Chapter 14: Problem 1
Find the 15th term of the sequence for which \(a_{n}=-n^{2}-1 . \quad-226\)
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Chapter 14: Problem 1
Find the 15th term of the sequence for which \(a_{n}=-n^{2}-1 . \quad-226\)
These are the key concepts you need to understand to accurately answer the question.
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$$ S_{n}=\frac{n(n+1)(2 n+1)}{6} \text { for } a_{n}=n^{2} $$
Change \(0 . \overline{36}\) to reduced \(a / b\) form, where \(a\) and \(b\) are integers and \(b \neq 0\). $$ \frac{4}{11} $$
$$ \sum_{i=1}^{5} i^{3} \quad 225 $$
Suppose that you save a dime the first day of a month, \(\$ 0.20\) the second day, and \(\$ 0.40\) the third day and that you continue to double your savings each day for 14 days. Find the total amount that you will save at the end of 14 days. \(\quad \$ 1638.30\)
n^{2}+n \text { is divisible by } 2
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