is \( \frac{1}{4374} \).

Step by step solution

01

Identify the Sequence

First, observe that the sequence provided is a shrinking sequence of fractions: \( \frac{1}{2}, \frac{1}{6}, \frac{1}{18}, \frac{1}{54}, \ldots \). These fractions suggest a geometric sequence where each term after the first is multiplied by a common ratio.
02

Determine the Common Ratio

To find the common ratio, divide the second term by the first term: \( \frac{1/6}{1/2} = \frac{1}{6} \times \frac{2}{1} = \frac{2}{6} = \frac{1}{3} \). Similarly, dividing the third term by the second, \( \frac{1/18}{1/6} = \frac{6}{18} = \frac{1}{3} \). Thus, the common ratio \( r \) is \( \frac{1}{3} \).
03

Set Up the General Term Formula

For a geometric sequence, the general term \( a_n \) can be defined by the formula \( a_n = a_1 \cdot r^{(n-1)} \), where \( a_1 \) is the first term and \( r \) is the common ratio.
04

Calculate the 8th Term

Substitute the values of the first term \( a_1 = \frac{1}{2} \), the common ratio \( r = \frac{1}{3} \), and \( n = 8 \) into the general formula to find the 8th term: \[ a_8 = \frac{1}{2} \cdot \left(\frac{1}{3}\right)^{7} \]Calculate the power: \[ \left(\frac{1}{3}\right)^{7} = \frac{1}{2187} \]Now, find the 8th term by substitution:\[ a_8 = \frac{1}{2} \cdot \frac{1}{2187} = \frac{1}{4374} \]
05

Verify the Result

As the result \( \frac{1}{4374} \) is consistent with the sequence pattern and the geometric sequence calculations, we can conclude the answer is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Common Ratio
In a geometric sequence, the common ratio is a key component. It is the factor by which each term in the sequence is multiplied to obtain the next term. For example, in the sequence \( \frac{1}{2}, \frac{1}{6}, \frac{1}{18}, \frac{1}{54}, \ldots \), we can determine the common ratio by dividing any term by its preceding term. This helps maintain the uniformity of the sequence.
  • Take the second term \( \frac{1}{6} \) and divide it by the first term \( \frac{1}{2} \).
  • Perform the division: \( \frac{1/6}{1/2} = \frac{1}{6} \times \frac{2}{1} = \frac{1}{3} \).
Once the common ratio \( r \) is known, which in our case is \( \frac{1}{3} \), we can easily calculate subsequent terms by applying this ratio.
General Term Formula in Geometric Sequences
To find any term in a geometric sequence, we can use the general term formula. This formula is a powerful tool for calculating not just the next term, but any term within the sequence quickly and efficiently. The formula is given by: \[ a_n = a_1 \cdot r^{(n-1)} \]where:
  • \( a_n \) is the term you wish to find.
  • \( a_1 \) is the first term of the sequence.
  • \( r \) is the common ratio.
  • \( n \) is the term number.
Using this formula ensures you can directly jump to the term number you are interested in without having to calculate all prior terms.
Calculating Specific Terms in a Geometric Sequence
Suppose we want to find the 8th term of our sequence \( \frac{1}{2}, \frac{1}{6}, \frac{1}{18}, \frac{1}{54}, \ldots \). By using the general term formula \( a_n = a_1 \cdot r^{(n-1)} \), we can easily calculate specific terms. Let's go through the steps for the 8th term:1. Identify the known values:
  • First term \( a_1 = \frac{1}{2} \)
  • Common ratio \( r = \frac{1}{3} \)
  • Desired term number \( n = 8 \)
2. Replace these values into the formula: \[ a_8 = \frac{1}{2} \cdot \left(\frac{1}{3}\right)^{7} \]3. Calculate the power: \[ \left(\frac{1}{3}\right)^{7} = \frac{1}{2187} \]4. Substitute back: \[ a_8 = \frac{1}{2} \cdot \frac{1}{2187} = \frac{1}{4374} \]Therefore, the 8th term of the sequence is \( \frac{1}{4374} \), demonstrating how geometric sequence calculations work seamlessly with the formula.

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